Mathematics
user avatar
user avatar
user avatar
mathlove
  • Member for 9 years
  • Last seen this week
Profile Activity
Stats
122,101
reputation
2.9m
reached
2,645
answers
180
questions
Communities
Badges
View all badges
9
gold badges
107
silver badges
263
bronze badges
Top tags
View all tags
1,585
Score
480
Posts
17
Posts %
884
Score
284
Posts
10
Posts %
814
Score
327
Posts
12
Posts %
563
Score
312
Posts
11
Posts %
532
Score
229
Posts
8
Posts %
467
Score
267
Posts
9
Posts %
Top posts
View all questions and answers
All Questions Answers
Score Newest
answer
137
How do people perform mental arithmetic for complicated expressions?
Aug 10, 2015
question
85
Numbers $n$ such that the digit sum of $n^2$ is a square
Jan 6, 2015
answer
81
How to prove that the Fibonacci sequence is periodic mod 5 without using induction?
Jul 12, 2015
question
73
Representing every positive rational number in the form of $(a^n+b^n)/(c^n+d^n)$
Mar 11, 2015
question
64
Arranging numbers from $1$ to $n$ such that the sum of every two adjacent numbers is a perfect power
Feb 28, 2015
question
57
Finding triplets $(a,b,c)$ such that $\sqrt{abc}\in\mathbb N$ divides $(a-1)(b-1)(c-1)$
Apr 25, 2015
answer
54
Trick with 3-digit numbers, always get 1089
Sep 18, 2014
question
50
Finite Sum $\sum\limits_{k=1}^{m-1}\frac{1}{\sin^2\frac{k\pi}{m}}$
Oct 29, 2013
question
47
Why does this ratio of sums of square roots equal $1+\sqrt2+\sqrt{4+2\sqrt2}=\cot\frac\pi{16}$ for any natural number $n$?
Aug 10, 2013
question
47
$\lfloor \sqrt n+\sqrt {n+1}+\sqrt{n+2}+\sqrt{n+3}+\sqrt{n+4}\rfloor=\lfloor\sqrt {25n+49}\rfloor$ is true?
Aug 27, 2013
Top network posts
View all network posts
38
Arranging numbers from $1$ to $n$ such that the sum of every two adjacent numbers is a perfect power
34
About the ratio of the areas of a convex pentagon and the inner pentagon made by the five diagonals
33
Can we simplify $\int_{0}^{\infty}\frac{{\sin}^px}{x^q}dx$?
23
Does this sequence always give an integer?
22
Can we simplify $\int_{0}^{\infty}\frac{{\sin}^px}{x^q}dx$?

Your privacy

By clicking “Accept all cookies”, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy.