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dustin
  • Member for 9 years, 3 months
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17 votes

Different methods to compute $\sum\limits_{k=1}^\infty \frac{1}{k^2}$ (Basel problem)

16 votes
Accepted

how to find the branch points and cut

14 votes
Accepted

Collections of undergraduate research projects

13 votes

Laurent-series expansion of $1/(e^z-1)$

11 votes
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Winding number (demonstration)

10 votes
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Evaluate $\int_0^\infty \frac{(\log x)^2}{1+x^2} dx$ using complex analysis

9 votes

Prerequisite for Takhtajan's "Quantum Mechanics for Mathematicians"

9 votes
Accepted

Restricted Three-Body Problem

7 votes

Video Lessons in Complex Analysis

7 votes

cauchy theorem over cycles homologous to zero

6 votes
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Definite integral over $(0,1)$ rather than $[0,1]$

6 votes
Accepted

Proof for de Moivre's Formula

6 votes

How did Euler realize $x^4-4x^3+2x^2+4x+4=(x^2-(2+\alpha)x+1+\sqrt{7}+\alpha)(x^2-(2-\alpha)x+1+\sqrt{7}-\alpha)$?

6 votes

Pole on a contour. Problem with integration

6 votes

Can a complex number ever be considered 'bigger' or 'smaller' than a real number, or vice versa?

5 votes
Accepted

Evaluating $I_{\alpha}=\int_{0}^{\infty} \frac{\ln(1+x^2)}{x^\alpha}dx$ using complex analysis

5 votes

What is the importance of $\sinh(x)$?

5 votes
Accepted

Evaluate $\int_0^{\infty} \frac{\log x }{(x-1)\sqrt{x}}dx$ (solution verification)

5 votes

Simple complex line integral over a rectangle

5 votes

Complex Analysis Book

5 votes

Intuition for the Poisson kernel

5 votes

The $n$ complex $n$th roots of a complex number $z$

5 votes
Accepted

Reference Request - Introductory book on Mathematical Modelling in Economics and Business

5 votes
Accepted

Residue Theorem and Homologous to zero

4 votes
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Homogeneous wave equation on half line with nonhomogeneous boundary condition.

4 votes

Modulus of a complex number

4 votes

Series which are not Fourier Series

4 votes
Accepted

Residue theorem:When a singularity on the circle (not inside the circle)

4 votes
Accepted

Using complex analysis to evaluate $\int_0^\infty\frac{(\ln x)^3}{1+x^2}d x$

4 votes

I need Arctan but only Arctan2 is supplied

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