Mihai.Mehe
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$f(\frac{x}{||x||})=\frac{f(x)}{||x||}$ for a linear functional $f$ on a normed linear space $R$
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Given a functional $f:R\longrightarrow\Re$ were $R$ is a linear space: $f(\alpha x+\beta y)=\alpha f(x)+\beta f(y)$, $\forall x,y\in R $ and $\forall \alpha,\beta\in \Re$ reals. Let $\beta=0$, and $\...

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Numerical analysis condition number
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I summarized the solution given in the comments above by Ian. First we note that by definition, $\kappa_{p}(a)=|\frac{ap'(a)}{p(a)}|$. Where by hypothesis, $p(a)$ is a solution to $x^n-ae^{-x}=0$, and ...

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