143 views

The answer to this was to recognize that all elements were rotations or order 2 flips. So count rotations as you would in $\mathbb{Z}_{2n}$, then add $n$ more order 2 elements (the reflections).

203 views

I know this is a stale post, but just in case anyone is looking (like I was) I'll add the answer here because it took me a while to understand how to compute these expectations. \begin{align}\Bbb E(... View answer 1 answers 0 votes 28 views Accepted answer 0 votes Following the commentor, I searched Monkey Saddles. I found more complicated saddles: I guess these types of surfaces are called n-th order saddles. Formulas for them can be found here: https://rivix.... View answer 1 answers 0 votes 71 views 0 votes This is a very large set. In what follows, I'm basically going to quote a discussion that can be found in the Notes and References Section of Folland's real analysis book (Section 1.6) Start with ... View answer 2 answers 1 votes 97 views 0 votes Let v=\sum v_i e_i (basically a basis expansion of v). Then: Lv = L(\sum v_i e_i). Use the IP against some e_j:\left\langle L(\sum v_i e_i), e_j\right\rangle \\ = \left\langle \sum v_i e_i, L^...

168 views

I believe the awkward wording is suggesting a direct partition: P(\text{Male},\text{Science})+P(\text{Female},\text{Science})+(\text{Male},\text{Not Science})+P(\text{Female},\text{Not Science}) = 1\$...

2k views