Mathematics
user avatar
user avatar
user avatar
poetasis
  • Member for 4 years, 1 month
  • Last seen this week
  • Nebraska
Profile Activity
Stats
5,024
reputation
75k
reached
624
answers
48
questions
Communities
About

Retired fork lift mechanic, math hobbyist.

My avatar is an Isosceles triangle (2600,2600,1456) I made of six primitive Pythagorean triples I found using a formula I developed that generates no trivial triples, generates all "sets" of primitives, and only 1/3 of the imprimitives of Euclid's formula.

email: poetasis@gmail.com

Badges
View all badges
2
gold badges
9
silver badges
28
bronze badges
Top tags
View all tags
95
Score
218
Posts
32
Posts %
65
Score
170
Posts
25
Posts %
52
Score
143
Posts
21
Posts %
48
Score
98
Posts
15
Posts %
31
Score
55
Posts
8
Posts %
27
Score
48
Posts
7
Posts %
Top posts
View all questions and answers
All Questions Answers
Score Newest
question
10
Where is my error in trying to find Pythagorean triples with matching areas?
Jul 8, 2019
question
7
How do I solve the quintic $n^5-m^4n+\frac{P}{2m}=0$ for $n$?
Jan 9, 2020
answer
6
How do you find Pythagorean triples that approximately correspond to a right triangle with a given angle?
Oct 1, 2021
question
5
Proper notation for corresponding members in sets
Jan 24, 2021
question
5
Seeking series formula for: $3, 2, 4, 7, 11, 16, 26, 39, 63, 94, 152, 227, 367, 548, 886, 1323, 2139, 3194$
Nov 8, 2019
answer
5
Generating Pythagorean Triples Using a New Method?
Feb 12, 2021
question
4
Is this a new formula for Pell numbers?
May 30, 2020
question
4
How does symmetry help solve an equation?
Dec 31, 2019
answer
4
What is the remainder when $1^n + 2^n + 3^n + \ldots + 99^n$ is divided by $1 + 2 + 3 + \ldots + 99$?
Nov 10, 2020
answer
4
Solving Dudeney's "A Question of Cubes": sum of consecutive cubes is a square
Dec 19, 2020

Your privacy

By clicking “Accept all cookies”, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy.