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Ben Martin's user avatar
Ben Martin's user avatar
Ben Martin
  • Member for 7 years, 1 month
  • Last seen this week
4 votes
2 answers
111 views

Existence of global minimum of $f(x) = \sum_{i=1}^n e^{x_i}$

3 votes
1 answer
106 views

Can $\sin\left(\frac{x+y}{\sqrt{2}}\right)=\frac{y-x}{\sqrt{2}}$be written as a function of $x$

3 votes
1 answer
175 views

prove $f$ is bounded given $f(t^2+u)=tf(t)+f(u)$

3 votes
1 answer
1k views

Help understanding a proof that $[G:H][H:K]=[G:K]$

2 votes
2 answers
837 views

What is $S_n/S_{n-1}$?

2 votes
1 answer
67 views

Show $\limsup_{x\to \infty} \sin\left((x+t)^2\right)-\sin\left(x^2\right)=2$ for $ t \ne 0$

2 votes
2 answers
2k views

Is $f:\emptyset \to X$ injective

2 votes
1 answer
418 views

prove $lcm(a,gcd(b,c))=gcd(lcm(a,b),lcm(a,c))$ [duplicate]

2 votes
1 answer
72 views

Asymptotics of expected number of draws until repeat

1 vote
1 answer
87 views

How to prove this by induction

1 vote
1 answer
218 views

Geometric intuition behind determinant properties

1 vote
2 answers
63 views

Show open rectangles with vertices $\langle a\pm\frac{1-r}{8},b\pm\frac{1-r}{8}\rangle $ are contained in the unit disk

1 vote
0 answers
39 views

Behaviour of $\mathrm{argmin}_{\theta} \mathbb{E}_X \left[|X-\theta|^q\right]$ as $q \to 0^+$

1 vote
1 answer
246 views

Help understanding an injectivity proving technique in functional equations

1 vote
0 answers
33 views

Must a square root of a diagonal matrix with distinct eigenvalues be diagonal? [duplicate]

1 vote
1 answer
52 views

Is there a way to produce an definite integral based off a specific symmetry.

0 votes
0 answers
77 views

Can the harmonic series be assigned a shift invariant value?

0 votes
1 answer
87 views

Help proving that this structure is a group

0 votes
1 answer
33 views

Is my proof that the set of all functions from $X' \subseteq X$ to $Y'\subseteq Y$ exist valid

0 votes
2 answers
814 views

Show $T(x+iy)=2x-y+i(x-3y)$ is not a linear transformation

0 votes
1 answer
96 views

how to prove $(b^m)^\frac{1}{n}=(b^p)^\frac{1}{q}$if $\frac{m}{n}=\frac{p}{q}$