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k.stm's user avatar
k.stm's user avatar
k.stm's user avatar
k.stm
  • Member for 10 years, 8 months
  • Last seen more than a week ago
141 votes
Accepted

Proof of triangle inequality

44 votes
Accepted

Meaning of the backslash operator on sets

26 votes

How to prove the continuity of the metric function?

22 votes
Accepted

If Gal(K,Q) is abelian then |Gal(K,Q)|=n

20 votes
Accepted

Example of a non-splitting exact sequence $0 → M → M\oplus N → N → 0$

17 votes

Is every element in a set also an element of the powerset?

15 votes
Accepted

What is the rule for something divided by itself equaling 1?

15 votes
Accepted

$K$ is a splitting field $\iff$ any irreducible polynomial with a root in $K$ splits completely over $K$.

13 votes

Method of finding a p-adic expansion to a rational number

11 votes
Accepted

Prove that G\S generates G

11 votes
Accepted

From any ten naturals, find some numbers whose sum is divisible by $ 10.$

11 votes

Is product of two closed sets closed?

11 votes

How to show $\mathbf{Q} $ is not free

11 votes

Why is “or” (in logic) sometimes equivalent to “and” (in natural language)?

9 votes
Accepted

$f^2$ and $f^3$ are holomorphic implies $f$ is holomorphic.

9 votes

Solve $\dfrac{1}{1+\frac{1}{1+\ddots}}$

9 votes

Show that $f$ cannot have infinitely many zeroes in $[0, 1]$.

9 votes
Accepted

Category of sets, $\mathrm{I}_{\emptyset}$

9 votes

Is an automorphism a function or a group?

9 votes

Understanding $\mathbb{C} \otimes_{\mathbb{Q}} \mathbb{C}$

8 votes
Accepted

Relation between the notions connected and disconnect, confused

8 votes

Representing $\mathbb{R}/\mathbb{Z}$ as a matrix group.

8 votes

Creating surjective holomorphic map from unit disc to $\mathbb{C}$?

8 votes

Ring whose all ideals are double-sided is commutative?

8 votes

Is any subring of a Euclidean domain a unique factorization domain?

8 votes
Accepted

an example of an interesting connected topological space

8 votes

If two continuous maps into a Hausdorff space agree on a dense subset, they are identically equal

8 votes
Accepted

Let $G$ be a group and $A\subseteq G$. Showing $\{g\in G: gag^{-1}\in A \text{ for all } a\in A\}$ does not have to be a subgroup of $G$.

8 votes
Accepted

Every group is solvable, fake proof.

8 votes
Accepted

How come the $\epsilon-\delta$ definition of continuity is preferred over the sequential definition of continuity?

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