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tchappy ha's user avatar
tchappy ha's user avatar
tchappy ha
  • Member for 7 years, 5 months
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7 votes

Exercise 6.A.17 in "Linear Algebra Done Right 3rd Edition" by Sheldon Axler. I am worried if my solution is ok.

6 votes

Group of even order contains an element of order 2

5 votes
Accepted

Difference between Calculus $4$th edition and Calculus $3$rd edition by Michael Spivak?

4 votes

Let $f : Q\to \mathbb{R}$ be bounded. Then $f$ is integrable over $Q$ if and only if given $\epsilon> 0$, there is a $\delta> 0$ such that

4 votes

Prove that $\dim range T = 1$ if and only if there is a basis of $V$ and a basis of $W$ all entries of $M(T)$ equal $1$

3 votes

Is there a very small gap or no gap in this proof? ("Linear Algebra Done Right 3rd Edition" by Sheldon Axler.)

3 votes

8 Positive integers making numbers in the range $-1985\leq k\leq 1985$.

3 votes

8th non-isomorphic matroid on set of 3 elements

3 votes

I wonder why Michael Spivak assumed $f$ is integrable on $[a,b]$ "Calculus 4th Edition" by Michael Spivak "Measure, Integration & Real Analysis" Axler

2 votes

Cyclic Group Generators of Order $n$

2 votes

Theorem 3.55 in Baby Rudin: How to make sense of the proof?

2 votes

Is There A Polynomial That Has Infinitely Many Roots?

2 votes

Is it true that the order of $ab$ is always equal to the order of $ba$?

2 votes

Let $f : Q\to \mathbb{R}$ be bounded. Then the statement that $f$ is integrable over $Q$, with $\int_{Q}f = A$, is equivalent to the statement

2 votes
Accepted

Riemann Integration, question from Munkres

2 votes

To prove in a Group Left identity and left inverse implies right identity and right inverse

2 votes

Baby Rudin Theorem 3.7 Clarification

2 votes

If intersection of all the non-singleton subgroups of a group is not single ton , then is every element of the group is of finite order ?

2 votes

Show that $f$ is continuous if and only if for each $x \in X$ there is a neighborhood $U$ of $x$ such that $f|U$ is continuous.

2 votes

Prob. 16, Sec. 2.3, in Herstein's TOPICS IN ALGEBRA, 2nd ed: A finite set closed under an associative product with only one of the cancellation laws

2 votes

About 3.F Exercise 21 on p.114 in "Linear Algebra Done Right" by Sheldon Axler.

2 votes

$\mathcal{S}$, smallest $\sigma$-algebra on $\mathbb{R}$ containing $\{(r,s]:r,s\in\mathbb{Q}\}$, is the collection of Borel subsets of $\mathbb{R}$

2 votes

Variation of exercise $1.1.1$ from Tao’s measure theory book

2 votes

Gauss's Lemma Proof

2 votes

Prove that $ |A| = \lim_{t\rightarrow \infty}| A \cap (-t,t)|$ for all $A \subset \mathbb{R}$

1 vote

Linear Algebra problem (linear algebra done right)

1 vote

Measure, Integration & Real Analysis Sheldon Axler SEction 2B Exercise 12

1 vote

$A\subset\mathbb{R}, t>0\Rightarrow |A|=|A\cap (-t,t)|+|A\cap (\mathbb{R}-(-t,t))|$

1 vote

$I_1,I_2,\dots$ disjoint sequence of open intervals $\Rightarrow |\bigcup_{k=1}^{\infty} I_k|=\sum_{k=1}^{\infty}\ell(I_k)$

1 vote

Nested sequence of compact subsets covering an open set in $\mathbb{R}^n$

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