Emmanuel José García
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The half-angle formulas are central!

And as a picture is worth a thousand words...

A transformation that simplifies certain composite trigonometric integrals and offers an alternative approach to integrating through trig./hyp. substitution.

$$\int f\left(x,\tan{\frac{\beta}{2}}, \tan{\frac{\gamma}{2}} \right)\,dx=\int f\left(\frac{e^{i\alpha}+e^{-i\alpha}}{2}a, e^{i\alpha}, \frac{1-e^{i\alpha}}{1+e^{i\alpha}}\right)\,\frac{e^{-i\alpha}-e^{i\alpha}}{2i}a\,d\alpha\tag{1}$$

Where $$\alpha=\cos^{-1}\left(\frac{x}{a}\right)$$, $$\beta=\csc^{-1}\left(\frac{x}{a}\right)$$, $$\gamma=\sec^{-1}\left(\frac{x}{a}\right)$$ and $$a>0$$.

$$\int f\left(x, \sqrt{x^2-a^2}, \frac{\sqrt{x-a}}{\sqrt{x+a}}\right)\,dx= \int f\left(\frac{e^{i\alpha}+e^{-i\alpha}}{2}a, \frac{e^{-i\alpha}-e^{i\alpha}}{2}a, \frac{1-e^{i\alpha}}{1+e^{i\alpha}}\right)\,\frac{e^{-i\alpha}-e^{i\alpha}}{2i}a\,d\alpha\tag{2}$$

$$\int f\left(x, \sqrt{x^2+a^2}\right)\, dx = \int f\left(\frac{e^{\theta}-e^{-\theta}}{2}a, \frac{e^{\theta}+e^{-\theta}}{2}a\right) \frac{e^{\theta}+e^{-\theta}}{2}a\, d\theta\tag{3}$$

Where $$\theta=\sinh^{-1}(\frac{x}{a})$$ and $$a>0$$

Discovery is the privilege of the child: the child who has no fear of being once again wrong, of looking like an idiot, of not being serious, of not doing things like everyone else. - A. Grothendieck

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