Mathematics
user avatar
user avatar
user avatar
Blargian
  • Member for 6 years, 4 months
  • Last seen more than a month ago
Profile Activity
Stats
423
reputation
58k
reached
3
answers
22
questions
Communities
View all
About

Currently an undergrad Electronic Engineering student at the University of Pretoria, South Africa.

Is math related to science?

Badges
View all badges
3
gold badges
7
silver badges
17
bronze badges
Top tags
View all tags
5
Score
13
Posts
52
Posts %
0
Score
3
Posts
12
Posts %
0
Score
3
Posts
12
Posts %
0
Score
1
Posts
4
Posts %
0
Score
1
Posts
4
Posts %
0
Score
1
Posts
4
Posts %
Top posts
View all questions and answers
All Questions Answers
Score Newest
question
6
Ways to arrange books
Aug 25, 2018
question
2
Determine whether $\sum_n(2n!)/(n!(2n)^n)$ converges or diverges
Oct 2, 2017
question
2
Determine if the series 1/5 + 1/8 + 1/11 + 1/14 + 1/17 ... is convergent or divergent [duplicate]
Nov 24, 2017
question
2
Determine whether $\sum_{n=1}^\infty \frac{2}{\sqrt{n}+2} $ converges or diverges?
Nov 24, 2017
question
2
Determine if $\sum_{n=1}^\infty \frac{n+4^n}{n+6^n}$ converges
Nov 25, 2017
answer
2
Determine if the series 1/5 + 1/8 + 1/11 + 1/14 + 1/17 ... is convergent or divergent
Nov 24, 2017
answer
2
Use any test to determine convergence of the series $\sum_{n=1}^\infty \frac{(-1)^ne^{\frac{1}{n}}}{n^3}$
Nov 25, 2017
answer
1
Determine whether $\sum_{n=1}^\infty \frac{2}{\sqrt{n}+2} $ converges or diverges?
Nov 24, 2017
question
1
Use any test to determine convergence of the series $\sum_{n=1}^\infty \frac{(-1)^ne^{\frac{1}{n}}}{n^3}$
Nov 25, 2017
question
1
Applying the test for divergence to $2/\sqrt{n} + (-1)^{n}/3^{n+1}$
Oct 1, 2017
Top network posts
View all network posts
24
How are circuits which use complex ICs normally simulated?
8
How do astronauts sleep in zero G?
6
Difference between "слёзы" and "слезы"?
5
Designing 64.5kHz Hartley Oscillator

Your privacy

By clicking “Accept all cookies”, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy.