Mathematics
user avatar
user avatar
user avatar
JungHwan Min
  • Member for 6 years, 9 months
  • Last seen more than a week ago
Profile Activity
Stats
365
reputation
6k
reached
7
answers
3
questions
Communities
View all
About

Undergraduate student at Carnegie Mellon University, Math content intern at Wolfram|Alpha.

I like math, Java, the Wolfram Language, and 아희 (Aheui).

Badges
View all badges
This user doesn’t have any gold badges yet.
2
silver badges
13
bronze badges
Top tags
View all tags
4
Score
4
Posts
40
Posts %
3
Score
3
Posts
30
Posts %
2
Score
3
Posts
30
Posts %
2
Score
3
Posts
30
Posts %
2
Score
1
Posts
10
Posts %
2
Score
1
Posts
10
Posts %
Top posts
All Questions Answers
Score Newest
question
10
Why is this sum equal to $0$?
Nov 12, 2015
answer
2
$A$ can walk certain distance in $20$ days when he rests $6$ hours a day
Nov 17, 2015
answer
2
How to find interval of convergence of series?
Dec 7, 2015
answer
2
Length of a Curve (Semicirle) using integration
Feb 21, 2016
answer
2
If $f(0,0) = f(\infty,0)=f(0,\infty) = 1$, but $f(\infty,\infty) = 0$, then what is $f(a,b)$?
Sep 4, 2016
question
1
If $f(x)$ is defined on $x \in (a, b)$, then where is its integral, $F(x) = \int_c^x f(t) dt$, defined (for $c \in (a, b)$)?
Feb 18, 2018
question
1
When is $\sum_{k=1}^{n} \sin(a k + f(k))$ bounded for $a \in \mathbb{R}$, $f(k) = o(k)$?
Aug 1, 2018
answer
1
Detecting an error in the computation of an integral
Nov 15, 2015
answer
1
Integral of $e^{-x^{2}}$ and the error function
Nov 15, 2015
answer
0
How could I find the interval where the solution is valide for the initial value problem : $y'=\frac{1+3x^2}{3y^2-6y}$ with $y(0)=1$?
Feb 24, 2016
Top network posts
View all network posts
58
Appease Your Google Overlords: Draw the "G" Logo
46
Convert singular to plural
46
How do you make a Neural Net?
40
Remove surrounding zeroes of a 2d array
34
The Quantum Drunkard's Walk

Your privacy

By clicking “Accept all cookies”, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy.