Mathematics
Sean Eberhard's user avatar
Sean Eberhard's user avatar
Sean Eberhard's user avatar
Sean Eberhard
  • Member for 11 years, 8 months
  • Last seen this week
Profile Activity
Stats
9,525
reputation
241k
reached
183
answers
8
questions
Communities
View all
About

My hobbies include doing research mathematics, doing elementary mathematics, writing things in latex, cooking, correcting grammar, and being skeptical. Fortunately there is a stackexchange website for each of these compulsions.

Badges
View all badges
This user doesn’t have any gold badges yet.
27
silver badges
42
bronze badges
Top tags
View all tags
184
Score
58
Posts
30
Posts %
97
Score
31
Posts
16
Posts %
88
Score
28
Posts
15
Posts %
71
Score
17
Posts
9
Posts %
47
Score
10
Posts
5
Posts %
38
Score
12
Posts
6
Posts %
Top posts
View all questions and answers
All Questions Answers
Score Newest
answer
34
If $a^2$ divides $b^2$, then $a$ divides $b$
Aug 15, 2012
answer
21
ord $(b)|\max\{\text{ord}(g)|g\in G\}$ for all $b\in G\,$ a finite abelian group
Sep 6, 2012
answer
20
Difference between pushforward and differential
Sep 10, 2012
answer
17
$K_6$ contains at least two monochromatic $K_3$ graphs.
Sep 30, 2013
answer
15
Seating of $n$ people with tickets into $n+k$ chairs with 1st person taking a random seat
Mar 18, 2013
answer
15
Show that $ \lim\limits_{n\to\infty}\frac{1}{n}\sum\limits_{k=0}^{n-1}e^{ik^2}=0$
Feb 8, 2016
answer
12
Haar's theorem for the rotation-invariant distribution on the sphere
Mar 12, 2015
answer
12
Why is this sequence of functions not uniformly convergent?
Aug 23, 2012
question
10
Continuous Brouwer's fixed point theorem via Stokes's theorem?
Sep 12, 2012
answer
10
Compact connected group and torsion-free dual
Dec 10, 2014
Top network posts
View all network posts
26
Function that produces primes
23
morphism from a compact group to Z ?
22
Possible limits of $(1/n) \sum_{k=0}^{n-1} e^{i2\pi \cdot 2^k\alpha}$
22
Probability of satisfying a word in a compact group
22
A rather curious identity on sums over triple binomial terms

Your privacy

By clicking “Accept all cookies”, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy.