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Cronus
  • Member for 9 years
  • Last seen more than a month ago
10 votes
Accepted

Proof for continuous function on a discrete topology

10 votes
Accepted

Why isn't the Disjoint Union in Set a *product* in addition to being a coproduct?

7 votes

Lie Groups: Identity Component

6 votes

Connected Lie group is second countable?

6 votes

If $T\colon \mathbb R^n \to \mathbb R^n $ linear and $T^2 = kT$

6 votes

Why are Haar measures finite on compact sets?

6 votes

Classify the compact abelian Lie groups

6 votes

Is it possible to construct a continuous and bijective map from $\mathbb{R}^n$ to $[0,1]$?

6 votes

If all closed subsets of a set are compact, does it follow that this set is subset of a compact set?

6 votes
Accepted

Distinguishing the $+$ in $\mathbb R^n$ from the $+$ in $\mathbb R$ (where NOT distinguishing MAY INDEED cause confusion)

5 votes

Standard 7-Sphere

4 votes
Accepted

If continuous images of $X$ are closed in every $Y$, is $X$ a compact space?

4 votes

Group generated by a connected set is connected.

4 votes
Accepted

Connected, not path-connected subgroup of $\mathbb{T}^2$

4 votes
Accepted

Exponential map to simply connected abelian Lie group is an isomorphism.

4 votes

Can maximal compact subgroups of subgroups be extended to maximal compact subgroups of the ambient Lie group?

4 votes

Closed and Connected subgroups of $\mathbb{R}^n$

4 votes

Are $S^2$ and $S^3$ homotopy equivalent?

3 votes

connected $\Rightarrow$ path connected?

3 votes

Inner regularity property of Radon measures in metric spaces

3 votes

A topological group $G$ is compact whenever there is a compact $K \subset G$ such that $x K \cap K \neq \emptyset$ for all $x \in G$

3 votes

Does every locally compact group $G$ have a nontrivial homomorphism into $\mathbb{R}$?

3 votes

Being too pedantic with writing proofs

3 votes
Accepted

Example of Separable Product Space with cardinality greater than continuum?

3 votes
Accepted

Does $\partial A$ determine $A$?

2 votes
Accepted

Is a compact, connected subset of $\Bbb{R}^n$ whose boundary has empty interior inside it determined by its boundary?

2 votes
Accepted

Second countability is invariant under orbit space of an action

2 votes
Accepted

A more Intuitive proof of regularity of topological group

2 votes
Accepted

One dimensional topological subgroups of the torus

2 votes
Accepted

Kernel of restriction to dense subgroup is again dense