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Cameron Williams
  • Member for 10 years, 5 months
  • Last seen this week
  • United States
96 votes

Am I just not smart enough?

57 votes
Accepted

Why are mathematician so interested to find theory for solving partial differential equations but not for integral equation?

55 votes

Why is it not true that $\int_0^{\pi} \sin(x)\; dx = 0$?

32 votes
Accepted

Is this solution mathematically "legal"?

30 votes
Accepted

Why is the derivative of a vector orthogonal to the vector itself?

25 votes
Accepted

What is the relation between a Banach space and a Hilbert space?

23 votes

$\frac1a+\frac1b+\frac1c=0 \implies a^2+b^2+c^2=(a+b+c)^2$?

23 votes
Accepted

Upper Bound vs. Least Upper Bound

22 votes
Accepted

$A^{-1}$ has integer entries if and only if the ${\rm det}\ (A) =\pm 1$

21 votes
Accepted

What is the dot product and why do we need it?

21 votes

Why is zero the only infinitesimal real number?

19 votes
Accepted

Why formulate continuity in terms of pre-images instead of image?

17 votes
Accepted

Do row operations change the column space of a matrix?

17 votes
Accepted

How to prove $\exp(x)/(\exp(x)+1)^2$ is even?

16 votes

Determine if the following is surjective

15 votes
Accepted

Must all Lebesgue integrable functions really be invertible?

14 votes
Accepted

Why it's true? $\arcsin(x) +\arccos(x) = \frac{\pi}{2}$

14 votes

Find $\lim\frac{1}{\sqrt{n}}\left(\frac{1}{\sqrt{1}+\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{5}}+\ldots+\frac{1}{\sqrt{2n-1}+\sqrt{2n+1}}\right)$

13 votes
Accepted

Integral $\int_0^1 \log \left(\Gamma\left(x+\alpha\right)\right)\,{\rm d}x=\frac{\log\left( 2 \pi\right)}{2}+\alpha \log\left(\alpha\right) -\alpha$

13 votes
Accepted

Importance of groups $(\mathbb R,+)$ and $(\mathbb Z,+)$ for Fourier series

13 votes

Why do you need to use the chain rule in differentiation of ln?

13 votes

Convolution and multiplication of polynomials is the same?

12 votes

Intuition about the semidirect product of groups

12 votes
Accepted

Solve $2^{x+5} - 2^{x+2} = 7$

12 votes

Show $\sum_{i=0}^\infty {k+i \choose k}a^i=\frac1{(1-a)^{k+1}}.$

11 votes
Accepted

Solve equation with $x$ in the exponents

10 votes
Accepted

Finding a rare case where an incorrect rule works?

10 votes

Change of variable (translation) in complex integral

10 votes

Integral of $(3-x)/(x+2)$

10 votes

If $x>0$ and $x^a=x^b$ can one assume that $a=b$?

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