Mathematics
user avatar
user avatar
user avatar
spin
  • Member for 10 years, 11 months
  • Last seen this week
Profile Activity
Stats
9,423
reputation
280k
reached
192
answers
57
questions
Communities
View all
Badges
View all badges
5
gold badges
32
silver badges
77
bronze badges
Top tags
View all tags
382
Score
159
Posts
64
Posts %
235
Score
105
Posts
42
Posts %
103
Score
52
Posts
21
Posts %
67
Score
9
Posts
4
Posts %
44
Score
13
Posts
5
Posts %
39
Score
21
Posts
8
Posts %
Top posts
View all questions and answers
All Questions Answers
Score Newest
answer
93
Easy example why complex numbers are cool
Dec 23, 2014
question
76
Polynomials irreducible over $\mathbb{Q}$ but reducible over $\mathbb{F}_p$ for every prime $p$
Jun 20, 2012
answer
53
If $H$ is a cyclic subgroup of $G$ and $H$ is normal in $G$, then every subgoup of $H$ is normal in $G$.
Feb 8, 2012
question
51
How to prove that the sum and product of two algebraic numbers is algebraic? [duplicate]
Jun 7, 2012
answer
27
How to find pattern in $1,2,8,9,15,20,26,38....$ infinite sequence?
Sep 28, 2011
question
26
Proof that determinant rank equals row/column rank
Aug 27, 2012
question
25
$x^a - 1$ divides $x^b - 1$ if and only if $a$ divides $b$
Apr 4, 2012
question
22
If the tensor power $M^{\otimes n} = 0$, is it possible that $M^{\otimes n-1}$ is nonzero?
Apr 2, 2014
question
22
Description of Levi factors and unipotent radicals of parabolic subgroups in classical groups
Jan 14, 2016
question
19
Is there a nontrivial semidirect product of two groups isomorphic to their direct product?
Sep 24, 2012
Top network posts
View all network posts
51
Which groups can occur as the quotient of a group by its centre?
49
What is Atiyah's topological formulation of the odd order theorem?
17
How to construct a basis for the dual space of an infinite dimensional vector space?
16
Categorical Unification of Jordan Holder Theorems
15
If the tensor power $M^{\otimes n} = 0$, is it possible that $M^{\otimes n-1}$ is nonzero?

Your privacy

By clicking “Accept all cookies”, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy.