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mathkiss
  • Member for 10 years, 3 months
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13 votes
3 answers
428 views

On solving $\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{2+x}}}}=\sqrt[3]{6+\sqrt[3]{6+\sqrt[3]{6+\sqrt[3]{6+x}}}}$

6 votes
2 answers
271 views

Equation: $(x^2-9y^2)^2=33y+16$

6 votes
1 answer
234 views

Evaluate: $I=\int\limits_{0}^{\frac{\pi}{2}}\ln\frac{(1+\sin x)^{1+\cos x}}{1+\cos x}dx$

5 votes
4 answers
499 views

Find all integer solutions: $x^4+x^3+x^2+x=y^2$

3 votes
1 answer
248 views

Find the minimum value of $\frac{\sqrt{ab(a+b)}+\sqrt{bc(b+c)}+\sqrt{ac(c+a)}}{\sqrt{ab+bc+ca}}$

2 votes
1 answer
87 views

$P(-2)=P(-5)=n$

2 votes
2 answers
140 views

Find the value of a hard integral [closed]

1 vote
2 answers
273 views

Integral: $I=\int\limits_{0}^{1}\dfrac{x^2dx}{\sqrt{3+2x-x^2}}$

1 vote
1 answer
110 views

An inequality with $a,b,c>0$

0 votes
1 answer
179 views

A hard inequality with $a+b+c=3$

0 votes
1 answer
587 views

How prove this inequality: $\frac{x^3+1}{\sqrt{x^4+y+z}}+\frac{y^3+1}{\sqrt{y^4+z+x}}+\frac{z^3+1}{\sqrt{z^4+x+y}}\geq2\sqrt{xy+yz+zx}$

0 votes
1 answer
74 views

Integral: $I=\int\limits_{1}^{e}\dfrac{\ln x+\sqrt{1+\ln x}}{x\sqrt{1+\ln x}}dx$

-1 votes
2 answers
102 views

Prove that: $\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}=1$