ManOnTheMoon's user avatar
ManOnTheMoon's user avatar
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ManOnTheMoon
  • Member for 1 year, 10 months
  • Last seen more than 1 year ago
3 votes
1 answer
156 views

inclusion/exclusion for permutations from 1 to 7 with conditions

2 votes
0 answers
49 views

Wording questions regarding the two pizzas 4 sizes and 8 toppings questions

2 votes
1 answer
138 views

logic and application to a combinatorics question (Two chess players)

1 vote
1 answer
48 views

$A_1 ∩ A_2 · · · ∩ A_n $is the set of all objects that are in all of the $A_j $’s

1 vote
2 answers
615 views

Inclusion–exclusion principle; what is $(-1)^{n+1}$

1 vote
0 answers
64 views

partition and distinct summands wording problem

1 vote
0 answers
52 views

Number of solutions of $x_1 + x_2 + x_3 + x_4 + x_5 + x_6 = 34$ in positive even integers not exceeding 10

1 vote
1 answer
48 views

$\frac{1}{4}$ numerator of the boy or girl paradox problem

0 votes
2 answers
145 views

Find the number of seven-digit positive integers such that the sum of the digits is 19

0 votes
1 answer
34 views

$ \frac {p_1 \cdot \frac{1}{n}}{p_1 \cdot \frac{1}{n} + p_0(1-\frac{1}{n})} = \frac{1}{1+a(n-1)} $

0 votes
1 answer
64 views

$x = \frac{n!}{p!q!...},\space\space\space p+q+... = n $ from John Riordan's *Introduction to Combinatorial Analysis*

0 votes
1 answer
43 views

wording question regarding $\binom{n+r-1}{n}$

0 votes
1 answer
74 views

Find the number of solutions of $x + y + z + w = 1$ in integers greater than -4

0 votes
1 answer
108 views

Montmort’s matching problem with venn diagram

0 votes
1 answer
74 views

$\frac{1}{6}$ vs $\frac{5}{6}$ probability difference with 6 dice

0 votes
0 answers
67 views

wording question regarding a 13 cards game $\binom{52}{13}$ vs $\binom{52}{1}$ vs $\binom{52-4}{1}$

0 votes
0 answers
42 views

blackjack open vs close

0 votes
0 answers
56 views

$\frac{26!}{\sum_{k=1}^{26} \binom{26}{k}k!}$ trouble understanding how factorials are factored and how it's derives to Taylor series

0 votes
2 answers
137 views

$P(A_i) = \frac{1}{n} = \frac{(n-1)!}{n!} $