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Borealis
  • Member for 2 years, 7 months
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4 votes
1 answer
471 views

Understanding proof that $\mathbb{R}$ is Cauchy complete

2 votes
1 answer
127 views

Evaluate $\lim_{(x,y)\to (0,0)}{\frac{x^3 y}{x^2 - y}}$.

2 votes
2 answers
129 views

Understanding proof that multiplicative inverses exist in $\mathbb{R}$

2 votes
1 answer
35 views

Can $S = \{D_x, xD_x, x^2 D_x, x^3 D_x\}$ be extended to a set generating a Lie algebra?

1 vote
1 answer
37 views

Show that $\mathfrak{so}(p,q,\mathbb{R}) = I_{p,q} \mathfrak{so}(n,\mathbb{R})$.

1 vote
1 answer
200 views

Passing a test with multiple attempts (conditional probability)

1 vote
1 answer
65 views

Prove that the limit $\lim_{n\to\infty}{n^3}$ does not exist, using the $\varepsilon-N$ definition of a limit.

1 vote
2 answers
83 views

Convergence of $\int_{-\infty}^{\infty}{|x|\sin{x}\,dx}$

0 votes
2 answers
751 views

Prove that $\lim_{(x,y)\to(0,0)}{\frac{x^ny^m}{x^2+y^2}}=0$ if $n+m>2$.

0 votes
1 answer
131 views

Show that if $\lim_{\textbf{h}\to \textbf{0}}{T(\textbf{h})}=0$, then $\lim_{t\to 0}{T(t\textbf{v})}=0$ for some fixed $\textbf{v}$.

0 votes
1 answer
71 views

Suppose that $f$ is differentiable on $\mathbb{R}$, that $f(1)=1$ and $f(7)=5$. Show that there exists $c\in(0,4)$ such that $f'(c)=\frac{2}{3}$.

0 votes
1 answer
57 views

Prove that $f:(X,d_X)\to (Y,d_Y)$ being continuous at $x\in X$ $\Leftrightarrow$ given any neighbourhood $N$ of $f(x)$, $f^{-1}(N)$ is a nbhd. of $x$

0 votes
1 answer
30 views

Effect of replacing the $L^2$ norm in the definition of multivariable differentiability with the $L^1$ norm.

0 votes
1 answer
45 views

Integral curve equations conversion to cylindrical coordinates

0 votes
1 answer
39 views

Show that two subspaces $X$ and $Y$ of $\ell^1 (\mathbb{R})$ are such that $\overline{X+Y} = \ell^1 (\mathbb{R})$.

0 votes
0 answers
44 views

Question about the use of Green's theorem in Do Carmo's proof of the local Gauss-Bonnet theorem.

0 votes
1 answer
28 views

Cluster points of $(a_n)_{n=1}^{\infty}$, where $a_1=0$, $a_{2k}=\dfrac{(-1)^k\cdot(3k^2+k)}{k^2+7}$ and $a_{2k+1}=\dfrac{k^4}{k^3+k^2+k+1}$