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Interesting probability question, probability of getting right at this question of you check it at random.
The probability of guessing and choosing 2,3, or 5 are all 20%. Because each of these answers is not 20%, they are wrong. The probability of guessing and choosing 20% as an answer is 40%, so the ...
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Calculating $\mathbb{E}[N]$ for $N = \displaystyle \min_{n\in \mathbb{N}}\Big\{\sum_{i=1}^{n}{X_i\geq5000\Big\}}$, using Wald's lemma
We can also calculate $\mathsf E(N)$ directly. We let $\mathbb N=\mathbb Z_{\ge 1}$ and assume that $(X_n)_{n\in\mathbb N}$ is a sequence of iid random variables such that $\mathsf P(X_1 = m) = p (1-p)...
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