Skip to main content
43 votes
Accepted

What are the properties of eigenvalues of permutation matrices?

A permutation matrix is an orthogonal matrix (orthogonality of column vectors and norm of column vectors = 1). As such, because an orthogonal matrix "is" an isometry $$\tag{1}\|PV\|=\|V\|$$ ...
Jean Marie's user avatar
  • 84.5k
18 votes

What are the properties of eigenvalues of permutation matrices?

A permutation may be written as a unique product of primitive cycles $\pi = (c_1)\cdots(c_k)$. This corresponds to writing the matrix in block form with each cycle representing a block. Each cycle of ...
H. H. Rugh's user avatar
  • 35.4k
16 votes
Accepted

Number of homomorphisms between two arbitrary groups

Suppose $f:A_5 \to S_4$ be a homomorphism. Then $\ker f$ is a normal subgroup of $A_5$. But $A_5$ is simple, so $$\ker f \in \Big\{ \{e\},A_5\Big\}$$ $\ker f=\{e\}$ implies $$A_5/\{e\} \sim f(A_5)$$ ...
Chinnapparaj R's user avatar
14 votes

Secret-Santa: Probability of two people drawing each other.

Here's a fun fact: you might know that the probability that a random permutation has no fixed points is approximately $e^{-1}$ (and approaches this value quite rapidly). This generalizes: the ...
Qiaochu Yuan's user avatar
13 votes
Accepted

Find all Sylow 2-subgroups of $S_4$ using Sylow's theorems

1) Yes, you've got it. There are three unique ways to write $\{1,2,3,4\}$ as a union of two sets of size two. These are $\{1,2\}\cup\{3,4\}$, $\{1,3\}\cup\{2,4\}$, and $\{1,4\}\cup\{2,3\}$. These ...
user555203's user avatar
  • 3,387
11 votes
Accepted

What is the fractal dimension of the image given by a combinatorial sequence about permutation cycles?

$\def\FF{\mathbb{F}}$I want to make three points. (1) The generating function for this sequence $\bmod 2$ is a rational function. (2) There are good tools for understanding the fractal behavior of the ...
David E Speyer's user avatar
11 votes
Accepted

How can I tell if a permutation can be expressed as the commutator of another 2 permutations?

For the question in the post (now edited): In any group other than the trivial group and the group of two elements, every element can be written as the product of two nontrivial elements. In ...
Arturo Magidin's user avatar
10 votes

Elements of $S_n$ can be written as a product of $k$-cycles.

The conjugate of a $k$-cycle is a $k$-cycle. So $G$, the group generated by $k$-cycles is a normal subgroup of $S_n$. For $n\ne 4$, the normal subgroups of $S_n$ are $S_n$, $A_n$ and $\{\text{id}\}$. ...
Angina Seng's user avatar
8 votes

Elements of $S_n$ can be written as a product of $k$-cycles.

Here is a direct proof, requiring no knowledge of the normal subgroups of the symmetric group. Since we know that every permutation is a product of transpositions, it will suffice to show that, for ...
bof's user avatar
  • 79.6k
8 votes
Accepted

how to determine the number of moved points of a commutator [g,h] from the shared moved points of g and h

This answer uses the convention that $[g,h] = g^{-1}h^{-1}gh$. If $g$ is a permutation, the support of $g$, denoted $\mathrm{supp}(g)$, is the set of points that $g$ moves. Proposition. Let $g$ and $...
Jim Belk's user avatar
  • 49.8k
8 votes
Accepted

Any algebraic way to check valid permutations on a cube?

The question you ask is a special case of what is called the membership problem. The membership problem: Let $G$ be a group, and $H$ a subgroup. Is there an algorithm which takes an element $g\in G$ ...
David Sheard's user avatar
  • 2,402
7 votes
Accepted

How to show that $\mathbb{Z}_{12} $ is isomorphic to a subgroup of $S_7$?

Hint: look at $(1 \ 2 \ 3)(4 \ 5 \ 6 \ 7)$. What is its order?
Nicky Hekster's user avatar
7 votes

Let $\sigma\in S_n$ be an $n$-cycle, and let $\tau\in S_n$ be a $2$-cycle. Then, $\sigma$ and $\tau$ need not generate $S_n$.

Consider $\sigma=(1234)$ and $\tau=(13)$ in $S_4$. Viewed geometrically, we have four objects in a square where $\sigma$ rotates the square by $90^\circ$ and $\tau$ reflects the square on a fixed axis....
Parcly Taxel's user avatar
7 votes
Accepted

How to calculate the Galois group of $x^5+15x+12$?

Hint The polynomial $f(x) := x^5 + 15 x + 12$ is Einstein at $3$, so is irreducible, and thus $\operatorname{Gal}(f)$ is a transitive subgroup of $S_5$, namely, one of $S_5, A_5, F_{20}, D_{10}, C_5$. ...
Travis Willse's user avatar
7 votes
Accepted

Question in discrete mathematics about group permutations

$1 \xrightarrow{\text{(246)}} 1 \xrightarrow{\text{(1357)}} 3 \xrightarrow{\text{(1234567)}}4 $ $4 \xrightarrow{\text{(246)}} 6 \xrightarrow{\text{(1357)}} 6 \xrightarrow{\text{(1234567)}}7 $ $7 \...
CY Aries's user avatar
  • 23.5k
7 votes
Accepted

Does there exist any $x\in S_{10}$ such that $x(1\ \ 2\ \ 3)x=(9\ \ 10)$?

$x(1\,2\,3)x$ must be an even permutation. But $(9\,10)$ isn't. In general, to solve $xax=b$ in $S_n$where $a$ and $b$ are given permutations, note that this is the same as $(xa)^2=ba$, so this is ...
Angina Seng's user avatar
7 votes

How to know if a 8 puzzle is solvable

An inversion is an unordered pair of distinct numbers, such as $\{5,7\}$, where the two numbers are not placed in the order they are supposed to be in the puzzle (in this case, listing the numbers row-...
Arthur's user avatar
  • 202k
7 votes
Accepted

How to know if a 8 puzzle is solvable

Label the empty cell $9$. Then the above diagram represents the permutation $$(1\ 2\ 3\ 6\ 8)(4\ 5\ 9)(7).$$ The sign of this permutation equals $1$. Every move consists of swapping the empty cell ...
Servaes's user avatar
  • 65k
7 votes

How does $(abc) = (ac)(ab)$?

These cycles are effectively functions (think $f\circ g$). Since you are asking what the composition of functions $(ac)(ab)$ does to the elements $a$, $b$, and $c$, you need to read right to left, ...
ndhanson3's user avatar
  • 1,365
7 votes

Why is $(12345) = (54)(53)(52)(51)$?

This is cycle notation, which is ideal for many types of calculations with permutations. For example, the notation $(1\,2\,3\,4\,5)$ stands for the transformation that sends $$ 1 \mapsto 2 \mapsto 3 \...
Sammy Black's user avatar
  • 26.5k
7 votes
Accepted

Cycle notation: Inverse of $(1348)$ in $S_9$ ( Find the mistake)

Here $1 \mapsto 3 \mapsto 4 \mapsto 8$ is the result of applying the permutation $3$ times. So this means in $(1348)^3$, $1$ is mapped to $8$. Reading the others, we get $3\mapsto 1, 4\mapsto 3, 8\...
Vanessa's user avatar
  • 489
7 votes
Accepted

Prove that $\Gamma_{abc}=\frac{1}{2}\left(\partial_bg_{ac} + \partial_cg_{ab}-\partial_ag_{bc}\right)$

There seems to be something wrong with the cyclic renaming of indices in (2) and (3) as well as in (4) and (5). The main thing to keep in mind is that you cannot just cycle indices, but you must ...
AlexD's user avatar
  • 661
6 votes
Accepted

Permutation group equation: $x^{20} = \sigma$

Well, cycles of odd length are even permutations, and cycles of even length are odd permutations. Here we have three cycles of even length and one cycle of odd length, and so $\operatorname{sign}(\...
Vladimir's user avatar
  • 5,690
6 votes

Finding a presentation of a permutation group given the generators

$\langle x,y \mid x^7,y^2,(xyx^{-1}yx)^2,(xyx^{-3}yx^2)^2 \rangle$ is a presentation on the two given generators. Or better, $\langle x,y \mid y^2,(xyx^{-1}yx)^2,x^7(xyx^{-3}yx^2)^2 \rangle$ is a ...
Derek Holt's user avatar
  • 92.7k
6 votes
Accepted

Decomposing a permutation into 3-cycles

First, notice that, since 3-cycles are even, and products of even permutations are even themselves (if you know what it means, this comes from the fact that the map sending each permutation to its ...
Cristofer Villani's user avatar
6 votes

Secret-Santa: Probability of two people drawing each other.

Define an $r$-derangement to be a permutation whose smallest cycle has length strictly greater than $r$. Let $D_{n,r}$ denote the number of $r$-derangements in $S_n$. It is a standard result that for ...
MathematicsStudent1122's user avatar
6 votes

Why does $(13)(47)(13)(23)=(47)(23)$?

The key insight that you need is that disjoint cycles commute. This means that: $$ (1 3)(4 7)(1 3)(2 3) = (1 3)(1 3)(4 7)(2 3) = (4 7)(2 3) $$
Pedro Amaral's user avatar
6 votes
Accepted

Algorithm for finding the cycle-decomposition of a permutation.

Yes, there is a linear time algorithm. Skipping seen entries ensures each permutation entry is referenced at most $2$ times, so this is linear time. You cannot determine the number of cycles a ...
Mike Earnest's user avatar
  • 79.8k
6 votes
Accepted

Method to determine an order of an arbitrary permutation matrix

Here is how you can do it, assume the matrix is $n\times n$. Obtain the permutation $f:\{1,\dots, n\} \rightarrow \{1,\dots, n\}$ where $f(j)$ is equal to the row $x$ such that $A_{x,j} = 1$. ...
Asinomás's user avatar
  • 106k
6 votes
Accepted

Fixed-Point Free Involutions

An involution is a permutation that is its own inverse, but that can be a bit hard to parse at first. Let's see a concrete example: The map $x \mapsto -x$ from $\mathbb{Z} \to \mathbb{Z}$ is an ...
Chris Grossack's user avatar

Only top scored, non community-wiki answers of a minimum length are eligible