1
vote
Accepted
Prove this is an exact sequence
If one of $a,b$ is 0, then the proof is easy.
So assume $a,b\not=0$.
The last map in the sequence should be
$$f: ao + bo \longrightarrow o/(ao:bo)$$
$$ as + br \mapsto r$$
To see $f$ is well-defined, ...
- 310
Only top scored, non community-wiki answers of a minimum length are eligible
Related Tags
exact-sequence × 1277abstract-algebra × 484
modules × 336
homological-algebra × 289
group-theory × 195
algebraic-topology × 171
commutative-algebra × 167
homology-cohomology × 130
category-theory × 116
abelian-categories × 72
abelian-groups × 67
algebraic-geometry × 58
ring-theory × 57
tensor-products × 54
linear-algebra × 46
group-cohomology × 27
group-extensions × 27
sheaf-theory × 25
projective-module × 25
homotopy-theory × 24
solution-verification × 23
functors × 23
vector-bundles × 22
semidirect-product × 22
lie-groups × 21