7 votes
Accepted

Can we make this subspace $\aleph_0$-dimensional?

I claim that your space is the same as $\mathcal C(\bar A, \Bbb R)$. In particular the restriction map $f \mapsto f|_A$ from $\mathcal C(\bar A, \Bbb R)$ to your space is an isomorphism. The ...
Izaak van Dongen's user avatar
4 votes
Accepted

Number of continuous points of a graph (Problem 34 from 97-99 Math GRE practice questions booklet)

We furnish an example for which there are exactly two points of continuity, and no more: $$f(x) = \begin{cases} \sqrt{1 - x^2}, & x \in [-1,1] \cap x \in \mathbb Q \\ -\sqrt{1 - x^2}, & x \in [...
heropup's user avatar
  • 137k
3 votes
Accepted

Show that the jump $j_f(c)$ of increasing $f$ at $c$ is given by $\inf\{f(y)-f (x): x < c < y, x, y \in I\}$.

It is enough to show the following. If $A$ and $B$ are subsets of $\mathbb R$ such that $\inf(A)$ and $\sup(B)$ make sense, then $\inf(A-B)=\inf(A)-\sup(B)$, where $A-B=\{a-b\mid a\in A,b\in B\}$. ...
ultralegend5385's user avatar
3 votes
Accepted

Topological continuity of a circle parametrization

The preimage of an open set by a continuous map must be open in the domain. In this case, $[0,1)$ has the topology induced by $\mathbb{R}$, that is, open sets in $[0,1)$ are open sets of $\mathbb{R}$ ...
Julio Puerta's user avatar
  • 4,391
3 votes

Discontinuous solution of $y''(x)-2(1-x)(y'(x))^2=0$ with $y(0)=1$ and $y(2)=-1$

Solutions of equations always depend on the solution concept you choose, that is, you first have to define what you mean by a solution. However, your problem is a classical Dirichlet boundary value ...
Gerd's user avatar
  • 7,099
3 votes

Is open map needed to be continuous?

Consider the spaces $X = \mathbb{R}$ with the standard topology, and $Y = \mathbb{R}$ with the discrete topology. Define the map $f: X \rightarrow Y$ by $f(x) = x$, which is the identity map. $f$ is ...
Ali Mezher's user avatar
2 votes
Accepted

limit of convergent series in point wise convergent series of continuous functions

Your example is good. Here is another example with each $f_n$ also being smooth: Consider $f_n : [0, 1] \to \mathbb{R}$ given by $f_n (x) = n x \exp(-n x)$. Note that $f_n (0) = 0$ for all $n \in \...
K. Jiang's user avatar
  • 7,255
2 votes
Accepted

Discountinous function has a zero.

That's actually an interesting problem. One way is repeating one of the proofs of the IVT. Denote $a_1=a, b_1=b$, and let $h_1=\frac{a_1+b_1}{2}$. If $f(h_1)=0$ then we are done. If $f(h_1)>0$ then ...
Mark's user avatar
  • 40.2k
2 votes
Accepted

Continuity and Product Spaces

The function $h$ is continuous if and only if $f,g$ are. For one direction, assume $f,g$ are continuous and pick a net $(x_\alpha,y_\alpha)_\alpha$ in $A\times C$ converging to $(x,y)$. Then $\lim_\...
user469053's user avatar
  • 2,057
2 votes
Accepted

Prove that if $\lim_{x\to c}f'(x)$ exists, the value is $\lim_{x\to c} {f(x)-f(c)\over x-c}$ when $f$ is continuous.

You have proved the result already but you are just overthinking. Suppose $\lim_{x\to c}f'(x)=l$. Then, given $\epsilon >0$ there exists $\delta >0$ such that $|f'(x)-l|<\epsilon$ whenever $0 ...
geetha290krm's user avatar
2 votes
Accepted

If $f$ is Lipschitz and $g \in C^\infty_c(\mathbb{R})$, is $g \circ f$ Lipschitz?

If $f \in C^1_c(\mathbb{R})$, then $f^\prime$ is continuous with compact support, so $|f^\prime| $ attains its maximum, $L_f$, say. By the mean value theorem, for given $x, y$ there is $\xi\in (x,y)$ ...
Thomas's user avatar
  • 22.4k
2 votes
Accepted

"No infinite discrete subspace" vs "No infinite pairwise disjoint family of opens"

To summarize and amend comments: For $R_1$ (in particular, Hausdorff) spaces, the conditions are equivalent. But examples for $A \not \Rightarrow B$ exist among spaces which satisfy $T_1$, or weaker ...
Torsten Schoeneberg's user avatar
2 votes
Accepted

If $f$ is continuous at $a$, is $f^{-1}$ continuous at $f(a)$?

A counterexample is as follows (now $I$ is open). Define $f:(-1,+\infty)\to\mathbb{R}$ given by: $$f(x) = \begin{cases} x & \text{ $x\neq \dfrac{1}{n}, x\neq n$} \\ \dfrac{1}{2n} &\text{$x=\...
Julio Puerta's user avatar
  • 4,391
2 votes

If $f$ is continuous at $a$, is $f^{-1}$ continuous at $f(a)$?

If you relax the condition that $I$ is open, then I believe this is a counterexample. Let $f:[0,+\infty) $ be given by $$f(x) = \begin{cases} x & \text{$x \in \mathbb{Q}$} \\ -x & \text{$x \...
Julio Puerta's user avatar
  • 4,391
2 votes

Is the function $(x^2+y^2)\sin{(\frac{1}{x^2+y^2})}$ differentiable at the point $(0,0)$?

Since you already showed that $\frac{\partial{f}}{\partial{x}}$ and $\frac{\partial{f}}{\partial{y}}$ both exist at the point $(0,0)$ and are equal to $0$, your theorem 1 indicates that if $f$ is ...
Anne Bauval's user avatar
  • 35.3k
2 votes

Is $f(x,y)=\frac{3x^2-5y^2\sin(x)}{|x|+|y|}$ continous at $(0,0)$?

$\frac {3x^{2}} {|x|+|y|}\leq \frac {3x^{2}} {|x|}=3|x| \to 0$ and $\frac {|5y^{2}\sin x|} {|x|+|y|} \le \frac {5y^{2}} {|y|} =5|y| \to 0$. So $f(x,y) \to 0$ as $(x,y) \to (0,0)$. $f$ is not defined ...
geetha290krm's user avatar
2 votes

Prove or disprove $C:=\{x\in\mathbb{R}^n|f(x)\leq f(x_0)\}$ is closed

Take $n=2$ and define $f$ as $0$ in the open unit disk and $1$ outside. Then, if $x_0=(0,0)$, $C$ is the open unit disk, which is not closed.
Julio Puerta's user avatar
  • 4,391
2 votes

Prove or disprove $C:=\{x\in\mathbb{R}^n|f(x)\leq f(x_0)\}$ is closed

If $f$ is not continuous, this is clearly false. You can basically choose the values in any way you want. For example define $f:\mathbb{R}\to\mathbb{R}$ by $f(x)=0$ for $x\in(-1,1)$, and $f(x)=1$ ...
Mark's user avatar
  • 40.2k
1 vote
Accepted

Continuity of a mapping on a space of polynomial

General theoretical arguments were given in comments. More explicitely, a rough but sufficient bound is obtained via evaluation maps (as suggested in @julio_es_sui_glace's comment), for instance $$u_{...
Anne Bauval's user avatar
  • 35.3k
1 vote

A question about continuous functions with compact support in locally compact topological groups.

Funny, I was reading this part of the book just a few days ago, and it took me hours until I figured it out. I wish some authors would bother to write a few more details. Let $K$ be any compact set ...
Mark's user avatar
  • 40.2k
1 vote

Subset of $C^1([0 , 1])$ is open

Suppose $f \in G$. Since $f'$ is continuous we see that $\epsilon=\inf \{|f'(x)|: 0 \le x \le 1\}>0$. If $\|f-g\|<\epsilon$ then $g'(x)\neq 0$ for all $x$ because $|f'(x)-g'(x)|<\epsilon$ for ...
geetha290krm's user avatar
1 vote

Finding the discontinuities of $\text{inf}_i (|x - q_i| 2^i)$

Given any sequnce $(\epsilon_n)_{n\in\mathbb{N}}$ with $\epsilon_n>0$ and $\sum_{n\geq 0}\epsilon_n<\infty$ one can look at the set $\mathbb{R}\setminus\bigcup_{n\geq 0}(q_n-\epsilon_n, q_n+\...
dialegou's user avatar
1 vote
Accepted

Is this Result on Continuity of Composite functions true?

No. Take $f = g = \chi_\mathbb{Q}$, the indicator function of $\mathbb{Q} \subset \mathbb{R}$, i.e. $$ f(x) = g(x) = \begin{cases} 1 & \text{if } x \in \mathbb{Q} \\ 0 & \text{if ...
Ben Steffan's user avatar
  • 2,892
1 vote
Accepted

Continuity of Probability for Events with Density Greater Than a Threshold

Since $\lim_{y \to b+} \mathbb P(p(X) \ge y) = \mathbb P(p(X) > b)$ and $\lim_{y \to b-} \mathbb P(p(X) \ge y) = \mathbb P(p(X) \ge b)$, the only issue is whether there can be $b$ such that $\...
Robert Israel's user avatar
1 vote

Discontinuous solution of $y''(x)-2(1-x)(y'(x))^2=0$ with $y(0)=1$ and $y(2)=-1$

$\phi = y'$ $$\begin{align}\phi'-2(1-x)\phi^2=0&\implies\phi'=2(1-x)\phi^2\\&\implies\phi^{-2}\frac{d\phi}{dx} = 2(1-x)\\&\implies -\phi^{-1} = 2x-x^2+C_1\\&\implies \phi(x) = {\frac{1}...
Masd's user avatar
  • 608
1 vote
Accepted

If $f(0)=0,f(1)=1$,find all $a$ such that $\exists \xi\in (0,1)$ such that $f(\xi)+a=f'(\xi)$

This is problem 7 from last year's IMC (2023), as can be found here. I know, because I composed this problem :] For these kinds of problems, you often want to use Rolle's Theorem, which states that if ...
Mike Daas's user avatar
  • 1,879
1 vote

If $f(0)=0,f(1)=1$,find all $a$ such that $\exists \xi\in (0,1)$ such that $f(\xi)+a=f'(\xi)$

We want to reduce set of different possibilities for $a$, so it makes sense to try to find a function s.t. $f'(x) - f(x)$ has low number of possible values. If it has just one, then $f'(x) - f(x) = a$,...
mihaild's user avatar
  • 15.5k
1 vote

Differentiability of a Dirichlet Function Modified with $x^2$

$$0<\frac{|g(x)|}{|x|} \leq |x|$$ $$\lim_{x \to 0} 0 \leq \lim_{x \to 0}\frac{|g(x)|}{|x|} \leq \lim_{x \to 0} |x| \implies \lim_{x \to 0} |\frac{g(x)}{x}| = 0 \iff \lim_{x \to 0} \frac{g(x)}{x} = ...
hellofriends's user avatar
  • 1,508
1 vote
Accepted

Regularity and B-S equation

As mentioned in https://en.wikipedia.org/wiki/Geometric_Brownian_motion we have $$S_{t}=S_{0}\exp \left(\left(\mu -{\frac {\sigma ^{2}}{2}}\right)t+\sigma W_{t}\right).$$ So the mapping $(\mu, \sigma)\...
Thomas Kojar's user avatar
  • 3,611
1 vote

Find a continuous function from Moore plane to $\mathbb{R}$

It seems that you already know that the space is completely regular. So all you need to prove is that $X$ is closed in it. Because then it is a simple matter of applying the definition of being ...
freakish's user avatar
  • 43.1k

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