2 votes
Accepted

Why is coboundary $\sigma \to \sigma m-m$ automatically continuous?

We don't need that $M$ is discrete, it can be any abelian topological group. The map is continuous since it is built from continuous maps. This phrase can be made precise by at least two methods. ...
Martin Brandenburg's user avatar
2 votes

Norm is multiplicative?

Localize. Prove the norm map on ideals commutes with localization at prime ideals: $$ {\rm N}_{\mathcal O_L/\mathcal O_K}(I)\mathcal O_{K,\mathfrak p} = {\rm N}_{\mathcal O_{L,\mathfrak p}/\mathcal ...
KCd's user avatar
  • 43.2k
1 vote
Accepted

Confused about lemma in Ivan Niven's Irrational Numbers about conjugate elements in a number field

For your first question: algebraic elements in general can have minimial polynomials of large degree, but the algebraic elements in this degree-$h$ field extension all have minimial polynomials of ...
Greg Martin's user avatar
  • 74.9k
1 vote
Accepted

Suppose $0\to A\to B\to C\to D\to 0$ is exact. Let $0\to A[2]\to B[2]\to C[2]\to X\to 0$ be an exact sequence. Then, $X [2]$ is finite.

This is a bit ugly but works anyway. Consider the following diagram: $\require{AMScd}$ \begin{CD} @.B[2] @>>> C[2] @>>> X @>>> 0\\ @. @V{f}VV @V{g}VV @V{h}VV \\ ...
Just a user's user avatar
  • 13.3k
1 vote
Accepted

Given $F_0\subset\cdots\subset F_n$ and intermediate $E$, finding $F=E_0\subset\cdots\subset E_m=E$ such that $\max[E_i:E_{i-1}]\le\max[F_i:F_{i-1}]$

No. Consider $F_0 \subseteq F_1 \subseteq F_2 \subseteq F_3$ where $\mathrm{Gal}(F_3/F_0) \cong A_4$ and the subfields $F_0, F_1, F_2, F_3$ correspond to the subgroups $A_4, \mathbb{Z}/2\mathbb{Z} \...
Haran's user avatar
  • 8,911
1 vote

Twist of Elliptic curve $E_D: Dy^2=x^3+ax+b$ is not isomorphic to $E:y^2=x^3+ax+b$?

In general they are not isomorphic. Here is an argument I think should work. Suppose there were an isomorphism $\phi:E\to E_D$ defined over $K$. Now take your isomorphism over $K(\sqrt{D})$ and ...
K02's user avatar
  • 1,317
1 vote

Why do we fix an extension of valuation of $K$ to $\overline{K}$?

The extension is not unique unless $K$ is complete with respec to $v$. Take a global field $K$, with $v$ being the valuation for a maximal ideal $\mathfrak m$, then for any algebraic extension $K\...
Just a user's user avatar
  • 13.3k

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