Questions tagged [unique-factorization-domains]

A commutative ring with unity in which every nonzero, nonunit element can be written as a product of irreducible elements, and where such product is unique up to ordering and associates. Also called UFD or "factorial ring"

Filter by
Sorted by
Tagged with
0 votes
0 answers
15 views

Why $y$ is a rational integer?

I was reading that solution of $\mathbb{Z}[\sqrt{−n}]$ is not a UFD here Conclude that $\mathbb{Z}[\sqrt{−n}]$ is not a UFD. But I do not understand this line "So either $d = 1, 2$ or $\gcd(y,\...
Emptymind's user avatar
  • 1,767
0 votes
0 answers
13 views

For compact and connected $K\subset\mathbb{C}$, $H(K)$ is a PID?

For compact and connected $K\subset\mathbb{C}$, let $H(K)$ be the set of functions that extend to a holomorphic function over an open neighborhood of $K$. This answer states that $H(S^1)$ is a UFD (...
Jianing Song's user avatar
  • 1,022
0 votes
1 answer
29 views

$c(kp) = kc(p)$ where $c$ is the content of a polynomial, $p$ a polynomial in $R[x]$ and $k \in R-\{0\}$ (without assuming Gauss' Lemma)

I have been trying to prove (without assuming Gauss' Lemma) that for $R$ a UFD and $p(x) \in R[x]$ then for $k \in R- \{0\}$ we have $c(kp) = kc(p)$. My approach is as follows: $$ k\cdot c(p) \cdot p''...
JazzGuitar7's user avatar
0 votes
0 answers
26 views

Divisibility of a non invertible element in an integral domain

Let $A$ be a Unique factorization domain. I want to prove : Every non-invertible element of $A$ is divisible by at least one irreducible element. My reason to believe that is because if $x$ is non ...
Laurent Claessens's user avatar
1 vote
1 answer
73 views

Factorization of $x^3-10x+4$ over $\mathbb Q(\sqrt 2, \sqrt[3] 2)$

What is the factorization of $p(x) = x^3-10x+4$ over $ \mathbb Q(\sqrt 2, \sqrt[3] 2)?$ Since $p(x)$ is of degree $3$, it is irreducible over any field extension of $\mathbb Q$ if and only if no ...
user2345678's user avatar
  • 2,795
0 votes
0 answers
26 views

Do all polynomials $p(x)$ with integer coefficients output infinitely many composite numbers for integer $x$? [duplicate]

Inspired by this question, I was wondering if there was a simple proof that if $p(x)$ is a polynomial of degree $\geq 1$ and with integer coefficients, then $p(x)$ is a composite number for infinitely ...
Adam Rubinson's user avatar
-1 votes
1 answer
109 views

The diophantine equation $ a^2 + p b^2 = c^2 + p d^2 = q $ and related ring theory questions.

Inspired by norms of integral domains I started to think about the related diophantine equation for the norms. Let $2 < p,q $ be given primes. Consider the diophantine equation for positive ...
mick's user avatar
  • 14.6k
0 votes
0 answers
24 views

Primes in quadratic rings that are not UFD's [duplicate]

In a quadratic ring $\mathbb{Z}[\sqrt{d}]$ that is not a UFD, is there a simple proof that if an element has a norm that is a prime integer, then that element of the ring is prime, not merely ...
akay's user avatar
  • 9
0 votes
0 answers
109 views

$\mathbb Z[x_n]$ is always a UFD?

Let $n$ be a positive integer and consider $f(x,n) = \frac{x^{(2n)}}{(2n)!}$ where $x^{(m)}$ is the rising factorial: $$\begin{align*} x^{(1)} &= x\\ x^{(2)} &= x(x+1)\\ x^{(3)} &= x(x+1)(...
mick's user avatar
  • 14.6k
2 votes
1 answer
43 views

Proving existence of a lcm in a Unique Factorization Domain $D$ using the ascending chain condition?

I'm aware there are many posts asking this question, but I was wondering if it was possible to prove this fact using ascending chains? The problem (as in the title) is the following: Let $D$ be a UFD....
Isochron 's user avatar
  • 1,017
1 vote
0 answers
49 views

Is there a general formula for factorizing multivariate complex polynomials?

Let $\mathbb{C}[X_1,...,X_d]$ denote the space of polynomials over $\mathbb{C}$ in $d$ variables. In the case $d = 1$, we can always factorize a polynomial using its zeros and their multiplicity, i.e. ...
Andreas132's user avatar
0 votes
0 answers
33 views

Characterization of irreducible multivariate polynomials over the complex numbers

Let $\mathbb{C}[X_1,...,X_d]$ denote the set of polynomials over $\mathbb{C}$ in $d$ variables. If $d=1$, we know that the irreducible polynomials are exactly the polynomials of degree $1$, i.e. ...
Andreas132's user avatar
3 votes
1 answer
71 views

$A[X, Y ]/(X^2+Y^2−1)$ is integral domain

Deduce that if $A$ is a unique factorization domain (UFD) of char- acteristic zero, then $A[X, Y ]/(X^2+Y^2−1)$ is an integral domain. Let $B = A[X, Y]/(X^2 + Y^2 - 1)$, and suppose that $f(X, Y)$ ...
Abcd's user avatar
  • 437
6 votes
0 answers
64 views

Multiplicative Subsets of the Natural Numbers and Unique Factorization

Elementary number theory books often give as an example of non-unique factorization the set $S = \{4k+1: k \in \mathbb{N}\}$. $S$ doesn't have unique factorization because $(3 \cdot{7})(11 \cdot {19}) ...
Pete Klimek's user avatar
5 votes
2 answers
114 views

Prove that $\mathbb{C}[x,y,z]/(y^2z-x^3+xz^2)$ is not isomorphic to $\mathbb{C}[x]$

I want to prove that $\mathbb{C}[x,y,z]/(y^2z-x^3+xz^2)$ is not isomorphic to $\mathbb{C}[x]$. My attempt is to see that because $\mathbb{C}$ is UFD, then $\mathbb{C}[x]$ is UFD. However, in $\mathbb{...
Jessen William's user avatar
0 votes
0 answers
60 views

Decomposition of bivariate polynomials over finite fields as a sum of univariate products

Let $p$ be a prime. Given a bivariate polynomial $f(X,Y)\in \mathbb{F}_p[X,Y]$ with degrees $d_1,d_2$ in $X,Y$ respectively, what is the lowest known upper bound on the smallest integer $k$ such that $...
Mathdropout's user avatar
2 votes
0 answers
52 views

When is $\dfrac{k[x,y,z]}{(x^a +y^b+z^c)} $ a unique factorization domain?

Let $k$ be an algebraically closed field of characteristic zero. Let $a,b,c$ be relatively prime positive integers. Then, is $\dfrac{k[x,y,z]}{(x^a +y^b+z^c)} $ a UFD? This question is motivated from $...
strat's user avatar
  • 169
0 votes
0 answers
63 views

Examples of Gorenstein local unique factorization domain of dimension $2$ and embedding dimension $4$

I am looking for an example of a local UFD $(R,\mathfrak m)$ of dimension $2$ which is also Gorenstein and $\mathfrak m$ is minimally generated by four elements. Does there exist any such examples?
Snake Eyes's user avatar
1 vote
1 answer
48 views

Generator of ideal in $Q(\zeta_5)$

I am thinking about the splitting of 11 in $Q(\zeta_5)$. This totally splits, and I was told that since the minimal polynomial of $\zeta$ completely factorizes mod 11 as $$ x^4 + x^3 + x^2 + x + 1 = (...
Three aggies's user avatar
2 votes
0 answers
81 views

Bezout Lemma in $\mathbb{Z}[X]$

I'm thinking about the relation between the GCD, the resultant, and the Bezout lemma/identity for the ring $\mathbb{Z}[X]$. Take two elements $f,g \in \mathbb{Z}[X]$. We know: the GCD exists, because ...
user avatar
4 votes
3 answers
304 views

UFD implies GCD

Let $R$ be an integral domain. Assume $R$ is UFD, show $R$ is GCD. I did not find proof anywhere except one in proofwiki, but unfortunately there is a crucial part which I do not understand. https://...
Ziqiang Cui's user avatar
0 votes
0 answers
18 views

Eigenspace decomposition for an integer matrix with integer eigenvalues

Suppose $A$ is a $n$ by $n$ matrix with integer entries and all eigenvalues $\lambda_1,\dots,\lambda_k$ of $A$ are also integers. If we consider the action of $A$ on $\mathbb{C}^n$, we know that $\...
Faniel's user avatar
  • 109
1 vote
0 answers
54 views

More examples that are elementary of GCD domains that are not UFD domains.

What are some more examples that are elementary of GCD domains that are not unique factorization domains? For my personal notes, I'm looking for examples of rings that belong to one rung but not the ...
Greg Nisbet's user avatar
  • 9,673
0 votes
0 answers
46 views

Unique Factoring in $\mathbb{Z}[x]$

While in class, my professor gave us a proposition that if $R$ is a unique factoring domain, then $R[x]$ is also a unique factoring domain. While in class I didn't think too much about it, but now I ...
Ty Perkins's user avatar
0 votes
0 answers
25 views

Proving that fractions can be written in lowest terms in a unique factorization domain [duplicate]

When proving that rational numbers can be written in their lowest terms, we used the well-ordering principle to choose a numerator that is the smallest and then it contradicts the fact that this ...
AMX's user avatar
  • 61
1 vote
0 answers
49 views

Linear systems over UFDs

When Hermite and Smith normal form are discussed in the textbooks (e.g. the one of Adkins and Weintraub) they assume the ring to be a PID. What goes wrong over UFDs? Can one still do something similar ...
HCH's user avatar
  • 51
0 votes
0 answers
74 views

Irreducibility using reduction mod $p$.

I know that if $R$ is a UFD and $\mathfrak{p} \subset R$ a prime ideal and $f$ a polynomial in $R[X]$ with content 1, s.t. $\deg(f)=\deg(\bar{f})$ then: $\bar{f}$ is irreducible in $R/\mathfrak{p}[X] \...
Henry T.'s user avatar
  • 1,091
0 votes
0 answers
35 views

Proof that $v_{p}(ab)=v_{p}(a)+v_{p}(b)$

Recall. We say that an integral domain $A$ is a unique factorization domain if the following statements are true : (i) For every $a \in A \backslash \{0\}$, there exists a unit $u$, a non negative ...
Flowt's user avatar
  • 96
0 votes
0 answers
35 views

Content of polynomials in UFD.

Let $R$ be a UFD and $f(x)=\sum_{i=0}^{n} a_ix^i,g(x)=\sum_{j=0}^{m} b_jx^j\in R[x]$.The content of $f(x)g(x)$ is companion to the product of contents of $f(x)$ and $g(x)$. (By companion I mean for ...
GGG's user avatar
  • 345
1 vote
0 answers
32 views

Finding a generator for the product of two ideals in $ \mathbb{C}[X][Y]$

Let $f, g\in\mathbb{C}[X,Y]$ be two irreducible elements in $\mathbb{C}[X,Y]$ such that $(f) \neq (g)$. Give a generator for the ideal $((f) + (g)) \cdot ((f) \cap (g))$. I figured out that $(f) \cap ...
number9_displ's user avatar
0 votes
1 answer
49 views

Viewing domain elements as fractions via natural map into fraction field (abuse of notation)

We have a simple proposition saying that Proposition: Suppose $R$ is a UFD and let $Q(R)$ be the fraction field of $R$. Let $f(x)=\sum_{i=0}^n a_i x_i \in R[x]$ be a polynomial of degree $n\ge 1$. ...
Sam Wong's user avatar
  • 2,195
0 votes
1 answer
69 views

How to prove $x^p+y^p=\displaystyle{\prod_{k=0}^{p-1} (x+\xi_p^ky)}$

I am reading a "proof" of Fermat's last theorem which uses the assumption that $\mathbb{Z}[\xi_p]$ is a UFD (which is actually not true in general). This proof uses the following ...
ABC's user avatar
  • 874
1 vote
1 answer
92 views

Questions about $K[x_1, \ldots , x_4]/(x_1x_2-x_3x_4)$ being a graded ring

So I was trying to understand this answer to the question of why $K[x_1, \ldots , x_4]/(x_1x_2-x_3x_4)$ ($K$ being a field) is not an UFD, and the author seems to use the fact that $K[x_1, \ldots , ...
gisame's user avatar
  • 411
0 votes
0 answers
70 views
+100

How to show the quadratic integer ring O is not a UFD.

Let $R=\mathbb{Z}[\sqrt{−n}]$ where $n$ is a squarefree integer greater than 3. Prove that $R$ is not a UFD. Conclude that the quadratic integer ring O is not a UFD for $D\equiv 2, 3$ mod $4$, $D < ...
Aleah Lillie's user avatar
2 votes
1 answer
124 views

Problem with understanding why $\mathbb{C}[x, y] / (x^2 + y^2 - 1)$ is UFD

Reading this questions Ring of trigonometric functions with real coefficients we can see that $\mathbb{C}[x, y] / (x^2 + y^2 - 1)$ is a UFD because it's isomorphic to Laurent polynomial ring which is ...
NeoFanatic's user avatar
1 vote
0 answers
70 views

Why is a semilocal domain $A$ a UFD, if its localisations at maximal ideals $A_{\mathfrak m}$ are UFDs?

This is Exercise 20.2 in Matsumura's Commutative Ring Theory: Let $A$ be an integral domain. We say that $A$ is locally UFD if $A_{\mathfrak m}$ is a UFD for every maximal ideal $\mathfrak m$. If $A$ ...
red_trumpet's user avatar
  • 7,425
0 votes
1 answer
55 views

Is there are two prime elements which generate a proper ideal? [duplicate]

Let $A$ be a UFD, we know $A$ is a PID iff $A$ is a Bezout domain. Now I want to consider the case $A$ is not a PID. So the question is that does every UFD $A$ which is not PID admit two distinct ...
qinxs's user avatar
  • 316
0 votes
0 answers
56 views

Example of integral domain which is not a UFD [duplicate]

I was looking for an integral domain which is not a UFD and I've thought to $\mathbb{C}[x,y]/(x-y^2)$ My questions are: Is it right? Is there any easier example?
wood's user avatar
  • 288
1 vote
1 answer
111 views

D.C.C condition of principal ideals on UFD

The question is: Let $R$ be a UFD, and $I \neq (0)$ be an ideal of $R$. Prove that every descending chain of principal ideals containing $I$ must stabilize. Since for an UFD, A.C.C holds for principal ...
Donky Dang's user avatar
8 votes
0 answers
264 views

Number of ring structures on $\mathbb{Z}$ with the usual multiplication

The usual addition is not the only one that makes $\mathbb{Z}$ into a ring with the usual multiplication. Indeed, for any positive integer $n$, $\mathbb{Z}[x_1,x_2,...,x_n]$ is a unique factorization ...
Geoffrey Trang's user avatar
3 votes
0 answers
166 views

Is $\mathbb R[X,Y,Z]/(X^2+Y^2+Z^2+1)$ a unique factorization domain?

Let $\mathbb R$ be the field of real numbers. From Nagata's criterion for unique factorization domains, it follows that $\frac{\mathbb R[X_1,\ldots,X_n]}{(X_1^2+\ldots+X_n^2)}$ is a unique ...
sagnik chakraborty's user avatar
0 votes
0 answers
28 views

Is it true that an uniformizing element of a discrete valuation ring $R$ is either zero or prime?

Let $R$ be a DVR. This means that it is a PID with a unique maximal ideal. Let us denote $m$ to be the maximal ideal. Then there is a unique irreducible element $\pi$ up to multiplication my a unit ...
user1294729's user avatar
  • 1,952
0 votes
1 answer
210 views

Problem in understanding of If $R$ is a UFD, then $R[x]$ is also a UFD(Gauss's theorem)

Gauss's Theorem:If R is a UFD then so is R[X], the ring of polynomials over R. I am studying the the from this pdf. But I have problem in understanding. Proof: Take a (non-zero) polynomial $f ∈ R[X]$....
Alexander's user avatar
  • 293
1 vote
0 answers
40 views

Minimal non-zero prime ideal in a UFD

I'm trying to understand the following Proposition: Proposition: Let $R$ be a UFD (unique factorization domain) with subset $P$ of the set of irreducible elements of $R$. Then $P$ is in bijective ...
R.S.'s user avatar
  • 119
1 vote
1 answer
78 views

Finding $x$ from $Ax = b$ with $QR$ factorization

I'm currently trying to find $x$ such as $A x = b$ where $A \in \mathbb{R}^{5\times 5}$, $x \in \mathbb{R}^{5}$ and $b \in \mathbb{R}^{5}$. I used for that the $QR$ factorisation. I know I have the ...
Emile Couzin's user avatar
0 votes
1 answer
117 views

Is $\mathbb{Z}[\sqrt[3]{2}]$ a UFD? [duplicate]

Is the quotient ring $\mathbb{Z}[X]/(X^3-2)$ a UFD? I don’t have any idea to find whether some ring is a UFD or not.
microman's user avatar
0 votes
1 answer
470 views

How can an irreducible polynomial be represented as a product of irreducible polynomials? [duplicate]

In Charles Pinter's Abstract Algebra, he presents the factorization theorem for polynomials. That is, Every polynomial $a(x)$ of positive degree in $F[x]$ can be written as a product \begin{equation*}...
jinks908's user avatar
1 vote
0 answers
120 views

Show that the ring $\mathbb C[x^3,x^2y,xy^2,y^3]$ is normal, but it is not a unique factorisation domain

OExercise I am trying to solve: Show that the ring $R = \mathbb{C}[x^{3}, x^{2}y, xy^{2}, y^{3}]$ is normal, but $R$ is not a unique factorisation domain. Normal means that $R$ is integrally closed ...
user1318's user avatar
2 votes
1 answer
550 views

Let $R:=\mathbb{Z}[\sqrt{-6}]$. Prove that $R$ is not a Unique Factorization Domain

Question: Let $R:=\mathbb{Z}[\sqrt{-6}]$. (a) Prove that $R$ is not a Unique Factorization Domain (b) Find an irreducible element of $R$ that is not prime (c) Find a non-principal ideal in $R$ (d) ...
Rough_Manifolds's user avatar
2 votes
0 answers
103 views

What are the integers that lack unique factorization in $\mathbb Z[\zeta_n],$ $n= 23$? [closed]

In the cyclotomic integers $\mathbb{Z}[\zeta_n]$, $n=23$ has class number $3$ and so unique factorization fails (https://en.wikipedia.org/wiki/Cyclotomic_field ). Can anyone give me examples of such ...
Eric Wheeler's user avatar

1
2 3 4 5
14