Questions tagged [singular-measures]

Two measures are said to be singular w.r.t. each other if they are supported on disjoint sets.

Filter by
Sorted by
Tagged with
2 votes
1 answer
48 views

Could the definition of singular measures be weakened?

The question: The standard definition of singular measures is given on Wikipedia: Two positive measures $\mu$ and $\nu$ defined on a measurable space $(\Omega,\Sigma)$ are called singular if there ...
donaastor's user avatar
  • 1,667
2 votes
1 answer
110 views

Derivative(s) of Cantor Measure (Donald L. Cohn ch. 6.2, exercise 6.2.4, related to lemma 6.2.5)

First, context: I'm doing a course on measure/integration theory following the book by Donald L. Cohn. In section 6.2, he defines the (upper and lower) derivates of a finite Borel measure $\mu$ on $\...
Carl-Fredrik Lidgren's user avatar
0 votes
1 answer
138 views

Clarification on mutual singularity of probability measures

Let $P_1$ and $P_2$ be two probability measures on a measurable space, $(\Omega, \mathcal{F})$. Then $P_1$ and $P_2$ are mutually singular (denoted $P_1 \perp P_2$) if there exists $A \in \mathcal{F}$ ...
user avatar
0 votes
1 answer
133 views

$\lambda$ charge, $\mu$ measure, $\lambda \bot \mu$ implies $\lambda^{+},\lambda^{-},|\lambda|\, \bot\, \mu$

Let $\lambda$ a charge and $\mu$ a measure in $(X,\mathcal{X})$, with $\lambda\,\bot\,\mu $. So, $\exists A,B\in\mathcal{X}$ such that $A\cap B=\emptyset$, $X=A\cup B$ and $\lambda(A)=\mu(B)=0.$ I'm ...
Mateus Rocha's user avatar
  • 2,626
1 vote
0 answers
105 views

Singular Borel measures that are regular and the quotient of it's derivative over itself.

Let $\lambda$ be a positive regular Borel measure such that $\lambda\perp m$ on $\mathbb{R}^n$. Let $E$ be Borel with positive $\lambda$ measure and on $E$ $$\limsup_{r\to 0^+}\lambda B(x,7r)/\lambda ...
CitizenSnips's user avatar
0 votes
1 answer
181 views

Support of a Measure (Singular to Lebesgue)

On $[0,1]$ let m be lebesgue measure and $\mu$ a positive borel measure with $\mu \perp m$. Show that there exists a measure $\nu$ such that $\|\mu-\nu\|< \epsilon$, and $m(\text{support}(\nu)) = ...
Will Porteous's user avatar
2 votes
1 answer
66 views

Does the Lebesgue measure on the segment $y=x$ represent this distribution?

Set $\Omega=(-1,1)^2$. Consider the following measure on $\Omega$: $\mu(A)=m(A \cap L)$, where $L=\{ (x,x) \, | \, -1 < x < 1\}$ (the segment of the line $y=x$ in $\Omega$) , and $m$ is the ...
Asaf Shachar's user avatar
1 vote
0 answers
130 views

Singular bivariate distributions

It is known that singular copulas with prescribed support do not have a density, i.e. $\frac{\partial^2 \mathbf { C } \left( u _ { 1 } , u _ { 2 } \right)}{\partial u_1 \partial u_2} = 0$. For example,...
Alex's user avatar
  • 121
0 votes
0 answers
119 views

Singular continuous

I am trying to construct a probability measure which is absolute continuous, singular constinuous and discrete. How can I do? I have not been able to find any example os such a measure. Might you help ...
anonymous's user avatar
0 votes
0 answers
108 views

Singular function that is Holder for all $\alpha<1$

I am asking for an example of a singular continuous function that is Holder for all $\alpha<1$. We know that such function cannot be Lipschitz, otherwise it is absolutely continuous. We also know ...
Tongou Yang's user avatar
  • 1,985
3 votes
0 answers
307 views

property of singular measure with respect to Lebesgue measure

Question: Let $\mu$ be a finite positive Borel measure on $\mathbb{R}$ that is singular to Lebesgue measure. Show that $$\lim_{r\to 0^+} \frac{\mu([x-r,x+r])}{2r}=+\infty$$ for $\mu$-almost every $x\...
Mathillda's user avatar
  • 295
11 votes
1 answer
588 views

An example of a a convolution of singular distribution and a Gaussian distribution that has a 'simple' pdf

I am looking for a nontrivial example of a singular distribution that when convolved with a Gaussian distribution has a pdf of a 'simple' form. I let 'simple' be something that you interpret ...
Boby's user avatar
  • 5,843
4 votes
1 answer
167 views

Reverse type $1-1$ inequality

If $\mu \in \mathcal{M}(\mathbb{T})$ is nontrivial and singular with respect to lebesgue measure, then $$|\{\theta \in \mathbb{T} : M\mu(\theta) >\lambda\}| \ge \frac C\lambda \|\mu\|$$ where $| \...
David Bowman's user avatar
  • 5,542
1 vote
0 answers
45 views

$\mu := \sum_{n\le 1} a_n \mu_n$ and $\mu _n \perp \nu$ . Show $\mu \perp \nu$.

Let $(\mu_n)_{n\in \Bbb N}$ and $\nu$ be $\sigma$-finite measures on $(\Omega , \mathcal A)$ and $(a_n)_{n\in \Bbb N}$ such that $\mu := \sum_{n\le 1} a_n \mu_n $ is a signed measure. Further, there ...
DeltaChief's user avatar
3 votes
1 answer
130 views

Cantor function behavior close to point $1$

I was reading about the Cantor function (The Devil's Staircase) here and based on the picture and the description of the function, it seems to me that when $x \rightarrow 1$, $$1-c(x)=o(1-x).$$ Is ...
Alik's user avatar
  • 221
1 vote
1 answer
772 views

Understanding Folland's definition of two complex measures being mutually singular

In Folland's "Real Analysis", two complex measures $\nu=\nu_r + i\nu_i$ and $\mu=\mu_r + i\mu_i$ are said to be mutually singular (in symbols: $\nu\perp \mu$) if "$\nu_a \perp \mu_b$ for $a,b = r,i$". ...
Kimarokko's user avatar
  • 473
2 votes
0 answers
177 views

Singular measures

I'm given a measurable space $(\Omega, \mathcal F)$ and two probability measures $\mu,\nu$ on it with $\mu\ne\nu$. Consider the product measures $P:=⊗_{k\in \Bbb N}\mu$ and $Q:=⊗_{k\in \Bbb N}\nu$ on $...
john_jerome's user avatar
4 votes
1 answer
4k views

Properties of mutual singular measures

Let $\mu$ be a positive measure and $\nu_1, \nu_2$ arbitrary measures, all defined on the same measurable space $(S,\Sigma)$. We say that two arbitrary measure $\mu, \nu$ are mutually singular (...
iJup's user avatar
  • 1,919
0 votes
1 answer
133 views

Measure theory (Singularity)

If $μ$ and $v$ be positive measures on $(X,Σ)$ such that each positive $ϵ$ there is a set $A$ in $Σ$ that satisfies $μ(A)<ϵ$ and $ν(A^c)<ϵ$. Now how to prove that $μ$ and $v$ are mutually ...
Antora's user avatar
  • 31
2 votes
0 answers
72 views

Singular Measures on product $L^2$ Space

Let $<\Omega,\mathfrak{F},\mathbb{P}>$ be a probability space and let $\mathfrak{F}_1\cup\mathfrak{F}_2 =\mathfrak{F}$ be independent $\sigma$-fields. Then do there exist singular measures $\...
ABIM's user avatar
  • 6,609
1 vote
2 answers
1k views

Singular measure example?

Can anyone tell me if I am grasping this correctly? Let $(X,\mathcal{F})$ be a measurable space where $X=[0,4\pi]$and then let $\lambda_{1}$ be a signed measure defined by $$ \lambda_{1}(E)=\int_{E} ...
AnalysisStudent's user avatar
2 votes
1 answer
521 views

Poisson Process independent Wiener Process using singular measures

I was reading some stochastic calculus of Jump processes and saw the following result: If $W_t$ is Brownian and $N_t$ is Poisson both adapted to the $W_t$'s natural filtration then these processes ...
ABIM's user avatar
  • 6,609
0 votes
1 answer
38 views

Measures which are constant when not zero

Let $S$ be a finite set. I want to consider measures $\mu$ on $S$ which are constant only when not zero. As an example, let $S$ be $\{a,b,c,d,e\}$, and take the measure: $\mu(a)=\mu(b)=\mu(e)=1/4,\...
geodude's user avatar
  • 7,929
1 vote
0 answers
279 views

Does mutual singularity of measures imply absolute continuity?

I know that, a measure $\nu$ is absolutely continuous with respect to another measure $\mu$ if $\mu(A)=0$ implies $\nu(A)=0$. and the relation is indicated by $\nu<<\mu$. On the other hand, ...
Stat95's user avatar
  • 147
1 vote
1 answer
182 views

$λ = f dµ$ and $ρ = g dµ$ for Lebesgue measure $µ$, give necessary and sufficient conditions on $f,g$ for $λ ⊥ ρ$ and $λ << ρ$

Le $f,g : \mathbb{R} → \mathbb{R}$ be extended integrable functions. Let $λ = f dµ$ and $ρ = g dµ$ for Lebesgue measure $µ$. Give necessary and sufficient conditions on $f,g$ for $λ ⊥ ρ$ and necessary ...
user138017's user avatar
  • 1,151
-1 votes
1 answer
95 views

Show that Uniform$(1,5)$ is neither singular nor absolutely continuous with respect to Uniform$(0,3)$.

Actually, I'm just studying singular continuity, absolute continuity.I know the definitions.And have solved few very basic sums. Now, in this problem, I'm not understanding what does this 'with ...
saudade's user avatar
  • 675
1 vote
0 answers
152 views

Singularity of measures

I study the book of Gamelin about uniform algebras. As a corollary of the following Lemma: "let $K$ be a (weak star) compact convex set consisting of positive measures and a (complex) measure $\mu$ is ...
truebaran's user avatar
  • 4,520
2 votes
1 answer
352 views

Under the Borel measure associated to the Cantor function each of the intervals remaining in the construction of the Cantor set has measure $2 ^{-n}$

Let $f$ be a function such that agrees with the cantor function on $[0,1]$, vanishes on $(-\infty,0)$, and is identically $1$ on $(1,+\infty)$ and let $\mu_f$ the Borel measure associated to $f$. Show ...
Jose Antonio's user avatar
  • 7,064
2 votes
0 answers
100 views

Decomposition of a measure

Let $\mu$ be the Lebesgue-Stieltjes measure on $\mathbb{R}$ corresponding to the distribution function, $F$ where $$F(x) = \left\lbrace \begin{array}{ll} 0& \text{if} \,\, x<0\\ ...
user145993's user avatar
  • 1,339
0 votes
2 answers
197 views

two mutually singular measures witch both support is whole $\mathbf{R}$

I have some problem with an exercise(for homework): Find two mutually singular measures $u$ and $v$ (Borel finite on $\mathbf{R}$) with $$\mathrm{supp}(u)=\mathrm{supp}(v)=\mathbf{R}.$$ I tried to ...
user207950's user avatar
1 vote
0 answers
283 views

How to calculate expectation of Cantor distribution without using p = 0.5

The question goes like this: given F(x) is the distribution function of Cantor distribution, how to calculate $E(x) = \int xdF(x)$ without using the argument of the following: X is characterized by ...
Riley Zhang's user avatar
1 vote
2 answers
287 views

Consider two singular measures $ m$ and $v$ and $v$ is absolutely continuous with respect to $m$ show that $v=0$

Consider two singular measures $m$ and $v$ on a measurable space $(X,\mathcal{A})$ and $v$ is absolutely continuous with respect to $m$, i.e., $(v<<m)$. Show that $v=0$.
EEE's user avatar
  • 221
1 vote
2 answers
651 views

Singular Lebesgue-Stieltjes measure

I read that if $F:\mathbb{R}\to\mathbb{R}$ is a non-decreasing singular function, i.e. a non-decreasing continuous function such that $F′(x)=0$ almost everywhere, then the Lebesgue-Stieltjes measure $\...
Self-teaching worker's user avatar
1 vote
0 answers
111 views

Representations and mutually singular measures

I'm finding some difficulties with an exercise from Conway and I ask for some help in understanding it: "Let X be a compact space and let $\{\mu_n\}$ be a sequence of measures in X. For each $n$ let $...
Benzio's user avatar
  • 2,057
4 votes
2 answers
1k views

Do there exist two singular measures whose convolution is absolutely continuous?

Let $\mu, \nu$ be finite complex measures with compact supports on the real line, and assume that they are singular with respect to the Lebesgue measure. Can their convolution $\mu\ast\nu$ have a ...
limanac's user avatar
  • 619
0 votes
1 answer
184 views

Two Radon measures and mutual singularity

Let $\mu$ and $\lambda$ be Radon measures on $\mathbb{R^n}$. Show that $\mu$ and $\lambda$ are mutually singular iff $D(\mu,\lambda,x)=\infty$ for $\mu$ almost all $x \in \mathbb{R^n}$. I have looked ...
Trajan's user avatar
  • 5,152
6 votes
2 answers
2k views

How we compute expectation of a singular random variable?

In probability (or measure) courses, we often see the Cantor distribution that is singular with respect to the Lebesgue measure. Its CDF is increasing but whenever its differentiable, the ...
Sergio Parreiras's user avatar
2 votes
1 answer
3k views

Jordan decomposition theorem (question to singularity)

Let $(\Omega,\mathcal{A})$ be a measurable space. (Hahn Decomposition Theorem) Let $\varphi\colon\mathcal{A}\to\mathbb{R}$ be a signed measure. Then there exist disjoint sets $\Omega^+\in\...
mathfemi's user avatar
  • 2,591
12 votes
3 answers
5k views

Singular continuous functions

A function $f:[0,1]\rightarrow\mathbb{R}$ is called singular continuous, if it is nonconstant, nondecreasing, continuous and $f^\prime(t)=0$ whereever the derivative exists. Let $f$ be a singular ...
user avatar
1 vote
1 answer
318 views

Question about singular continuous functions

A function $f:[0,1]\rightarrow\mathbb{R}$ is called singular continuous, if it is nonconstant, nondecreasing, continuous and $f^\prime(t)=0$ for almost every $t\in(0,1)$. Let $f$ be a singular ...
user avatar
1 vote
0 answers
166 views

Product of a singular and continuous measures

Suppose we have a function $f(x,y)\geq 0$ and we integrate it with respect to a measure $\mu=\mu_{\mathrm{a.c.}}+\mu_{\mathrm{disc}}+\mu_{\mathrm{s.c}}$. Is it true that \begin{equation} \iint f(x,y)d\...
Mikhail's user avatar
  • 21
4 votes
2 answers
922 views

Singular measures on Real line

Can some one please give me an example of continuous Singular measure on Reals which is not absolutely continuous to cantor-type sets. Thank you.
chandu1729's user avatar
  • 3,791
2 votes
0 answers
346 views

CDF of non-atomic singular measure

Suppose $\mu$ is a non-atomic measure on the Borel subsets of $[0, 1]$ such that $\mu$ and Lebesgue measure are mutually singular. Show that if $F$ is the cumulative distribution function of $\mu$, ...
Absar Ul Haq's user avatar
2 votes
0 answers
67 views

Singular measure with respect to translates

Let $\mu$ be some Borel measure on $\mathbf{R}$ such that, for every $t \neq 0$, the push-forward $(\tau_t)_* \mu$ is singular with respect to $\mu$ (where $\tau_t(x)=x+t$). What can we say about $\mu$...
timofei's user avatar
  • 737
0 votes
1 answer
1k views

Singular measure with respect to Lebesgue measure

Let $\mu$ be a finite positive Borel measure on $\mathbb{T}$ such that $\mu$ is singular with respect to Lebesgue measure. Let $E$ be a closed subset of $\mathbb{T}$ such that $\mu(\{x\})=0$ for every ...
Abelvikram's user avatar
0 votes
1 answer
739 views

Singular measure is regular

In Rudin Real and Complex Analysis, the proof of theorem 7.13 (page 142 3rd ed), why is $\mu$ regular? If I understand correctly: prove that a singular complex Borel measure is regular. The reasoning ...
PPR's user avatar
  • 1,046
1 vote
1 answer
196 views

Uniqueness of singular measure for inner function

A singular inner function $M$ (an analytic function on the open unit disk without zeros which takes on unimodular boundary values almost everywhere) can be written as $$M(z)=c \exp\left(\int_0^{2\pi} \...
Anonymous999's user avatar
  • 1,238
3 votes
1 answer
182 views

Bound on the growth of a singular measure

Working through some measure theory, I came upon the Lebesgue-like decomposition for monotonic functions. In that context, I've cooked up a singular measure $\nu$ on $[0,1]$ about which I know only ...
Eugene Shvarts's user avatar
5 votes
2 answers
3k views

Mutually Singular measures

c.f. Rudin's Real and Complex Analysis (Third Edition 1987) Chapter 6 Q9 Suppose that $\{g_n\}$ is a sequence of positive continuous functions on $I=[0,1]$, $\mu$ is a positive Borel measure on $I$, $...
Cecilia's user avatar
  • 51
5 votes
1 answer
588 views

Singular measures - approximate characteristic function

One can decompose a $\sigma$-finite measure $\mu$ on $\mathbb{R}$ in three parts: $\mu_{ac}$: absolutely continuous $\mu_{sc}$: singular continuous $\mu_{pp}$: pure point A common example for a ...
user13655's user avatar
  • 438