Questions tagged [separation-axioms]

Separation axioms are properties of topological space which, roughly speaking, say in what way two points, a point and a closed set, or two closed sets can be "separated". Most important are $T_0$-spaces, $T_1$-spaces, Hausdorff, regular, completely regular and normal spaces.

Filter by
Sorted by
Tagged with
2 votes
1 answer
46 views

Comparing two notions of "needed-for-Hausdorffness"

Suppose $\mathcal{X}=(X,\tau)$ is a non-Hausdorff space. There are two ways to make precise "the sets that need to become open if we refine $\mathcal{X}$ to become Hausdorff" that I'm ...
Noah Schweber's user avatar
-2 votes
0 answers
88 views

Uncountable product of real interval is connected and separable? [closed]

I've learned that countable product of connected separable space is connected separable. Suppose we have an arbitrary set $S$. Let $A=[0,1]^S$ be a weakly ordered space. Is $A$ connected separable? A ...
dodo's user avatar
  • 622
0 votes
1 answer
33 views

Proof that every $T_0$ Topological Vector Space is regular

I'm currently reading through Convex Analysis and Beyond by Mordukhovich and Nam where the following preposition and proof are given (note that the authors define TVSs to be $T_0$). Proposition 1.92 ...
TheLimePixel's user avatar
0 votes
1 answer
31 views

$k_3$-Hausdorff

A subset of a space is $k_1$-closed if its intersection with every compact subset is closed in the subset. A subset of a space is $k_2$-closed if its intersection with every continuous image of a ...
Steven Clontz's user avatar
1 vote
1 answer
33 views

Are retracts always closed in a compact weak Hausdorff space?

A retract is a subspace $R\subseteq X$ for which there exists a continuous map $f:X\to R$ with $f(r)=r$ for all $r\in R$. If $X$ is compact and has the property KC (all compacts are closed, a ...
Steven Clontz's user avatar
2 votes
1 answer
39 views

Is a space $T_1$ iff every irreducible component is a point?

I've been thinking a little about irreducible components while reading Atiyah and Macdonald and wanted to try and understand the idea of irreducible component in more general terms of separation ...
Isky Mathews's user avatar
  • 3,143
5 votes
2 answers
125 views

How are k-Hausdorff and weakly Hausdorff distinct?

In this pull request to the pi-Base database, we encountered this situation. A space $X$ is said to be weakly Hausdorff provided for every compact Hausdorff space $K$ and every continuous $f:K\to X$, $...
Steven Clontz's user avatar
6 votes
1 answer
161 views

Why is a Countable Basis Needed in This Proof?

My question is regarding the Theorem in Munkres that states: Every Regular Space with a Countable Basis is Normal. Before reading the proof in Munkres, I tried to prove it myself and came up with a &...
Kenneth Winters's user avatar
1 vote
1 answer
53 views

Is there an error in Steen and Seebach's Counterexamples space 99 "Maximal Compact Topology"?

In Counterexamples space 99, the Maximal Compact Topology is asserted to be non-Hausdroff (note 1), KC (compacts are closed, note 3), and first-countable (note 5). But KC spaces are US, and first ...
Steven Clontz's user avatar
1 vote
3 answers
107 views

What separation is required to ensure extremally disconnected spaces are sequentially discrete?

Conversation continued at MathOverflow In https://github.com/pi-base/data/issues/387 it is noted that Tychonoff extremally disconnected spaces are sequentially discrete (see Encyclopedia of General ...
Steven Clontz's user avatar
5 votes
1 answer
37 views

How separated is a submetrizable space?

A space is submetrizable if its topology contains a coarser metrizable topology. Each such space is Hausdorff: given two points $x,y$, the sets $B_{|x-y|/2}(x),B_{|x-y|/2}(y)$ are open in the space. ...
Steven Clontz's user avatar
1 vote
1 answer
56 views

Are pseudonormal pseudocompacts all weakly countably compact?

All normal pseudocompacts are weakly countably compact (that is, infinite subsets cannot be closed and discrete). Can "normal" be weakened to "pseudonormal"? A space is ...
Steven Clontz's user avatar
2 votes
2 answers
108 views

Extremally disconnected without Hausdorff

In Theorem T000045 of pi-Base, a proof is given to defend the assertion from Counterexamples in Topology that all Extremally disconnected ($T_2$ where the closure of open is open) spaces are Totally ...
Steven Clontz's user avatar
1 vote
0 answers
20 views

Definition of hereditarily collectionwise normal spaces using separated families

From some literature I've learned that there are two equivalent definitions of hereditarily collectionwise normal spaces, but struggling with finding a proof. Definition 1. A topological space $X$ is ...
Noiril's user avatar
  • 333
2 votes
0 answers
12 views

Continuous Functions on Compact T_2 topological spaces [duplicate]

Let $X$ be a compact $T_2$ topological space and let $x_0\in X$. Can we find a continuous function $f:X\to [0,1]$ such that $f(x_0)=1$ and $f(x) < 1$ for any $x_0\neq x$? My try: Every Compact $T_2$...
user490489's user avatar
1 vote
2 answers
69 views

Prove that a quotient space isn't Hausdorff

Let $Q=[0,1]\times[0,1]\subset \mathbb{R}^2$ and the following relation $$(x,y)\sim (x',y')\iff (x,y)=(x',y'),\; (x',y')=(x,1-y),\;x\neq 0.$$ And $\pi: Q\to Q/\sim := X$ projection on the quotient. $X$...
Turquoise Tilt's user avatar
4 votes
1 answer
88 views

Thomas plank is not realcompact

Let $X = \bigcup_{n\geq 0} L_n$ where $L_n = [0, 1)\times\{1/i\}$ for $i > 0$ and $L_0 = (0, 1)\times \{0\}$. Define the topology on $X$ as follows: each point $(x, 1/i)$ for $x\in (0, 1)$ and $i &...
Jakobian's user avatar
  • 8,148
2 votes
1 answer
103 views

$T_D$ spaces and locally closed subsets

Let $X$ be a topological space, we say it is $T_D$ if each of its points is locally closed. That is, for any $x\in X$ we have $\lbrace x\rbrace=U\cap V$ where $U\subseteq X$ is an open subset and $V\...
N.B.'s user avatar
  • 2,005
1 vote
1 answer
30 views

A space is $T_3$ if every point has a closed neighborhood that is $T_3$ in the subspace topology

Let $(X, \tau)$ be a topological space. By $T_3$ I will mean that $\forall x \in X$ and $A $ closed subset of $X$ that does not contain $x$, there exists disjoint open sets $U, V$ such that $x \in U$,...
Victor's user avatar
  • 572
0 votes
0 answers
42 views

Proof Verification Half Open Intervals are Normal Topological Spaces [duplicate]

This is the question I am attempting: Show that the real line with the topology generated by the collection of half-open intervals $[a, b) = \{x \mid a \leq x < b \}$ is normal topological space. ...
Kenneth Winters's user avatar
-1 votes
1 answer
38 views

How to construct counterexamples of spaces which satisfy some separation axioms?

I want to know some counterexamples of spaces which satisfy some separation axioms.For example, the counterexample for a space which doesn't satisfy $T_0$,$T_3$ and $T_4$ axioms. Is there a more ...
Aftermath Crazy's user avatar
-1 votes
1 answer
42 views

Locally compact and regular topogical space needs to be Hausdorff?

Consider X a topological space, that is locally compact and regular. Is X necessarily a Hausdorff space? Thank you in advance.
Guilherme N.'s user avatar
0 votes
0 answers
40 views

Regular Topological Infinite Spaces

Can anyone prove this please? Let $Y$ be regular and $A\subset Y$ any infinite subset. Then there exists a family $\{U_n| n \geq 0\}$ of open sets whose closures are pairwise disjoint and such that $A\...
nininnn's user avatar
0 votes
0 answers
32 views

If {$x$}' is closed then {$x$}' is the union of disjoint closed sets.

I'm reading about separation axioms weaker than $T_1$ on topological spaces. One article makes the following claim: In an arbitrary topological space $(X,\tau)$ (Not necessarily $T_1$) "If for ...
GumK's user avatar
  • 1
0 votes
0 answers
39 views

If $X$ is regular and $f:X \to Y$ is a continuous, surjective, open and closed function, then $Y$ is Hausdorff.

Let $(Y, \sigma)$ and $(X, \tau)$ be two topological spaces. If $X$ is regular and $f:X \to Y$ is a continuous, surjective, open and closed function, then $Y$ is Hausdorff. I've already proved that if ...
Blue's user avatar
  • 281
3 votes
1 answer
54 views

Continuity using nets on a dense subspace and regularity

If $Y$ is regular, $f:T\to Y$ is a function such that $X\subseteq T$ is dense in $T$, and for any net $x_\alpha\in X$ converging to $x\in T$, $f(x_\alpha)$ converges to $f(x)$, then $f$ must be ...
Jakobian's user avatar
  • 8,148
1 vote
1 answer
44 views

Fully normal implies collectionwise normal?

T214 of pi-Base tracks that fully $T_4$ spaces are collectionwise normal, citing an assertion from a diagram in Steen/Seebach's Counterexamples. Is fully normal sufficient? In any case, how can this ...
Steven Clontz's user avatar
0 votes
1 answer
35 views

Perfect but not fully normal spaces?

A perfectly normal space satisfies that all closed sets are $G_\delta$ (countable intersections of open sets). This implies complete normality. A fully normal space satisfies that every open cover may ...
Steven Clontz's user avatar
1 vote
1 answer
49 views

What separation properties are satisfied by the Arens space?

The Arens space is obtained by taking a discrete sequence $\{x_n:n<\omega\}$ converging to $\infty$, then attaching another discrete sequence $\{x_{n,m}:m<\omega\}$ converging to each $x_n$. ...
Steven Clontz's user avatar
2 votes
0 answers
21 views

Open "enlargement" of locally finite family of compact sets

I want to show that Let $M$ be a paracompact $T_2$ space and let $(K_i)_{i\in I}$ be a locally finite family of compact subsets of $M$, then there is a locally finite open covering $(U_j)_J$ of $M$ ...
William von Schwarz's user avatar
3 votes
0 answers
191 views

Spaces where each compact subset has compact closure: have they already been studied?

Let $(X, \tau) $ be a topological space be such that for every $K\subset X$ compact implies $\operatorname{cl}(K)$ is also compact. I am interested in the study of such spaces [call $\textrm{G} $ ...
Sourav Ghosh's user avatar
  • 12.7k
1 vote
1 answer
132 views

How to show that an unbounded set does not exist using the axioms of ZF Set Theory?

I am currently studying a course on ZF Set Theory and would like to know how to show that a set does not exist using the axioms. For example, the following two sets are clearly equivalent to a set of ...
FD_bfa's user avatar
  • 3,713
3 votes
1 answer
59 views

Proof Verification: Compact Hausdorff Implies Normal

Here is the definition of "normal space" that I am working with: A topological space $(X,\tau)$ is normal if for any two disjoint closed sets $A$ and $B$, there exists disjoint open sets $U$...
helpme's user avatar
  • 661
2 votes
0 answers
52 views

How many second-countable $T_1$ spaces are there? [duplicate]

How many second-countable $T_1$ spaces, up to homeomorphism, are there? Let $X$ be a second-countable $T_1$ space. Since $X$ is second-countable, there are at most $\beth_1$ open sets in $X$. And ...
Dannyu NDos's user avatar
  • 1,697
0 votes
2 answers
68 views

Is Right ray topology is normal space?

Let $\mathbb{R}$ be the set all real numbers with right ray topology $\Im$={$(a,\infty):a\in \mathbb{R}$}$\cup${$\mathbb{R},\emptyset$}. Is $(\mathbb{R},\Im)$ a normal space? Each non-empty closed set ...
tulepes's user avatar
  • 39
0 votes
2 answers
167 views

How to show that the space $Y$ obtained by identifying points on the same straight line through origin in $R^{n+1}-\{0\}$ is Hausdorff?

Background: $Y$ turns out to be projective space but I'm trying to prove this and have not proven it yet (i.e., $Y$ is homeomorphic to the space $X$ obtained by identifying antipodal points on the ...
Koro's user avatar
  • 10.9k
0 votes
1 answer
47 views

$X_{\alpha}$ is normal when $\prod{X_{\alpha}}$ is normal

If $\prod{X_{\alpha}}$ is normal in product topology then $X_{\alpha}$ is normal for all $\alpha$ assuming $X_{\alpha}\neq\emptyset$
Madhusudan Semwal's user avatar
3 votes
1 answer
83 views

Separating countable sets and Urysohn spaces

Consider the following separation property: For any countable disjoint subsets $A, B\subseteq X$ of a $T_1$ space $X$ such that $A\cap \overline{B} = \overline{A}\cap B = \emptyset$ there exist ...
Jakobian's user avatar
  • 8,148
1 vote
1 answer
83 views

Prove that if $Y$ is hausdorff then $Y^X$ is it too when it is equipped with open-compact topology.

So in this question is asked to show that if $Y$ is an Hausdorff space then for any other space $X$ the subset of continuous function $\mathcal C(X,Y)$ of $Y^X$ is Hausdorff but I think that really ...
Antonio Maria Di Mauro's user avatar
0 votes
0 answers
80 views

Geometric realization of a simplicial set is Hausdorff

I am reading the book May's Simplicial objects in algebraic topology and I am trying to understand the proof for Theorem 14.1 - the geometric realization of a simplicial set is a CW-complex. He says ...
Singh_Gunjeet's user avatar
0 votes
0 answers
64 views

Is a fully normal space even normal?

Ryzard Engelking in his topology text at the historical and bibliographic notes of $5.1$ says that a topological space $X$ is fully normal if every open cover has an open star refinement (click here ...
Antonio Maria Di Mauro's user avatar
1 vote
0 answers
22 views

Example of closed map from $T_2$-space onto non-$T_2$ quotient? [duplicate]

What is an example of a continuous closed surjection $f : X \rightarrow Y$ from a $T_2$-space $X$ to a space $Y$ that is not $T_2$?
murray's user avatar
  • 748
0 votes
0 answers
30 views

What is this separation property of locales called

Trying to come up with a point-free formulation of the $T_1$ axiom I thought of the following condition on a frame/locale $L$: $$\forall U \in L \, . \, U \wedge \bigwedge \{ V \in L : U \vee V = \top ...
Jonas Frey's user avatar
0 votes
1 answer
47 views

A type of $T_2$ topological space such that for every point there's a $T_3$ subspace then the whole space is $T_3$ [closed]

Given a $T_2$ topological space $(X,\tau)$ such that $\forall x\in X, \exists V\in \tau$ such that $x \in V$ and the subspace $(cl(V),\tau_{cl(V)})$ is $T_3$ then $(X,\tau)$ is $T_3$. I really don't ...
user avatar
2 votes
1 answer
68 views

Prove that $(X,\tau_1\cap\tau_2)$ is also a $T_1$-space, whenever $\tau_1$ and $\tau_2$ are $T_1$.

Let $\tau_1$ and $\tau_2$ be two topologies on a set $X$ and that $(X,\tau_1)$ and $(X,\tau_2)$ are $T_1$-spaces (discrete topology). Prove that $(X,\tau_3)$ is also a $T_1$-space, where $\tau_3=\...
cantor's sloth's user avatar
0 votes
0 answers
32 views

Separation axioms from a product to a particular space

I developed a proof of the following statement but I'm not sure if it is correct: Proposition: Let $\lbrace X_\alpha \rbrace_{\alpha \in I}$ a collection of topological spaces and consider $X := \...
Ivan Camilo Ballen Mendez's user avatar
2 votes
2 answers
100 views

Why is a perfectly normal space completely normal?

Suppose that $X$ is perfectly normal space. To show that $X$ is completely normal, I must show that every subspace of $X$ is normal. To that effect, let $Y$ be a subspace of $X$. Let $A, B$ be ...
Koro's user avatar
  • 10.9k
1 vote
0 answers
32 views

A problem about paracompact Hausdorff space and its closed subset.

Let X be a paracompact Hausdorff space. $M=\bigcup_{i=1}^{\infty}F_i$, $F_i$ is closed. Prove that M is paracompact as a subspace of X. Idea: In Munkres' book topology, there are two theorems: (1) ...
save123's user avatar
  • 309
4 votes
1 answer
86 views

If Any continuous map from $A$ into $\mathbf{R}$ may be extended to a continuous map of all of $X$ into $\mathbf{R}$. Then $A$ is closed subset.

TRUE/ FALSE: Let $X$ be a normal space and $A$ be a subspace of $X$. If Any continuous map from $A$ into $\mathbf{R}$ may be extended to a continuous map of all of $X$ into $\mathbf{R}$. Then $A$ is ...
S Joseph's user avatar
  • 505
3 votes
0 answers
45 views

quotient space of similar matrices is not Hausdorff?

This is a problem of my midterm test... Denote invertible $2\times 2$ matrices on $\mathbb{C}$ by ${\rm GL}(2,\mathbb{C})$, and define the conjugation action of ${\rm GL}(2,\mathbb{C})$ on itself by ...
Albert Liu's user avatar

1
2 3 4 5
18