Questions tagged [quotient-group]

This tag is for questions relating to "Quotient Group".

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Quotient group isomophic to $\mathbb{Z}$

In a certain document I am asked to show that if, given a group $G$, there is a normal subgroup $N$ such that $G/N \simeq \mathbb{Z}$, $\forall n \in \mathbb{N}$ there exists a subgroup $H$ such that $...
Daniel C.'s user avatar
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For group $G,H$, $f: G \to H$ be an homomorphism, and $N$ be a normal subgroup of $G$, $\frac{G}{N} \cong Im(f) \implies N \cong Ker(f)?$. [duplicate]

I am a complete beginner to Abstract Algebra. Today I asked my professor the following: For group $G$ and $H$, let $f: G \to H$ be an homomorphism, and $N$ be a normal subgroup of $G$, if $\frac{G}{N}...
wsz_fantasy's user avatar
  • 1,106
2 votes
1 answer
48 views

Finding all the possible orders of elements in a quotient group

Let $A$ be an arbitrary Abelian group and let $H:=\{a\in A\mid\exists b\in A\mid a=b^3\}.$ Prove $H$ is a normal subgroup of $A$. Determine all the possible orders of elements in the group $A/H.$ My ...
Invisible's user avatar
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1 vote
2 answers
52 views

$G/H \cong \mathbb{Z}$ implies existence of $K \leq G$ s.t. $K \cap H = 1$ and $HK = G$

Let $H \lhd G$ and $G/H \cong \mathbb{Z}$. The claim is that there is a subgroup $K \leq G$ such that $K \cap H = 1$ and $HK = G$. Is the following correct? Take $a$ to be any element in a generator ...
ploosu2's user avatar
  • 7,970
0 votes
0 answers
36 views

Stallings' Theorem

I am trying to understand Stallings' Theorem for lower central series. Here is the statement: Say we have groups $A, B$ with lower central series $A=A_1, A_2, ...$ and $B=B_1, B_2, ...$ respectively. ...
JMM's user avatar
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2 votes
1 answer
99 views

Quotient group by two isomorphic groups

In the processes of studying some questions I suddenly realized something basic but weird. We have $\mathbb{Z}\cong 2\mathbb{Z}$, but $\mathbb{Z}/\mathbb{Z}\ncong \mathbb{Z}/2\mathbb{Z}$. It looks ...
Westlifer's user avatar
5 votes
1 answer
133 views

Composition series with non isomorphic quotients

Question Let $1\lhd G_1 \lhd \ldots \lhd G_n=G$ be a composition series of the group $G$. If for every $i\not= j$ the quotients $G_{i+1}/G_i$ and $G_{j+1}/G_j$ are non isomorphic, then show that every ...
1123581321's user avatar
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1 vote
1 answer
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Openness of canonical projection of quotient topological group

I'm studying the topological groups, and have difficulties with understanding why for a canonical projection onto quotient $\rho$ for a subgroup $H$ a preimage of image of an open set $U$ $\rho^{-1}(\...
Volodymyr Savin's user avatar
1 vote
0 answers
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Quotient of the group $\mathbb{Z}^2 \oplus \mathbb{Z} ^2 \oplus \mathbb{Z} ^2$

Does there exists $x_1$, $x_2$ , $y_1$ , $y_2 \in \mathbb{Z}^2$, such that $$\frac{\mathbb{Z}^2 \oplus \mathbb{Z} ^2 \oplus \mathbb{Z} ^2 }{ \langle (x_1,y_1,0), (0,x_1,y_1) , (x_2,y_2,0), (0,x_2,y_2) ...
ghc1997's user avatar
  • 1,163
1 vote
1 answer
32 views

Subgroups of self dual groups

Let G be an infinite locally compact abelian group that is isomorphic to its own dual. If H is a closed subgroup of G, is it necessarily true that $H \cong \widehat{G/H}$? I ask because in the case of ...
Pedro Lourenço's user avatar
1 vote
0 answers
71 views

Quotient group with $\mathbb{Z}_2$ and $\mathbb{Z}_4$

I recently published another question about quotient groups. In this case, I was practising and trying to find the elements of the group $\mathbb{Z}_2 \times \mathbb{Z}_4 / \langle(1,1)\rangle$. The ...
Daniel C.'s user avatar
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4 votes
1 answer
88 views

Elements of $\mathbb{Z}_6 / \mathbb{Z}_2$

Studying some concepts of group theory and after having read and trying to assimilate the concept of quotient group, I was wondering what structure would have the group $\mathbb{Z}_6 / \mathbb{Z}_2$. ...
Daniel C.'s user avatar
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1 vote
1 answer
115 views

Is it always $|G:gG|=1$ where $G$ is a group and $g \in G$?

Is it always $|G:gG|=1$ where $G$ is a group and $g \in G$? When $G$ is finite then I use Lagrange’s Theorem, $$|G:gG|=\frac{|G|}{|gG|}=1.$$ When $G$ is not finite then I don't know what should I do. ...
Samvel Safaryan's user avatar
1 vote
0 answers
23 views

2-groups with abelianization of type (2,2)

On Olga Taussky's article "A Remark on the class field tower" there is a note on the last page where she states that P. Hall pointed out to her that exists 3 different groups of order $2^k$ ...
Vítor Machado's user avatar
-1 votes
1 answer
49 views

What is meant by the phrase "but the identity in a quotient group is the subgroup" in this Abstract Algebra proof? [duplicate]

I was reading How to Think about Abstract Algebra by Lara Alcock, and encountered the following theorem and proof in the section on Lagrange's Theorem: Claim: Let $K = \{e, (12)(34), (13)(24), (14)(...
EJoshuaS - Stand with Ukraine's user avatar
4 votes
0 answers
49 views

Element in a coset whose order's prime divisors are those of the order of the coset

This is exercise 3B.6 of Isaacs' "Finite Group Theory"; more specifically, item $(a)$. It goes: Let $N \lhd G$ and let $g \in G$, where $G$ is a finite group. Suppose $Ng$ has order $m$ in ...
Gauss's user avatar
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3 votes
1 answer
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Meaning of factorization of groups

I am studying group theory from the book "Abstract Algebra" by Dummit and Foote, and in the text the author states the following: Simple groups, by definition, cannot be "factored"...
Hesham Abdelgawad's user avatar
1 vote
1 answer
98 views

Writing a quotient group as a product of cyclic groups

Let $G = \mathbb{Z}_{12} \times \mathbb{Z}_{12}$, and let $a$ be a generator of $\mathbb{Z}_{12}$. Consider the subgroup $H$ generated by $(a^4, a^6)$. I need to write $G/H$ as a product of cyclic ...
Adam_math's user avatar
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0 votes
0 answers
33 views

Isomorphism between isomorphic abelian groups quotiented by isomorphic subgroups [duplicate]

Let $G_1$ and $G_2$ be two abelian groups such that $G_1 \approx G_2$ ($G_1$ is isomorphic to $G_2$). $H_1$ is a subgroup of $G_1$ and $H_2$ is a subgroup of $G_2$ such that $H_1 \approx H_2$. Check ...
Aman Kushwaha's user avatar
8 votes
1 answer
180 views

Is every finite simple group a quotient of a braid group?

Question: Is every finite simple group a quotient of a braid group? Context: The braid group on two strands $ B_2 $ is isomorphic to $ \mathbb{Z} $ and so the infinite family of abelian finite simple ...
Ian Gershon Teixeira's user avatar
1 vote
1 answer
65 views

The factor group $\mathbb{R} / \mathbb{Z}$ under addition has an infinite number of elements of order 4 [closed]

The factor group $\mathbb{R} / \mathbb{Z}$ under addition has an infinite number of elements of order 4. The answer is false, but I cannot still understand it. I thought that it is true since there ...
user avatar
7 votes
1 answer
155 views

If every element of $G/H$ has a square root and every element of $H$ has a square root, then every element of $G$ has a square root.

I have tried to prove this statement but cannot. Does it require the group $G$ to be abelian? This assumption is not stated in the text I am reading, but all I can get is that if we consider that $gH =...
Fnark Man's user avatar
  • 137
0 votes
2 answers
78 views

The abelianizer functor is not faithful

I wanted to understand why the abelianizer functor from the category Grp of groups to the category Ab of abelian groups is not faithful. This amounts to finding a couple of groups $G$ and $H$ and two ...
palio's user avatar
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2 votes
2 answers
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Existence of a canonical bijection between $G/H \times H/K$ and $G/K$

Suppose $G$ is a group and $K<H<G$. All of the constructions of a bijection $G/H \times H/K \to G/K$ that I saw go more or less as follows. Choose a set of representatives ${g_i}$ for $G/H$, ...
MCL's user avatar
  • 512
3 votes
1 answer
91 views

Show group defined via quotient of matrix $A$'s columns has order $|\det A|$.

The problem: Let $M \leq \mathbb{Z}^n$ be the subgroup generated by the rows of an $n \times n$ matrix $A$ with entries in $\mathbb{Z}$. Show that $G=\mathbb{Z}^n/M$ is finite if and only if $\det A \...
Robin's user avatar
  • 838
3 votes
1 answer
70 views

If $G/G’ $ is cyclic, prove by induction that $G/Z(G)$ is cyclic if $G$ is $p$ group. [duplicate]

Let $G$ be a $p$ group. If $G/G’$ is cyclic, prove $G/Z(G)$ is cyclic by induction. I tried playing with the base cases : if $|G|=p $ or $p^2$, $G $ is abelian, so $G/Z(G)=G/G =\{G\}$ which is ...
Kadmos's user avatar
  • 1,005
0 votes
2 answers
81 views

Confusion about the difference between HN/N and H/N in the second isomorphism theorem

Im trying to understand the second isomorphism theorem but I am stuck. So in my textbook the author did the following: Let G be a group and N<G a normal subgroup and H<G a subgroup. Let $\pi: G\...
muhammed gunes's user avatar
0 votes
0 answers
27 views

Isomorphic quotient ring implies sum of numerators

I have to show the following proposition: Let $O$ be a commutative unitary ring that contains $Z$ the ring of integers. $I\le O$ an ideal. Suppose that $\frac{O}{I}\cong\frac{Z}{pZ}$ with p prime ...
Alessandro Vagni's user avatar
1 vote
0 answers
72 views

Maximal quotient group of direct product

In GAP small group library, The group $$[32,2]=\langle a,b,c\mid a^4=b^4=c^2=1, ba=abc, [a,c]=[b,c]=1 \rangle.$$ We say $G/N$ is a maximal quotient group if there exists no quotient group $G/K$ such ...
Yilan Tan's user avatar
0 votes
2 answers
77 views

proof that if G is a solvable group then quotient of G is solvable

I am reading Stewart book on Galois theory, one of the theorem proves that if $G$ is solvable and $N$ is a normal subgroup of $G$, then the quotient of $G$, $G/N$ is solvable. I can't fully understand ...
Andrea's user avatar
  • 147
1 vote
1 answer
79 views

$K \leq H_1 \leq H_2 \leq G$, and that $K \trianglelefteq G$ and $H_1 \trianglelefteq H_2$. show that $[H_2 : H_1] = [H_2/K : H_1/K]$.

Suppose that $K \leq H_1 \leq H_2 \leq G$, and that $K \trianglelefteq G$ and $H_1 \trianglelefteq H_2$. Using only Lagrange, show that $[H_2 : H_1] = [H_2/K : H_1/K]$. (It's not enough to just write ...
user20194358's user avatar
3 votes
1 answer
93 views

If $[G:K] = m$, then prove that $g^m \in K$ for all $g \in G$.

Let $K$ be a normal subgroup of $G.$ If $[G:K] = m$ then prove that $g^m \in K$ for all $g \in G$. Solution: If $[G:K] = m$ then $|G/K| = m$. By Lagrange's theorem, the order of an element divides ...
user20194358's user avatar
4 votes
1 answer
143 views

Solvable-by-finite groups

I am trying to prove this: Let $G$ be a finite-by-solvable group, i.e. $G$ has a normal subgroup $N$ that is finite with $G/N$ solvable. Prove that $G$ is solvable-by-finite, i.e., $G$ has a solvable ...
Milan Rashed's user avatar
1 vote
0 answers
41 views

Find the quotient group $G/H$ of group $G = 15\mathbb{Z}_{18}$ by $H = 8\mathbb{Z}_{18}$

I have a question about Quotient groups. I have a task to find a quotient group $G/H$ of group $G = 15\mathbb{Z}_{18}$ by $H = 8\mathbb{Z}_{18}.$ $G = \{0, 3, 6, 9, 12, 15, 18, 21\}$ I found that $G / ...
m0o0n1's user avatar
  • 19
2 votes
2 answers
71 views

Show that the size of the pre-image $(\psi(x))$ is the same for all $x$. What is this size equal to?

Let $\psi: G \rightarrow H$ be a homomorphism, and let $K=\operatorname{ker}(\psi)$. Define the canonical homomorphism $\varphi: G \rightarrow G/K$ by $\varphi(x) = xK$. Show that the size of the pre-...
user20194358's user avatar
0 votes
1 answer
63 views

A quotient group of a $p$-group is a $p$-group [closed]

I'm trying to prove that given a $p$-group $G$ and any normal subgroup $A$ of $G$, the quotient group $G/A$ is also a $p$-group. If $G$ is finite, then $A$ is finite too and the size of $G/A$ is a ...
NadavS's user avatar
  • 11
1 vote
1 answer
54 views

Quotient of an abelian group by torsion subgroup provides a characteristic free abelian subgroup? [closed]

I have a follow up to this question: Rank of the quotient of an Abelian group by its torsion part?. So my understanding is given a finitely generated abelian group $G$ and its torsion subgroup $T_G$ ...
Txim's user avatar
  • 35
0 votes
0 answers
58 views

Why aren't all surjective continuous homomorphisms of topological groups open?

My apologies if this a naive question. Let $\phi:G\rightarrow H$ be a continuous surjective homomorphism of topological groups. Denote the kernel of $\phi$ by $N$, then: $$\begin{align} f:G\times N&...
Chris's user avatar
  • 2,073
3 votes
1 answer
93 views

Does it make sense to talk about a factor group by a non-subgroup?

In a problem I've just completed, I show that we have the isomorphism $SL(2,\mathbb{C})/\{-I,I\} \cong \mathcal{M}$ where $SL(2,\mathbb{C})$ is the group of 2x2 complex unimodular matrices, $\{-I,I \}$...
EE18's user avatar
  • 1,169
1 vote
2 answers
79 views

If the cardinality of the quotient set of a subgroup is $1$ does that mean that the subgroup is equal to the whole group?

Let $(G, \cdot)$ be a group and let $H \leq G$ (i.e. $H$ is a subgroup of $G$) such that $\mid G:H \mid = 1$ (i.e. the index of $H$ in $G$ is $1$). Does this imply that $G=H$? In the case that $G$ is ...
Shthephathord23's user avatar
0 votes
1 answer
57 views

Proof that all Quotient Groups are Abelian- where is my error?

I'm having trouble finding the error in my proof: Theorem: If H is a normal subgroup of G, then the quotient group G/H is abelian. Proof: $\forall x, y \in G$, $xy(yx)^{-1} = xyy^{-1}x^{-1} = e \in H$....
toothbrush's user avatar
2 votes
1 answer
77 views

Coset of $[18]$ in $\Bbb Z_{55}/11\Bbb Z_{55}?$

Q: Let $G=\mathbb{Z}_{55}$, $H=11\mathbb{Z}_{55}$ and $g=18\pmod{55}.$ Write down the elements of the left coset $gH$ as a comma-separated list of elements of $G$. My thoughts: First find $G=\mathbb{...
Jason Xu's user avatar
  • 383
1 vote
0 answers
53 views

When do $H_1 \cong H_2$ and $K_1 \cong K_2$ imply $F(H_1,K_1) \cong F(H_2,K_2)$?

Suppose $H_1$ and $K_1$ are subgroups of $G_1$ and $H_2$ and $K_2$ are subgroups of $G_2$ such that $H_1 \cong H_2$ and $K_1 \cong K_2$. When can we say $H_1 \cap K_1 \cong H_2 \cap K_2$? If this ...
khashayar's user avatar
  • 1,993
0 votes
1 answer
68 views

How to I take the quotient $GL^+(2,\mathbb{R})/SO(2,\mathbb{R})$

I am using the following representation of the $GL^+(2,\mathbb{R})$ group. $$ \exp( a+x \sigma_1 +y \sigma_2 + b \sigma_1\sigma_2) = \exp( \begin{bmatrix}a+x & -b +y \\ b+y & a-x\end{bmatrix}...
Anon21's user avatar
  • 2,455
4 votes
1 answer
78 views

Identify the group $(28\mathbb Z + 20\mathbb Z)/20 \mathbb Z$

This is a homework problem for an abstact Algebra course. Identify the group $(28\mathbb Z + 20\mathbb Z)/20 \mathbb Z$. I did this just by looking at individual elements of $(28\mathbb Z + 20\mathbb ...
pyridoxal_trigeminus's user avatar
4 votes
1 answer
92 views

Order of $xy$ in various quotients of the free product $G_1 * G_2$, where $x \in G_1, y \in G_2$ are nontrivial

Say we have two arbitrary nontrivial groups $G_1$ and $G_2$, and some arbitrary nontrivial elements $x \in G_1, y \in G_2$. Then it is known that the order of $xy$ in the free product $G_1 * G_2$ is ...
I Eat Groups's user avatar
3 votes
1 answer
57 views

Finitely generated abelian groups $G,H$ with the same finite quotients (up to isomorphism) are isomorphic

Two finitely generated abelian groups $G,H$ have the same finite quotients (up to isomorphism). Prove they are isomorphic. According to an earlier result, it seems that I need to use the fact that ...
Anon's user avatar
  • 1,649
1 vote
1 answer
70 views

For groups, rings, or $R$-modules $A, B, C$ with $C\subseteq B$, does $A/B \cong A/C$ imply that $B=C$?

I think this is true if the module is finite, using Lagrange's Theorem. However, is this the case for infinite modules (or rings, or groups)? This comes from me trying to prove that tensoring is right-...
IAAW's user avatar
  • 1,042
0 votes
1 answer
44 views

inverse elements in quotient ring $\mathbb{Z}/_{\langle 560 \rangle}$

im currently study for exam and I have a problem that I forgot how to solve. I have the quotient ring $\mathbb{Z}/_{\langle 560 \rangle}$. How do I find how many inverse elementes exists in the ring? ...
Ori Yehuda's user avatar
0 votes
0 answers
77 views

Let $G$ be a subgroup of $E(2)$ and suppose that $T$ is the translation subgroup of $G$. Prove that the point group of $G$ is isomorphic to $G/T$.

$E(n) = \{(A,x):A \in O(n) \text{ and } \mathbf{x} \in \mathbb{R}^n \}$, where $O(n)$ is the group of real orthogonal $n \times n$ matrices The point group associated to $p \in \mathbb{R}^n$ and a ...
Ethan's user avatar
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