Questions tagged [poker]

Poker is a card game with several variants (Draw, Texas Hold'em, ...), the common goal being to collect face value patterns such as "four of a kind", "full house" or "straight" or all of a suit ("flush") with five cards. Questions about combinatorics, probabilities, strategies (bluffing and betting).

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poker expectation clarification

I ran across a passage in "The Mathematics of Poker" explaining bluffing strategy. Here is a paraphrased version. Two players are playing heads-up ($1$ vs $1$) poker. They're on the final ...
nezam jazayeri's user avatar
0 votes
1 answer
46 views

When calculating probability of a one pair in 5 card poker, why do we use $\binom{12}{3} \cdot \binom{4}{1}^3$ and not $\binom{48}{3}$?

I know that when calculating the probability of getting one pair in 5 card poker, it is done like: $$ P(\text{one pair}) = \frac{\binom{13}{1} \cdot \binom{4}{2} \cdot \binom{12}{3} \cdot \binom{4}{1}^...
altntrance's user avatar
0 votes
0 answers
58 views

Probability of two pair for a poker dice

I understand that the well known way to solve this is Choose the rank for the two pairs from 6 options - $6C2$ Choose the dice for the first pair - $5C2$ Choose the dice for the second pair - $3C2$ ...
rustic.t's user avatar
3 votes
1 answer
141 views

How do I calculate the probability of getting a 5 card straight in 7 card poker?

So here's my progress on this problem. The first straight to examine is $\begin{pmatrix} A & 2 & 3 & 4 & 5 & n & m\end{pmatrix}$. If we start with all one suit, there are $\...
Alfred's user avatar
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0 votes
1 answer
50 views

How to prevent Nash-EQ solver getting stuck in an infinite loop?

I would like to write a Nash equilibrium solver for a simplified Poker game. I was reading that the way some Nash equilibrium solvers for Poker work is that they iterate until convergence: For a given ...
mercury0114's user avatar
0 votes
1 answer
30 views

What are the odds that 2 players heads-up in poker will both not make a pair or better by the river, assuming they only check?

Here is my current thinking, please let me know if it is correct. The result doesn't seem intuitive and I feel like I'm missing something, hence I am reaching out here. 52 - 4 = 48 cards remaining. (4-...
clef98's user avatar
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0 votes
2 answers
35 views

Exponentials of stochastic band matrices

Edit: I should probably say the motivation: I was interested in modeling the probability of winning a heads-up poker match if the players will play until one player goes bust. Because the game is zero ...
Davis Yoshida's user avatar
1 vote
1 answer
38 views

Probablity of 5 card holdem hand given 7 cards

The probabilities of getting a straight flush, 4 of a kind, full house, ... , and so on, when dealt 5 cards from a randomly shuffled deck are easily calculated as straight flush .000015, four of a ...
Hober Malloy's user avatar
5 votes
1 answer
143 views

Probability of poker pair - what's wrong with this?

Thanks to others here, I know the correct way to calculate the probability of one pair in 5-card poker is P(one pair) = $C(13, 1) * C(4, 2) * C(12, 3) * [C(4, 1)]^3 / C(52, 5)$ = 0.4225690276... Why ...
kotm16's user avatar
  • 53
1 vote
1 answer
27 views

What are the odds of getting 2 sets in texas holdem?

I'm looking to create a variant of holdem allowing 6 and 7 card hands in special situations. Namely, 3 pair, 2 set, and quads over set (a full mansion). My probability skills are rusty, but I'm still ...
Paul Tudan's user avatar
3 votes
1 answer
73 views

What are the odds of getting 3 pair in texas holdem?

I'm looking to create a variant of holdem allowing 6 and 7 card hands in special situations. Namely, 3 pair, 2 set, and quads over set (a full mansion). My probability skills are rusty, but I'm still ...
Paul Tudan's user avatar
2 votes
0 answers
62 views

Probability of flush given that you observe 4 diamonds out of 5 cards

I came across this probability problem. In a Texas Hold’em game, you are dealt 2 cards in your hands and the 3 flop cards are shown. You observe 4 diamonds out of the 5 cards. What are your chances ...
Emperor Concerto's user avatar
0 votes
0 answers
23 views

Modified Deck. Unique Rules. Poker Probability.

64 cards. 4 standard suits. The ranks go from 1-12. However there are 16 cards that have a rank of "0"... The 0 rank cards have some unique attributes that modify the rules: They are double ...
Nowaht's user avatar
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1 vote
1 answer
51 views

Counting problem for finding the probability of two pairs in a five card hand.

I am having trouble understanding what I have wrong in this stats problem for my hw. I am trying to find the probability of getting two pairs in a 5 card hand from a deck of cards. So first we know ...
El_Tuercs's user avatar
2 votes
1 answer
160 views

How to rank a new type of Hold 'Em Poker hand (hard)

I am trying to figure out how to rank a new type of poker hand, henceforth called a 'Block'. A Block consists of 6 cards, and so is not possible in regular Poker - only Hold'em. Each Block consists of ...
Arcra's user avatar
  • 23
1 vote
0 answers
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Probability of a straight ending on specific number in 7-Card Poker

I am trying to calculate the probability of a straight that ends on a specific number, e.g. 6:{2, 3, 4, 5, 6} or Q:{8, 9, 10, J, Q}. Calculate Total number of straights: Assume $x$ in [5,13(K)]. ...
Dylan Finlayson's user avatar
2 votes
1 answer
76 views

Combinations Straight Flush in Texas Hold'em Poker

On the Wikipedia page about Poker probabilities for 7-card poker hands (Link) it says the following for the Royal Flush: \begin{equation*} \binom{4}{1} \binom{47}{2} \end{equation*} First we choose 1 ...
Gecko's user avatar
  • 123
0 votes
1 answer
139 views

Probability of a poker hand of winning

Just by curiosity I was looking for the probabilities of poker hands as a simple array of 5 cards, and what I found in many websites are the frequencies asociated to each combination of shown in a ...
Joako's user avatar
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3 votes
1 answer
145 views

Has the game of texas hold em poker been beaten?

I am no mathematician, I guess this is obvious. I hope this question is appropriate. So, I know that in poker the opponents psychology matter, but imagine that you are playing against a perfectly ...
Nikolai Frolov's user avatar
4 votes
2 answers
134 views

Why does calculating probability of 2 pairs seem so different from for a full house?

For 5 card poker without discards/draws, the probability of being dealt a 2 pair hand is about 0.047539, and for a full house is about 0.001441. 1 I first learned about calculating for a 2 pair hand....
user1902689's user avatar
3 votes
2 answers
922 views

What is the probability of getting a full house in a 7 card poker hand

I'm trying to calculate the probability of getting a full house in a 7 card poker hand. This is obviously the number of 7 card full house hands divided by $\binom{52}7$. To try and calculate the ...
diego caples's user avatar
4 votes
3 answers
104 views

Three-of-a-kind Poker Hand Problem

Problem: Three-of-a-kind poker hand: Three cards have one rank and the remaining two cards have two other ranks. e.g. {2♥, 2♠, 2♣, 5♣, K♦} Calculate the probability of drawing this kind of poker ...
80808learn's user avatar
1 vote
1 answer
123 views

Can Nash Equilibrium strategy be exploited, if another player deviates?

Consider a 3 player game (e.g. poker for 3 people). Nash equilibrium is a set of strategies $s_1, s_2, s_3$, such that the expected profit value for each player $s_i$ $E_i(s_1, ..., s_i', ..., s_N)$ ...
mercury0114's user avatar
0 votes
1 answer
32 views

Deriving the Semi-Bluffing Formula in Poker

I am recently taking this MIT Open course, and trying to derive the Semi-Bluffing formula on my own. The formula can be found on Page 52 of the slide. I am a bit confused about why there is a $2$ in ...
JOHN's user avatar
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1 vote
0 answers
32 views

What $n$-tuple am I applying the multiplication principle to when counting Texas Hold'em pocket cards with a pair?

Textbook problem (quoted): In Texas Hold'em poker a player receives 2 cards first. These are called the player's pocket cards. Find the number of pocket card configurations (that is, the number of ...
Ungar Linski's user avatar
0 votes
1 answer
57 views

What's the number of possible five-card poker hands drawn without replacement?

So we know a standard deck has 52 cards and it's asking the number of possible 5 card hands we could get from it without replacement which means without putting them back in the deck. I thought about ...
Michael Vie's user avatar
0 votes
1 answer
115 views

Conditional Probability in poker, Bayes Theorem

In a four person pokergame you are dealt a "king of heart" and "8 of spades". Three cards lay on the table none being a king or 8, meaning there is 41 cards left. Q: What is the ...
Lola's user avatar
  • 3
0 votes
2 answers
66 views

Can this Sum be reduced? It is calculating the expected value of a poker hand when you "Run it multiple times" for the last card.

There is a scenario in poker (Texas Hold'em) where if two players go "all in", they have the option to deal the remaining cards multiple times and it results in multiple pots that they could ...
JackAce's user avatar
  • 103
2 votes
1 answer
114 views

To show that there are two people in the tournament with the same starting hand and position in a Texas Hold'em poker tournament.

A Texas Hold'em poker tournament has $1557$ players, in $9$ distinct positions at $173$ tables. Each table has a standard $52$ card deck, and each player is dealt $2$ cards. Hands are considered "...
User8976's user avatar
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1 vote
1 answer
210 views

Probability of Full House in 5 Cards Given a Pair of Aces

What is the probability of a full house in a 5 card hand, given the first 2 cards are aces? My thought process is that there are 4 other events that could occur: A: Ace p: any card of given face App —&...
Eric Hill's user avatar
-4 votes
1 answer
223 views

What are the odds of drawing a pocket pair in poker? [duplicate]

In poker, you make a pocket pair when the ranks of your first two cards match. This does not include making a pair on the flop or in a full 7-card hand. There are six ways to draw a pocket pair of a ...
Lewis's user avatar
  • 87
0 votes
1 answer
114 views

probability of getting two pairs in poker [duplicate]

If it is assumed that all (52C5) poker hands are equally likely, what is the probability of being dealt two pairs? (This occurs when the cards have denominations a, a, b, b, c, where a, b, and c are ...
BioMath's user avatar
1 vote
1 answer
110 views

Standard deviation of a sample of poker hands from Mathematics of Poker book

This is a question related to the book "The Mathematics of Poker" by Bill Chen and Jerrod Ankerman. The author is explaining how to calculate the standard deviation per 100 hands based on a ...
luckyfool's user avatar
  • 113
0 votes
1 answer
46 views

Calculate the probability that a poker hand of 13 cards does not contain at least one suit

I know that this problem can be correctly calculated using inclusion-exclusion principle. However, I thought solving for the complement (i.e. the probability that it contains all suits) would be the ...
KII's user avatar
  • 55
3 votes
1 answer
172 views

Probability of having n number of cards of the same kind from drawn N cards

Introduction Before starting, I would like to specify a few things: The deck has 52 cards. From 1 (Ace) to 10, J, Q, K, all in four different suits: spades, diamonds, club and hearts. I don't add ...
Enderluck's user avatar
  • 110
0 votes
0 answers
49 views

Which card should we change (and to what card) to maximize the probability of getting two pairs?

In a standard $52$-card deck we change 8♧ with 10♤ and 9♧ with J♤ from another deck of cards. If we change another card, which card should we change (and to what card) to maximize the probability of ...
Marx's user avatar
  • 33
5 votes
1 answer
158 views

How is calculated the frequency of a pair, a flush of 2 cards, a straight of 2 cards and a straight flush of 2 cards (52 cards, hand of 2, 3, 4, etc)?

Introduction Before starting, I would like to specify a few things: The deck has 52 cards. From 1 (Ace) to 10, J, Q, K, all in four different suits: spades, diamonds, club and hearts. I don't add ...
Enderluck's user avatar
  • 110
2 votes
1 answer
92 views

Finding the probability of a full house in poker with two wild cards

Problem: Suppose that we have a standard poker deck and we add $2$ cards to it. These two cards added are jokers and are considered wild cards. What is the probability of getting a full house? Note: ...
Bob's user avatar
  • 3,796
0 votes
1 answer
67 views

Probability of getting two pairs from a modified deck

In a deck of cards with 52 cards we change clubs 8 with spades 10 and clubs 9 with spades jack from another deck of cards. What is the probability of getting two pairs if you draw 5 cards? In a ...
Marx's user avatar
  • 33
1 vote
2 answers
237 views

What is the probability of four of a kind in poker with wild cards?

Below is a problem I made up and did. Problem: Suppose that we have a standard poker deck and we add $2$ cards to it. These two cards added are jokers and are considered wild cards. What is the ...
Bob's user avatar
  • 3,796
0 votes
2 answers
96 views

poker hand conditional probability

Consider a deck of cards, where the backs are marked in such a way that you can distinguish a pip card (Ace, 2,...,10) from a face card (King, Queen, or Jack). You deal a poker hand to a friend. Given ...
rubik's user avatar
  • 59
0 votes
1 answer
252 views

How to calculate the probability of getting a pair on the flop in Texas Hold 'Em

I'm wondering how exactly I would go about calculating the odds of getting exactly a pair on the flop (so two pairs and three of a kind do not count). I'm assuming that the player's hand is not a ...
Jslater2001's user avatar
0 votes
0 answers
14 views

What is the probability of flopping 2 pair with paired hole cards in Holdem?

I was looking into it and the only thing that I'm not sure is whether in the equation for this probability has to be multiplied by 3 or 2. 48/50 x 3/49 x 44/48 x2 =10.78% Can someone please clarify?
speedy's user avatar
  • 3
0 votes
1 answer
631 views

I draw 7 cards from a standard card deck, what is the probability 5 of them are the same suit?

Apologies for the formatting, I am not familiar with this platform. I believe I have solved it but I looking for assurance. Let X be a random variable indicating the number of cards of the same suit (...
stat_us's user avatar
1 vote
1 answer
156 views

What is the probability of getting exactly two pairs in a poker hand of $7$ cards?

Problem: What is the probability of getting exactly two pairs in a poker hand of $7$ cards? Note: Only $5$ cards count, and the cards that count will be determined by the player holding the cards. ...
Bob's user avatar
  • 3,796
0 votes
1 answer
167 views

What is the probability of hitting 2 pair on the flop with upaired cards in Holdem poker?

I have mainly seen that the probability is 2.02%, but it always somewhere said it does not include if boards pairs. So I was thinking is the probability of getting 2 pairs if board pairs is equal to: ...
speedy's user avatar
  • 3
0 votes
0 answers
42 views

In Texas Hold’em does flipping the river before the turn change the game? [duplicate]

This question has a caveat that the game is played with the community cards dealt prior to the start of the hand, which isn’t standard poker play. The community cards are dealt: burn 1 card, 3 cards ...
Confused's user avatar
3 votes
2 answers
918 views

What is the probability that a five-card poker hand contains all 4 suits?

I know that my answer is wrong but I don't know why it is wrong. What is the probability that a five-card poker hand contains all 4 suits? What I did was I this: $$\frac{C(4,1)\,C(13,1)\,C(3,1)\,C(...
Justin Li's user avatar
1 vote
2 answers
775 views

Probability of getting three of a kind in a Poker hand

I have seen some answers to the question as $$\frac{\displaystyle\binom{13}{1}\binom{4}{3}\binom{12}{2}\binom{4}{1}^2}{\displaystyle\binom{52}{5}} $$ Why don't we use $$\frac{\displaystyle\binom{13}{1}...
TheGreatJRB's user avatar
6 votes
1 answer
617 views

Why is the probability of getting a pair in a five-card poker hand so complicated?

The working-out of this question has really confused me. I know the basics of probability but I don't get the calculations here. I think 13C2 * 4C2 determines the number of possible pairs, and the ...
EH86055's user avatar
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