Questions tagged [planar-graphs]

A planar graph is a graph (in the combinatorial sense) that can be embedded in a plane such that the edges only intersect at vertices. Consider tagging with [tag:combinatorics] and [tag:graph-theory]. For embeddings into higher-genus spaces, use [tag:graph-embeddings].

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Maximum number of vertices with degree three in maximal bipartite planar graphs

A bipartite graph $G$ is a graph where each cycle has an even length. If $G$ can be drawn on the plane without any crossings of edges, $G$ is called planar. $G$ is called maximal planar bipartite if ...
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Inductive proof for statement about product of weights in intro to dimer model

I was reading this review by Kenyon on the dimer model, and there's a lemma at the beginning that I'm struggling to prove. Here's the set-up. We have a finite 2D square lattice graph, bounded by a ...
Mako Strwlkr's user avatar
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An example of Dessin d'Enfants

I'm self-studying the book of Graphs on Surfaces and Their Applications, Lando & Zvonkin. In Sec 2.3, we assume the form of an underlying polynomial in the Fig.2.20 below as $$ f(x) = K \frac{(x - ...
Rowing0914's user avatar
5 votes
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Why does a 3-regular planar graph of diameter 3 have at most 12 vertices?

Today, I saw an interesting exercise on page 224 of the West textbook "Introduction to Graph Theory". 6.1.15. Construct a 3-regular planar graph of diameter 3 with 12 vertices. (Comment: T. ...
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Heptagon is divided into pentagons and hexagons. Prove that there are at least $27$ pentagons in this division.

A heptagon is divided into convex pentagons and convex hexagons in such a way that each vertex of the heptagon is the vertex of at least three polygons of the division. Prove that there are at least $...
thefool's user avatar
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Proof of $e\leq3v-6$ for planar graphs without Euler's formula

For a short talk for an audience not familiar with graph theory I want to give an informal proof that $e\leq3v-6$ holds in all planar graphs with $v>2$ and I don't want to use Euler's formula. My ...
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Concise yet Rigorous Proof: How to Modify It?

The following proposition is standard. Proposition 1. Let $G$ be a graph with a planar drawing $D$ and at least three vertices. Then, $D$ can be extended to a multi planar drawing $D^*$ by adding ...
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Connectivity vs. Simplicity in planar graphs

Let $G$ be a simple plane graph where each face is either a triangle or a quadrilateral. Now, for each quadrilateral face $f$ of $G$, we insert a pair of crossing edges into $f$ to obtain $G'$. For ...
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Maximal planar graphs with minimum independent sets

The lower bound is known to follow immediately from the Four Color Theorem. Theorem 1. If $G$ is a planar graph with order $n$, then $\alpha(G) \geq \frac{n}{4}$. The lower bound in Theorem 1 is sharp....
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How best to model "stream puzzle" games?

A number of puzzle games around the 00s had mechanics based around manipulating streams of objects towards sinks on a grid map, with the level being passed when a certain number of objects had been ...
redroid's user avatar
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Degenerate Schläfli symbols involving 1

I understand that Schläfli symbols with integral elements $\{p,q\}$ both greater than or equal to $2$ represent planar graphs (multigraphs if $p$ is $2$), and these graphs, if finite, represent ...
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The number of surfaces between connected components in higher dimensions

Let $C_1, \ldots, C_K$ be the collection of $K$ disjoint subsets (I'll call them components) of $\mathbb R^d$ so that: Each $C_i$ is connected and open. $\cup_i cl(C_i) = \mathbb R^d$, where $cl$ is ...
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In a planar embedding of a graph, can vertices lie on each other? [closed]

I am wondering if vertices of a planar graph can lie on top of each other in an embedding of the graph. Also, when drawing a picture/representation of the graph, is drawing vertices on top of vertices ...
Alexander D.'s user avatar
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Why is a non-planar graph still non-planar after subdividing it?

A graph $H$ is said to be a subdivision of a graph $G$ if $H$ can be obtained from G by successively deleting an edge in $G$, and replacing that edge with a length 2 path (whose central vertex was not ...
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Can a vertex lie on an edge in a planar graph?

I am wondering if a vertex can lie on an edge in a planar graph- I am not sure if an edge of this vertex is regarded as crossing the edge on which the vertex lies. I have two questions here: Is the ...
Shmuel's user avatar
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Euler's formula doesn't work for null graph?

Given the null graph with no edges or vertices, we have a connected planar graph as no edges cross when this graph is drawn in the plane, and the fact that any two distinct vertices have a path ...
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Are the edges of a planar graph part of its faces? (Graph Theory)

The definition of face I have learned for planar graphs is "a region where any 2 points in it not on $G$ can be connected by a line which doesn't intersect any of the edges of $G$". I am ...
Shmuel's user avatar
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How is the face for a tree graph bounded by any sides at all? (Graph theory) [closed]

I have learnt that every face in a planar graph has sides, and that sides are edges which bound the face clockwise. I am very confused about a few things regarding sides: I am not seeing how the ...
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What is "the plane" in graph theory?

I have learnt that a planar graph is a graph which can be drawn on the plane without any of its edges crossing. What exactly is "the plane"? In plane geometry, we define a plane to be a flat ...
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Dual graph relation to star-mesh duality

I'm confused about the realtionship between dual graphs and the so called star-mesh transformation: https://en.wikipedia.org/wiki/Star-mesh_transform. Take a simple triangle, its dual graph looks like ...
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A graph coloring game of merging subgraphs

A graph coloring game This is a 2-player game played by players $A$ and $B$. A random non-trivial planar connected graph $G(V,E)$ is chosen. Player $A$ sets up the game as follows: Player $A$ ...
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Bound number of loopless multigraphs

Let $d_1,\dots,d_n\geq 0$ be integers and let $G_{d_1,\dots,d_n}$ denote the set of loopless multigraphs with this degree sequence. I want to prove the following bound on the number of such ...
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Number of vertices in spherical embeddings with large stars.

Suppose I am given a spherical embedding of a graph, specifically a triangulation, onto the unit sphere such that all edges are short geodesics (lengths strictly smaller than $\pi$). Let us further ...
spektr's user avatar
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1 answer
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Are Apex graphs always Toroidal?

An Apex graph is a grpah that is either Planar, or can be made planar by removing a single vertex. Are all Apex graphs Toroidal?
blademan9999's user avatar
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Structural characterizations of planar graphs

I'm looking for as many characterizations of planar graphs, preferably those that are more `structural'. Wagner's and Kuratowski's results get close, but the characterizations of Whitney and Maclane ...
Kenneth Goodenough's user avatar
2 votes
1 answer
204 views

4-color coloring game.

Similar to this question. 5-color coloring game. Let there be two players, $𝐴$ and $𝐵$, and a map. They now play a game such that: Player $𝐴$ picks a region and player $𝐵$ colors it such that the ...
blademan9999's user avatar
1 vote
1 answer
50 views

For what values of $n$ $(n\ge 3)$ is the graph $C_n \times P_n$ planar?

First instinct was that maybe the new graph won't be planar for $n=3$ and $n=5$ because then it might contain a subgraph that is isomorphic to $K_3,_3$ or $K_5$, but I am not sure how to prove that. ...
Steve M.'s user avatar
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Generalization of Triangulations in Graph Theory

There are some results on planar triangulations I was trying to generalize to a larger class of graphs. So, what I am looking for is, a set of graphs such that the intersection of this set and the set ...
Keven McFlurry's user avatar
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Suppose a tree graph T with $n\ge 4$ ,and 3 edges $e_1,e_2,e_3$ from its complement tree graph T-.Show that $G = T + e_1 + e_2 +e_3$ is a planar graph

can't seem to find the proof for this problem. I know that a Tree graph has the property: $n = m - 1$ where $n$ is the number vertices and $m$ is the number of edges. Also not sure if the restriction ...
Steve M.'s user avatar
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1 answer
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Showing inequality about number of vertices with ceratin degree for planar graphs

I am currently struggling on showing the following inequality for planar graphs without loops. Let $\delta(G) \geq 3$ and $\tau_i$ be the number of vertices with degree $i$, then: $$ \tau_5 + 2 \tau_4 ...
Raoul Luqué's user avatar
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Related between Kuratowski theorem and any graphs that $\chi(G)\leq 4$ and $\chi(G)\leq 5$

Is there related between Kuratowski's theorem and any graphs that $\chi(G)\leq 4$ and $\chi(G)\leq 5$ (chromatic number)?
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3 votes
1 answer
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Construct a class of maximal planar graphs with exactly 4 vertices of degree 3.

The post is very interesting, and it tells us that any planar graph with at least $4$ vertices has at least $4$ vertices of degree $5$ or less. Recently, I also saw a question on a Chinese forum (...
licheng's user avatar
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e <= 3v - 6 for planar graph question: why does every face (of a planar graph) have to have at least three sides?

Can't we make a face with just two edges(sides) and two vertices? We just connect those two vertices twice each with different edges and we can make a face between the two edges with only two vertices ...
OneMoreGamble's user avatar
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3 answers
82 views

Could there exist a planar graph with the following degrees of vertices: {5, 5, 4, 4, 4, 2} [closed]

I was wondering if a graph existed because I used euler's inequality and it said that theres supposed to be a graph but im having a hard time figuring out what it is. Thank you!
ploop's user avatar
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1 vote
1 answer
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Asymmetric graphs with asymmetric edge-deleted subgraphs

When I say graph, I mean undirected, irreflexive graphs without multiple-edges (sometimes called a simple graph). Call a graph $G$ “asymmetric” if the only automorphism of $G$ is the identity map. For ...
Joe's user avatar
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3 votes
1 answer
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Find segment x on the secant circles below

In the figure determine $'x'$ , knowing that $PM=MQ=4$ and $O$ and $O'$ are centers.(S:$x=4$) I try: $\triangle OQH \sim \triangle OAP \implies \dfrac{HO}{OP} = \dfrac{HQ}{AP} = \dfrac{8+OP}{AO}$ $\...
peta arantes's user avatar
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9 votes
2 answers
138 views

A periodic layout for the Petersen graph

The Petersen graph is a well-known graph with genus $1$, which means it can be drawn without crossings on a torus. Here is one possible embedding of this type. Topologically, we can think of a torus ...
Misha Lavrov's user avatar
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0 answers
20 views

Inverse of image connected component graph labeling

For a given image I one can compute connected components and define a graph structure G on those components. Each connected ...
Danvil's user avatar
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1 vote
2 answers
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Does a maximal planar graph with number of vertices $\ge$ 6 always have a vertex of degree exactly 5?

In a proof of a theorem, my professor wrote that since $G$ is a maximal planar graph with $|V|\ge6$, so, there exists a vertex of degree 5. I know the result that every planar graph has a vertex of ...
Esha's user avatar
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Given a directed graph, can you determine if it can be drawn as a planar graph?

Say a directed graph has loops and has nodes directed towards each other. I would like to know if there is an algorithm for determining if the graph can be drawn as a planar graph.
John Glen's user avatar
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Given several $a_i$-$r$ paths in a planar graph how ``balanced" of a tree rooted at $r$ can I make?

Suppose I am given distinct nodes $a_1,a_2,.., a_l, r$ and several $a_i$-$r$ paths $P_i$ in a planar graph $G$. I wish to construct a tree $T$ connecting $a_1,a_2,.., a_l, r$ that minimizes the ...
Hao S's user avatar
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2 votes
0 answers
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Counting the number of faces of non-connected planar graph

I have a non-connected planar graph with 15 vertices, 20 edges and 3 components. I know the Euler's formula for counting the number of faces in a connected graph, but how do I modify it using the ...
smilos's user avatar
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1 vote
1 answer
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Can we construct a class of planar graphs with minimum degree $5$ (or even $5$-connected planar graphs) with diameter 3?

The diameter of graph is the maximum distance between the pair of vertices. From the article we know that there is no planar graph of diameter 2 with minimal degree 5. (Thank kabenyuk for informing ...
licheng's user avatar
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1 vote
3 answers
98 views

The connectedness of dual graph

Prove: if a planar graph $G$ is $k$-vertex-connected, then so do its dual $G^{\ast}$ for $k=2,3$. And find a counterexample for $k=4$. I only have a vague idea for $k=2$: if $G$ has a cut vertex, then ...
Isomorphism's user avatar
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Overlapping models/minors of planar graphs

Suppose we are given a planar graph $G$ and connected subgraphs $G_1,G_2,..,G_l$ of $G$ such that each $G_i$ intersects (shares a node with) constant many other $G_j$ on average. Construct a graph $H$ ...
Hao S's user avatar
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0 answers
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Question about "growing layers of a planar graphs"

Given a planar graph $G$ k nodes $S$ of $G$ construct "layers" $L_i$ for $i=0,1,...$ as follows $L_0=S$, having constructed layers $L_0,L_1,..,L_i$ layer $L_{i+1}$ consists of those nodes ...
Hao S's user avatar
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Let $n\geq 3$. Is there a connected, planar, bipartite graph with $n$ regions and $n$ vertices?

The answer given is that according to a Corollary of Euler’s formula (Corollary 3 Section 10.7), such a graph has at most $2n − 4$ edges. Applying this to Euler’s formula ($r = m − n + 2$), there are ...
toru's user avatar
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0 answers
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Queue number above 2 for planar graphs?

Are there any known planar graphs with queue number greater than $2$? The queue number of a graph counts the minimum number of subsets that the edges must be divided into to avoid all nested pairs of ...
isaacg's user avatar
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2 votes
0 answers
60 views

Does a quadrangulation with minimum degree $3$ contain either a $(3,3)$ edge or a $(3,4)$ edge$?$

A simple graph $G$ is a quadrangulation of the plane if it can be embedded in the plane in such a way that all faces are quadrangles. We say an edge $e=(uv)$ is an $(a,b)$-edge if the degrees of the ...
licheng's user avatar
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2 votes
1 answer
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Argue that in a planar graph on n nodes there is an independent set of at least n/8 nodes, each of degree at most 11.

I am having troubles with this question. Seems non-trivial as I see it. The tightest lower-bound I could reach was "at least n/12" number of nodes in the independent set, with the assumption ...
mark_52's user avatar
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