Questions tagged [perfect-powers]

A perfect power is a positive integer that can be expressed as an integer power of another positive integer. This tag should only be used when having in mind an arbitrary perfect power (as opposed to a specific one, like a perfect square, a perfect cube, etc.).

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Given $a,b$ find perfect cube solutions to $a+bx, \forall x\in\mathbb{N}$ [closed]

Suppose we are given $a,b\in\mathbb{N}$ find $x\in\mathbb{N}: \exists k\in\mathbb{N}: a+bx=k^3$.
Frank Liu's user avatar
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Can $!1+!2+!3+\cdots+!n$ be a perfect power?

Can $!1+!2+!3+\cdots+!n$ be a perfect power if $n\geq3$? Note that $!n$ is a subfactorial. I do know that $1!+2!+3+\cdots+n!$ is only a perfect power if $n=1, 3$, since when $n\geq9, 1!+2!+3!+\cdots+9!...
Thirdy Yabata's user avatar
4 votes
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Is $1105$ the only Poulet-number of the form $2^a+3^b$?

Conjecture : $1105$ is the only Poulet-number that can be written in the form $2^a+3^b$ with positive integers $a,b$ A Poulet-number is a composite number $N$ satisfying the congruence $2^{N-1}\equiv ...
Peter's user avatar
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Is $S_n=1!^{1!}+2!^{2!}+3!^{3!}+\cdots+n!^{n!}$ a perfect power if $n\geq2$

Is $S_n=1!^{1!}+2!^{2!}+3!^{3!}+\cdots+n!^{n!}$ a perfect power when $n\geq2$? I know that: $S_n\equiv2\pmod{3}$ if $n\geq2$, so $1!^{1!}+2!^{2!}+3!^{3!}+\cdots+n!^{n!}$ is never a perfect square if $...
Thirdy Yabata's user avatar
6 votes
0 answers
134 views

For which $x,n$ is the finite geometric series a perfect power?

Let $x,n,y,q$ be integers greater than one with $n>2$ as well (this is to avoid trivial solutions). The closed form for the geometric series $S(x,n)=\sum_{k=0}^{n-1} x^k$ is $\frac{x^{n}-1}{x-1}$. ...
Integrand's user avatar
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Is $7$ the largest possible value of $n$ for which $(1!+2!+3!+…n!)+16$ is a perfect power?

Is $7$ the largest possible value of $n$ for which $(1!+2!+3!+…n!)+16$ is a perfect power? I noticed that $(7!+6!+5!+4!+3!+2!+1!)+16=77^2$ is a perfect power, and I don’t know if that is the largest ...
Thirdy Yabata's user avatar
2 votes
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262 views

Can $(5^k+1)(2^k)$ be a perfect power?

Can $(5^k+1)(2^k)$ be a perfect power? I noticed that $(5^k+1)(2^k)=(10^k+2^k)$, and this cannot be a perfect square since the last digit of $(5^k+1)(2^k)$ is either $2$, or $8$ when $k$ is odd, and ...
Thirdy Yabata's user avatar
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Let $n \in \mathbb{Z}$. Prove $n^6 = k^9 = m^4$ and Let $a = n^6$ $\iff$ $a$ must be a perfect $36$-th power. [duplicate]

Prove $n^6 = k^9 = m^4$ and Let $a = n^6$ $\iff$ $a$ must be a perfect $36$-th power.
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Is there any perfect power in the sequence $12,123,1234,12345,...$?

Inspired from the question Is there any perfect square in the sequence $12,123,1234,12345,...$?, there is no perfect square other than $1$ in the sequence of Smarandache numbers. But I wonder if are ...
Thirdy Yabata's user avatar
0 votes
1 answer
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Specific Prime Numbers Chain proofs of maximum length limits.

Considering Prime Numbers $p\in P$ such that $(p^2+4)\in P, (p^2+4)^2+4\in P, ((p^2+4)^2+4)^2+4\in P, (((p^2+4)^2+4)^2+4)^2+4\in P,((((p^2+4)^2+4)^2+4)^2+4)^2+4\in P$, seems to be either very rare, or ...
Eugen's user avatar
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Congruence equation $v^q \equiv a \pmod p $

I am reading a text on number theory, but I am confused about the following. Let $a$ be neither $\pm 1$ nor a perfect square. Suppose $h$ is the largest positive integer such that $a$ is a perfect $h$...
hmm1's user avatar
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The numbers from $11111$ to $99999$ are written in a random order, one after another, forming a single number. Prove that it cannot be a power of $2$.

I found the following problem in a book with advanced math problems for 6th grade that I cannot solve: All the numbers from $11111$ to $99999$ are written in a random order, one after another, thus ...
Marius Bancila's user avatar
1 vote
2 answers
218 views

When is $63\cdot2^x\pm1$ a perfect power?

When is $63\cdot2^x\pm1$ a perfect power? I noticed that: $63\cdot2^0+1=2^6$ $63\cdot2^1-1=5^3$ $63\cdot2^8+1=127^2$ Other than $0,1,8$, are there any integer values of $x$ such that $63\cdot2^x\pm1$ ...
Thirdy Yabata's user avatar
34 votes
2 answers
2k views

Can $1!^2+2!^2+3!^2+\dots+n!^2$ be a perfect power when $n\geq2$?

I know that $S_n:=1!^2+2!^2+3!^2+\dots+n!^2$ cannot be a perfect square because it is equal to $2\pmod{3}$ and it is never a perfect cube because it is equal to $5\pmod{9}$, but can $S_n$ be a higher ...
Thirdy Yabata's user avatar
10 votes
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Can we always find arbitrarily close powers of $a$ and $b$?

This post was motivated by this other post. I'm aware of Pillai's conjecture (yet to be proven) which states that the gaps in the sequence of perfect powers tend to infinity. However, what happens if ...
Alma Arjuna's user avatar
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2 votes
1 answer
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How to prove that $N!+p(N)$ can't be a perfect power, where $p(N)$ is the $N^{th}$ prime?

I've attempted to solve this problem. I can only conclude that if $N!+p(N)=x^y$, since $p(N)>N$, $x$ must be formed by primes greater than $N$ except for $p(N)$. I don't know how to go on. By ...
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Is there a product of $k$ consecutive integers which is one more (or less) than a perfect cube?

I've seen this question with numerous proofs on the product of four consecutive integers being one less than a perfect square. Then I've started to wonder: how many consecutive integers does one need ...
Rusurano's user avatar
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1 answer
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Can $n!+16$ be a perfect square when $n\geq5$?

Can $n!+16$ be a perfect square? I think $n!+16$ can be a perfect square, since $n!+16$ is $0 \mod 4$, and always $1 \mod 3$ ( when n is $> 5$), and always $5 \mod 11$ ( when $n$ is $> 11$). But ...
Thirdy Yabata's user avatar
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0 answers
159 views

Can $300$…$04$ be a perfect square? [duplicate]

$300…04$ is divisible by $4$ and always $1$ mod $3$. Sometimes, $300$…$04$ is $1$ mod $11$, which is a quadratic residue modulo $11$. But when I tried to check if there is any perfect square form of $...
Thirdy Yabata's user avatar
1 vote
4 answers
524 views

Can $\,9\!\cdot\!10^n+4\,$ be a perfect square? [duplicate]

I think $\,9\!\cdot\!10^n+4\,$ can be a perfect square, since it is $0 \pmod 4$ (a quadratic residue modulo $4$), and $1 \pmod 3$ (also a quadratic residue modulo $3$). But when I tried to find if $\;...
Thirdy Yabata's user avatar
3 votes
1 answer
119 views

$(a^n-1)(b^n-1)$ can't be a square for all $n$ unless $ab$ is a square

Let $a,b$ be positive integers $>1$ such that $(a^n-1)(b^n-1)$ is a square for all $n\ge 1$. Prove that $ab$ is a perfect square. I'm not asking for a solution to this problem because I already ...
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Is there an analogue to Bertrand's Postulate for primes for perfect powers?

Is there an analogue to Bertrand's Postulate for primes for perfect powers? Bertrand's Postulate: $\forall x \gt 1 \in \mathbb{Z}, \exists p \in \mathbb{P}$ such that $x < p < 2x$. For perfect ...
vvg's user avatar
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0 votes
1 answer
23 views

Finding the smallest perfect power in a range

Given a range $[a, b]$, how does one find the smallest perfect power contained in the range? i.e., find $a \le k^m \le b$ where $a, b \in \mathbb{R_{\ge 0}}$ and $k, m \in \mathbb{Z_{\ge 0}}, m \ge 2$....
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3 votes
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How to make graphs that avoid certain sub-graphs and have as many edges as possible?

The other day, I needed to create a graph with $10$ vertices, $16$ edges, and which didn't have a loop of four vertices, $C_4$, or a daisy-chain of three $3$-cliques (see picture) as sub-graphs. Turns ...
Chris Wolird's user avatar
11 votes
2 answers
536 views

Potential solution to Sloane's "Powers of 2" problem?

Neil Sloane gave a problem in a recent Numberphile video here. It seems like there's a solution. But Sloane said it's unsolved and very hard so maybe not. But I'll try to outline the idea for the ...
Chris Wolird's user avatar
11 votes
2 answers
389 views

Can $5^n+6^n+10^n$ be a perfect power?

Related to this question: Can $f(n)=5^n+6^n+10^n$ with a non-negative integer $n$ be a perfect power ? It is not a perfect power for $0\le n\le 10^5$ Analysis modulo $3$ reveals that a perfect ...
Peter's user avatar
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2 votes
1 answer
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Finding three perfect complex powers with equal norm and cancelling imaginary parts

The Problem I've been curious about finding 3 distinct Gaussian integers with equal norm whose imaginary parts cancel out. So $\alpha, \beta, \gamma\in\mathbb{Z}[i]$ with $|\alpha|=|\beta|=|\gamma|$ ...
WhiteStoneJazz's user avatar
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29 views

Formula for working out the greatest power that another number is divisible by

Is there a formula to answer the question What is the highest value of $n$ where it is true that $b^n$ is a factor of $x$? where $b$ and $x$ are known positive integers and $n$ is an unknown non-...
CJ Dennis's user avatar
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To prove that irrational powers of 1 is equal to 1 [closed]

It is easy to prove that if 1 is raised to any power of a rational number ( say $x$), then : $(1)^x = (1)^{p/q}$ (because $x$ can be expressed as $p/q$ where $p$ and $q$ are integers except $q≠0$). ...
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1 vote
1 answer
276 views

Prove that we can express $n^k$ as a sum of $n$ consecutive odd natural numbers

Prove that $\forall n \in \mathbb{N},$ we can express $n^k$ where $k \geq2$ is an integer, as a sum of $n$ consecutive odd numbers. My Solution - Let $2m+1$ be the first odd number , $m \geq 0 , m \...
Aleph's user avatar
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0 answers
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Number Theory Problem: Find a perfect power k^m > 1 where k, m, k^m do not contain 2 in their decimal digits, nor do share any decimal digit.

Find a perfect power k^m > 1 where k, m, k^m do not contain 2 in their decimal digits, nor do share any decimal digit, even if k^m might possibly be expressed in more than one way for some value, e....
Tamas Nagy's user avatar
3 votes
3 answers
427 views

How close is an odd power of two to a perfect square?

Let $n \ge 1$ be an odd natural number. Define $$f(n)=\min \{\,\, |k| \,\,\, | \, k+2^n \,\,\,\text{is a square}\,\,,k \in \mathbb{Z}\}.$$ That is $f(n)$ measures how close is the power $2^n$ to a ...
Asaf Shachar's user avatar
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5 votes
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Self-powers residues

Let $a$, $x$ and $n$ three positive integers such that $\gcd(a,n)=1$ and $x^x=a \mod n^n$. Prove that we can find a positive integer $y$ such that $y^y=a\mod n^{n^n}$. This is what I managed to prove ...
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1 vote
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Whole number solutions to $2n^4+1=m^2$. [duplicate]

What are the whole numbers for which two times the forth power of it plus one is a square? In mathematical notation: $$2n^4+1=m^2;m,n\in\mathbb{Z}$$ My Observations: because of the squares, all ...
Saha's user avatar
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Fixed point power function for fractional values

I am using below Matlab code to calculate power function i.e. without using built-in function. My requirement is - What improvement/ suggestion make the below function support fractional base and ...
Coder's user avatar
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I can't understand this solution with $\equiv$

I found a solution for finding the units digit of a sum. It said that the $\equiv$ means "has the same units digit as". Using this, they said that $3^1+3^3+3^5+...+3^{2009} \equiv 3+7+3+...+...
Kamal Saleh's user avatar
1 vote
1 answer
178 views

About the diophantine equation $x^3+y^3=z^8$

After solving the exercise The equation $x^n+y^n=z^{n+1}$ has infinite solutions in the positive integers. I realized that this can be easily generalized to If $m\equiv 1 \pmod n$, the equation $x^...
jjagmath's user avatar
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1 vote
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Is it the case that for every $n$, $m$, there is an integer expressible as a sum of $m$ distinct positive integer squares in $n$ distinct ways?

I am not a mathematician, but I learn from various sources that we know that, for every n, there is an integer that can be expressed as a sum of two positive integer squares in n distinct ways, and ...
Daniel Hill's user avatar
2 votes
0 answers
112 views

Find all positive integers $x,y$ such that $(x+y)(xy+1)$ is a power of $2$ [duplicate]

Find all positive integers $x,y$ such that $(x+y)(xy+1)$ is a power of $2$ It is clear that as we are given a factorisation of the power of two, both of those terms have to be powers of two. $x+y$ is ...
fabigatmath's user avatar
0 votes
1 answer
75 views

Find all triples $(a,b,c)$ giving $3$ powers of $3$ simultaneously [closed]

For which triples $(a,b,c)$ of positive integers are $2a+b,2b+c,2c+a$ all powers of $3$ ? I found out that $a, b, c$ have the same remainder after division by $3$.
Heipl's user avatar
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4 votes
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Squareful Part of a Family of Numbers

For any integer $x$, let $f(x)=64x^6-27$. Now, write $f(x)=g(x)h(x)$, where $g(x)$ is the squarefree part of $f(x)$ and $h(x)$ is its squarefull (powerful) part. For example, $f(5)=13^2\cdot 61\cdot ...
Jean's user avatar
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3 votes
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Consecutive prime powers that are not prime

I am looking for consecutive entries $(a_k,a_{k+1})$ in the sequence of prime powers $$(a_n)=(2,3,2^2,5,7,2^3,3^2,11,13,2^4,17,19,23,5^2,3^3,29,31,2^5\cdots)$$ such that neither $a_k$ nor $a_{k+1}$ ...
Valerio's user avatar
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Does there exist a positive integer $k$ and an irreducible polynomial $P$ of degree at least $2$ such that $P$ is a power of $k$ infinitely often?

Does there exist a positive integer $n\in\mathbb{Z}$ and an irreducible polynomial $P\in\mathbb{Z}[X]$ of degree at least $2$ such that there are infinitely many pairs of positive integers $(m,k)$ ...
Mastrem's user avatar
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0 votes
2 answers
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How well does this method of checking if an integer $N$ is a square perform?

The method is based on the following observation: an integer $N=n^2$ is a square which can also be written as $N=n^2=(a+b)^2=a^2+2ab+b^2$ with: $a=(n−1)/2$ $b=(n+1)/2$ We need to consider two cases, $...
user25406's user avatar
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Infinitely many $n$ which divide $3^{6n-1} - 1$

Are there infinitely many positive integers $n$ such that $n$ divides $3^{6n-1} - 1$? I guess the answer should be positive and the only reasonable idea I have is to consider $n = 3^k - 1$ since if $k$...
DesmondMiles's user avatar
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2 votes
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Are there solutions to $a^5=b^5+c^5+d^5$ where $a,b,c,d \in \mathbb{N}$?

This is a generalization of Fermat's last theorem which states that there are no solutions to: $$a^n=b^n+c^n : a,b,c,n \in \mathbb{N}, n>2$$ A generalization of Fermat's last theorem, Euler powers ...
SebMagee's user avatar
0 votes
1 answer
38 views

Proof verification of a question associated with perfect cubes

(Poland) For positive integers $a \leq b$, do the following items: (a) Show that $b^3 < b^3 + 6ab + 1 < (b+2)^3$. (b) Find all such a and b for which both $a^3 + 6ab +1 $ and $b^3 + 6ab + 1$ are ...
Edmund Blackadder's user avatar
7 votes
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80 views

Are there any primitive examples besides 56,65 where the sum of a number's cube and its digital reverse's cubes is square?

I saw a question a while back which asked (paraphrased): how many examples exist of the form $a^n + b^n = c^2$ where $b$ is $a$'s digits in reverse, $n \geq 2$, and $a,b,c$ are coprime. For $n = 2$, ...
abnew123's user avatar
3 votes
1 answer
105 views

Are there positive integers $a,b,c$ such that both $2a(b^c+1),2a(b^c-1)$ are perfect powers?

Are there positive intgers $a,b,c$ such that both $2a(b^c+1),2a(b^c-1)$ are perfect powers? My research We have $2a(b^c+1)-2a(b^c-1)=4a$, so I looked at perfect powers which have a multiple of $4$ as ...
Kaira's user avatar
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9 votes
2 answers
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Does every odd prime power divide a number of the form $\ n^{n-1}+n-1\ $?

A conjecture motivated by a factoring project : For every odd prime power $\ P\ $ , there is an integer $\ n>1\ $ such that $\ P\mid n^{n-1}+n-1\ $. In other words , every odd prime power divides ...
Peter's user avatar
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