Questions tagged [homological-algebra]

Homological algebra studies homology and cohomology groups in a general algebraic setting, that of chains of vector spaces or modules with composable maps which compose to zero. These groups furnish useful invariants of the original chains.

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its related to mathematical logics

Which of the following are true statements? (1) (∃x ∈ N)(∃y ∈ N)(x + y ̸ = x · y). (2) (∃x ∈ N)(∃y ∈ N)(∃z ∈ N)(x − (y − z) ̸ = (x − y) − z). (3) (∀x ∈ {0, 1})(∀y ∈ {0, 1})(x2 + y2 + xy = (x + y)2).
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Show that if $\operatorname{Hom}_{R}(-,D)$ is exact then the original sequence $0 \to L \to M \to N \to 0$ is *split* exact.

I want to show that if for all modules $D$ the sequence $$0 \to \operatorname{Hom}_{R}(N,D) \xrightarrow{\varphi^*} \operatorname{Hom}_{R}(M,D) \xrightarrow{\psi^*} \operatorname{Hom}_{R}(L,D) \to 0$$...
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Projective dimension of the residue field

For $R$ a ring and $M$ a module, denote the projective dimension of $M$ over $R$ by $pd(M)$. We have the following: Lemma (Matsumura Commutative ring theory section 19 lemma 1). Let $(R,m,k)$ be a ...
Countable's user avatar
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Projective-injective modules over $k[x]$

I am looking at graded $k[x]$-modules. I am also interested in the subcategory of modules $M$ all whose graded components are finite dimensional, but that's an optional restriction. In either case, I ...
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Graded Betti numbers of monomial ideals and inclusions

Let $I$ and $J$ be two monomial ideals in some polynomial ring $S=k[X_1,...,X_n]$. Furthermore, assume that $G(I)\subseteq G(J)$, where $G(I)$ denotes the minimal set of monomial generators of $I$, ...
Diego Parodi's user avatar
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Graded-commutativity of cup product: Non-commuative coefficient ring

For $R$ a commutative ring and $X$ a topological space the cup product on the singular cohomology $H^{\ast}(X)$ is graded commutative. I have a question about the proof of this claim. Some definitions ...
Margaret's user avatar
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A question about tensor products of fin. gen. proj. modules and module maps

Consider non-zero bimodules $M,N$, and $P$, over a ring $R$, that ar additionally assumed to be finitely-generated and projective as left $R$-modules. Take a bimodule map $f:N \to P$, does it hold ...
Fantas Anadolou's user avatar
1 vote
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Each $(R,S)$-bimodule is a left $R \otimes_k S^{op}$-module

I am trying to understand and fill the gaps of Rotman's proof (in his homological algebra text). This approach is different from this post ("Post 1") and is more complete than this one (&...
IsaacR24's user avatar
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What are some examples of injective sheaves?

Injective objects in the category of abelian groups are precisely the divisible groups. However, despite using injective resolutions of sheaves everywhere, I realized that I did not know a single ...
Anthony Lee's user avatar
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$\mathbb{Z}[u,v]/(u^2+u-v^3+v)$ is torsion free over $\mathbb{Z}$?

Literally, $B:=\mathbb{Z}[u,v]/(u^2+u-v^3+v)$ is torsion free over $\mathbb{Z}$? Note that https://en.wikipedia.org/wiki/Torsion-free_module : from contents in the 'Examples of torsion-free modules' ...
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Injective object in category $\mathcal{K}$, which has an object $a$ and $\text{Hom}(a,a) = S $ is a semigroup with unit.

We consider the category $\mathcal{K}$ with an element $a$ and $\text{Hom}(a,a) = S$, where $S$ is a semigroup with unit. Is $a$ an injective object of $\mathcal{K}$, if $S = \{ 1,\alpha, \alpha^2\}$ ...
naan2224's user avatar
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Equivalences of categories of complexes of modules

Let $k$ be an algebraically closed field of characteristic $0$. Let $R, S$ be two commutative $k$-algebras. Let $\operatorname{Ch}(R), \operatorname{Ch}(S)$ be the categories of complexes of $R$-...
Walterfield's user avatar
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Products in the category R-Mod

I have already shown that Ab is an Abelian category, in particular it has finite products. Using this, I want to show that R-Mod has finite products. I feel that what I have done makes sense, but I am ...
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Ring with IBN and isomorphic free modules

This is problem 2.26(iii) in Rotman's Homological Algebra. 1. Problem 2.26(iii) (R a ring with IBN) 2. Partial Proof Let $W \subset X$ be finite and define $$W' = \{b \in B : \text{supp}(b) \subset W ...
IsaacR24's user avatar
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Duality in cohomology of bialgebras

Let $A$ be a finite dimensional bialgebra over a field $k$. Then $A^\vee=\mathrm{Hom}_k(A,k)$ is a bialgebra. Assume that $A$ and $A^\vee$ are local rings with commutative residue fields isomorphic to ...
Ben S.'s user avatar
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4 votes
1 answer
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Geometric interpretation of a generalized Euler sequence

Although similar arguments work for $\mathbb P^n$ for any $n$, let us deal with $X=\mathbb P^1_k$ for simplicity. Recall there is a so-called Euler sequence on $X$ (twisted by $\mathcal O_X(1)$): $$ 0 ...
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$Hom_\mathbb Z$ and direct products

This is problem 2.25(ii) from Rotman's Homological Algebra Text. 1. Problem Let $p$ be a prime, $B_n$ be a cycle group of order $p^n$, and $A = \bigoplus_{n=1}^\infty B_n$. Show that $$ \mathcal S := ...
IsaacR24's user avatar
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Example about endomorphism ring of an indecomposable object, which have non-trivial idempotent element in an additive category.

Recently I read some about Krull-Remak-Schmidt category. If $A$ is an additive category in which every idempotent splits, every object is the biproduct of finitely many indecomposable objects and the ...
Well's user avatar
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Special case of Snake's Lemma - Neukirch Proposition 12.9

I was wondering how Neukirch gets in his Proposition 12.9 (see http://www.math.toronto.edu/~ila/Neukirch_Algebraic_number_theory.pdf) from the snake-lemma long exact sequence to his claimed sequence. ...
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Enveloping algebra of an algebra essentially of finite type (Weibel 9.4.5)

Let $k$ be a commutative Noetherian ring and $R$ be an algebra essentially of finite type (that is, $R$ is a commutative $k$-algebra and it is a localization of a finitely generated $k$-algebra). In ...
Jasmine Guan's user avatar
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Beginner's guide on homological algebra for commutative ring settings [duplicate]

At the moment, I'm a masters student, and I find commutative algebra to be pretty fascinating. The first seven chapters of "Introduction to Commutative Algebra" by Atiyah & Macdonald, &...
Pritam Roy's user avatar
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Third cohomology of a group

I'm familiar with two primary ways to discuss the n$^{th}$ cohomology of groups with coefficients in an abelian group $A$: (1) Through the exploration of n-fold extensions. (2) By examining the map $...
MANI's user avatar
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1 answer
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Modules over the ring $\mathbb{F}_p[C_p]\cong \mathbb{F}_p[X]/(x^p-1)$

I would like to understand the category of modules over the group algebra $\mathbb{F}_p[C_p]\cong\mathbb{F}_p[X]/(x^p-1)$. I am interested in computing the group cohomology of $C_p$ with coefficient ...
Dog_69's user avatar
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2 votes
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Webeil's Intro to Homological Algebra: does theorem 10.6.3 implicitly reindex cochain complexes to chain complexes?

Let $R$ be a ring, let $\mathbf{D^-(R-mod)}$ denote the derived category of bounded above cochain complexes of $R$-modules, and consider the total tensor product functor $$ \otimes_R^\mathbf{L}: \...
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Example 2.2 in Rotman's Homological Algebra Text

1. Example 2.2 (excerpt) Example 2.2. Let $G$ be a finite group and let $k$ be a commutative ring. The group ring is the set of all functions $\alpha : G \to k$ made into a ring with pointwise ...
IsaacR24's user avatar
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Commutative diagrams in Opposite Category

I am working on the kernels and co-kernels of morphisms in categories with zero objects. I came across the following: $(C,j:B\to C)$ is a cokernel of $f\in \text{Hom}_{\mathcal{C}}(A,B)$ $\iff$ $(C,j^{...
frelg's user avatar
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0 answers
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mapping cone and derived functor

Let $F:\mathcal{C}\rightarrow \mathcal{D}$ be a left exact functor between abelian categories. If $f:A\to B$ is a morphism in $D^+(\mathcal{C})$, do we have $$\operatorname{Cone}(\operatorname{R}F(A)\...
Yijun Yuan's user avatar
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Trouble understanding torsion

I'm reading this paper. In definition 6.1.2 it is mentioned that $H_n(G;A) \cong \text{Tor}_n^{\mathbb{Z}G}(\mathbb{Z}, A)$ (for all $n=0, 1, 2, ...$). What exactly is meant by the right-hand side? I'...
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$\operatorname{Tor}^{\mathbb{Z}}_1(-,-)$ on finite abelian groups is not right exact?

In his answer here Martin Brandenburg claims that the Tor functor $\operatorname{Tor}^{\mathbb{Z}}_1(-,-)$ in the category of finite abelian groups is not right exact in neither argument. Since Tor is ...
Peter's user avatar
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Stallings' Theorem

I am trying to understand Stallings' Theorem for lower central series. Here is the statement: Say we have groups $A, B$ with lower central series $A=A_1, A_2, ...$ and $B=B_1, B_2, ...$ respectively. ...
JMM's user avatar
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Category Theory and Cardinality

This is a very basic question from Rotman's Homological Algebra text. I think the issue is that I don't know how to rigorously talk about cardinality. Problem If $\mathcal A$ is a small category (...
IsaacR24's user avatar
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0 answers
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Acyclicity of co-chain complexes in terms of quasi-isomorphisms.

Weibel gives equivalent conditions for acyclicity of chain complexes, one of which is that the chain complex map $0\to C_.$ is a quasi-isomorphism (i.e. $H_n(0)=0\to H_n(C_.)$ is an isomorphism). ...
frelg's user avatar
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1 answer
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Corollary to Yoneda Lemma

I'm working from Rotman's Homological Algebra text. There's just one detail of the Corollary that I don't follow. 1. Yoneda Lemma Theorem 1.17 (Yoneda Lemma). Let $\mathcal{C}$ be a category, let $A \...
IsaacR24's user avatar
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1 vote
1 answer
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Calculating a specific example of a simplicial resolution of an algebra

In the Stacks Project Tag 09D4, there's an explicit description of a simplicial resolution \begin{align*} P_{2}\to P_{1}\to P_{0} \end{align*} of an $A$-algebra $B$. I am trying to follow this ...
Eric's user avatar
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1 vote
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Basic confusion about $Tor_n$ and projective resolutions

Osborne's text has the below basic example. 1. Example 9 $R = \mathbb Z_4$, $A = B = \mathbb Z_2$ A projective resolution of $\mathbb Z_2$ is $$ \cdots \rightarrow \mathbb Z_4 \xrightarrow{\times 2} \...
IsaacR24's user avatar
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How to construct $\delta^i$ morphism for right derived functors?

Suppose $F: \mathcal{A} \to \mathcal{B}$ is a left-exact functor between abelian categories. Assume $\mathcal{A}$ has enough injectives. I want to prove the following: For every short exact sequence $...
Anthony Lee's user avatar
2 votes
0 answers
40 views

Resolution for exterior power of a quotient

Let us assume that we have exact sequence of vector spaces: $$0\to U\to V\to W\to 0.$$ We can think of $0\to U\to V$ as a resolution of $W$. Can we construct some canonical resolution of $\Lambda^n W$...
Galois group's user avatar
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0 answers
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Proof regarding when left exact functors are $\delta$-functors

Here is the theorem I am trying to prove: $\mathcal{A}$ and $\mathcal{B}$ are abelian categories. Suppose $F: \mathcal{A} \to \mathcal{B}$ is a left exact functor. If $\mathcal{A}$ has enough ...
Anthony Lee's user avatar
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0 answers
24 views

Tor-dimension of $A/(a)\otimes_k B$, where $A$ and $B$ are Dedekind domains

Let $A$ and $B$ be two Dedekind domains which contain a field $k$ which is algebraically closed in both $A$ and $B$. Let $a$ be a non zero element in $A$. What is the Tor-dimension of $A\otimes_k B$? ...
Stabilo's user avatar
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1 vote
1 answer
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Right derived functors are additive

I am trying to prove the following statement: Let $F: \mathcal{A} \to \mathcal{B}$ be a left-exact functor between abelian categories. Suppose $\mathcal{A}$ has enough injectives. Then the right ...
Anthony Lee's user avatar
8 votes
0 answers
93 views

Alexander-Whitney map gives a coalgebra?

Let $R$ be a unital ring with multiplication $\mu\colon R\otimes R \rightarrow R$. Consider the category $\mathcal{Ch}(R-\text{mod})$ of chain complexes of $R$-modules. This category becomes a ...
Margaret's user avatar
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1 vote
1 answer
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Does the inclusion map $\iota: \mathbb{Z}\rightarrow \mathbb{R}$ induce an inclusion of co/homology groups?

Let $M$ be a smooth $n$-manifold, and $\iota: \mathbb{Z}\hookrightarrow \mathbb{R}$ be the natural inclusion homomorphism of abelian groups. Then, it is easy to check that we obtain a well defined ...
Chris's user avatar
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0 answers
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Question on Proof of Splitting Lemma for Modules

The setup of the question is as follows. Let the following be a short exact sequence of modules: $$ 0 \rightarrow A \xrightarrow{i} B \xrightarrow{p} C \rightarrow 0, $$ and let $r: B\to A$ be a map ...
pyridoxal_trigeminus's user avatar
2 votes
0 answers
79 views

Why is the Yoneda product sometimes called cup product?

In algebraic topology there is the cup product, which endows the direct sum of (singular) cohomology groups with the structure of an associative, graded-commutative, unital ring. Given an associative, ...
Margaret's user avatar
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1 vote
1 answer
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Prove the mod 2 Steenrod algebra has counit

Edit: $\epsilon$ must send $Sq^i$ to $0$ since it is the case where $\mathcal{A}_2$ is a graded algebra. The Wikipedia page presents the answer itself. I'm trying to show that the mod $2$ Steenrod ...
withoutfeather's user avatar
0 votes
0 answers
16 views

Term-wise added regular sequence

Suppose $k$ is a field. Suppose $f_1,\cdots,f_r\in k[x_1,\cdots,x_n]$ is a regular sequence, and $g_1,\cdots,g_r\in k[y_1,\cdots,y_m]$ is a sequence, where $x_i$ and $y_j$ are different symbols. It ...
Guanyu Li's user avatar
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3 votes
1 answer
57 views

Abelian group as second cohomology group of a pair G,M

I'm currently studying group cohomology and in particular group extension; I'm trying to figure out a solution to the following problem: let A an abelian group, is possible to find a group G and a G-...
Lorenzo Ferraiuolo's user avatar
1 vote
0 answers
37 views

Leray spectral sequence degenerate Case Hartshorne exercise III.8.1

In Hartshorne III.8.1 has the following exercise: 8.1. Let $f: X \rightarrow Y$ be a continuous map of topological spaces. Let $\mathscr{F}$ be a sheaf of abelian groups on $X$, and assume that $R^i ...
yi li's user avatar
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2 votes
0 answers
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Natural isomorphism on homology implies natural chain homotopy equivalence?

Let $F,G: C \to \mathrm{Ch}(\mathbb{Z}\textrm{-free})$ be two functors, where $C$ is an arbitrary category and $\mathrm{Ch}(\mathbb{Z}-free)$ is the category of chain complexes of free abelian groups. ...
David E's user avatar
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28 votes
1 answer
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Homology in a picture? (Is this picture just metaphorical, or a rigorous example that can be formalized?)

A post-doc colleague showed me this picture and said: going from the diagram No.2 to No.3 and to No.4 is taking the homology. I did not quite understand this comment. For me, if I take simplicial ...
gwynneth-m.sc.'s user avatar

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