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Questions tagged [congruences-geometry]

For questions about congruent geometric figures, e.g., determining whether one figure is congruent to another.

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Simple request for help with geometric transformations and a problem I have.

The question I have a problem where I have been given four options, but as far as I can tell, none of them are correct. Can someone help me understand the process of proving similarity? So to my ...
Aden's user avatar
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1 answer
37 views

reflexive property of congruence

While exploring basic geometry with my artist friend, she raised a question that neither of us could answer satisfactorily. Until today I thought that Hilbert's axiomatization of Euclidean geometry is ...
Ehsan Amini's user avatar
10 votes
2 answers
244 views

Proving 2 triangles are congruent

Given $\Delta ABC, \Delta A'B'C'$ s.t $\widehat{BAC}=\widehat{B'A'C'}, BC=B'C', AD=A'D'$ $(AD, A'D'$ are internal bisectors of $\widehat{BAC}, \widehat{B'A'C'}$ respectively). Prove that $\Delta ABC=\...
Harry's user avatar
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How to prove the SSS triangle congruence without isosceles triangles or circles?

The SSS triangle congruence is the following theorem from elementary geometry: If three sides of a triangle are equal to the three sides of another triangle, then the two triangles are congruent. ...
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How to define congruent angles without geometric transformations or measures?

I'm trying to build a proof of triangle SAS congruence (see the existing proof I know of) that does not base on geometric transformations, but only on basic axioms and definitions. Along my journey to ...
Rusurano's user avatar
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The sides and 3 diagonals of two convex hexagons is a rigid graph [closed]

Convex hexagon $ABCDEF$, is the graph of the sides and 3 diagonals a rigid graph? I attempted to apply Menger's theorem: $V(ABCD)=0\iff$ $$\det {\begin{bmatrix}0&d(AB)^{2}&d(AC)^{2}&d(AD)^...
hbghlyj's user avatar
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3 votes
2 answers
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(Confusing) Sine/Cosine rule for Question Regarding Obtuse Triangle / GCSE

Background: This question was taken from Pearson's Edexcel GCSE (9-1) Mathematics Algebra and Shape Workbook Question focus: 3(a) Triangle WXZ - Diagram (link to image, provided by stack exchange) ...
Ethan Z.'s user avatar
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How to prove $EN=\dfrac{AI}{2}?$ and $KN=\dfrac{CJ}{2}$? and $\dfrac{Area(ABD)}{2}+\dfrac{Area(BCD)}{2}=\dfrac{Area(ABCD)}{2}$?

Given \begin{aligned} \operatorname{Area}(E F G H) & =E K \cdot F G \\ & =(E N+K N) \cdot \frac{1}{2} B D \\ & =\frac{1}{2} B D \cdot E N+\frac{1}{2} B D \cdot K N \\ & =\frac{1}{4} ...
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2 votes
3 answers
285 views

Geometry question with congruent triangles and isosceles triangles

In the diagram below $AD\equiv BC$ and $\alpha + \beta=180^{\circ}$. Find the measure of $\theta$. I'm given a hint: First extend $DC$ past $C$ to the point $E$ where $CE \equiv AB$, then draw $AE$ ...
Future Math person's user avatar
2 votes
2 answers
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Proving two triangles congruent given two congruent sides and a congruent median

The title was a bit too short for me to fit the full details, so here's the scenario I have. Prove that two triangles are congruent if in two triangles, the median from the common vertex and two sides ...
nadelock's user avatar
0 votes
2 answers
57 views

Geometry question on angle chasing concerning 3 squares

I am kind of stuck on this problem. We know that the 9 points present in this sketch form three squares, HBAI, CFGB and DEFC. We also know, that the lines DI and AF intersect in S. The question for ...
Enkt Enktson's user avatar
0 votes
2 answers
198 views

Let $ABC$ be a triangle. Let $D$ and $E$ such that $AB \perp BD$, $AC \perp CE$Prove that $\bigtriangleup FBC$ is an isosceles right angled.

PROBLEM: Let $ABC$ be a triangle in which the measures $\angle ABC, \angle ACB$ are smaller than $45$. We consider that the points $D$ and $E$ such that $AB \perp BD$, $AB=BD$, $AC \perp CE$, $AC=CE$, ...
IONELA BUCIU's user avatar
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ABCD is a parallelogram, and AXY is a straight line through A meeting BC at X and DC at Y. Prove that BX.DY is constant.

I'm not able to figure out what "constant" here means. I proved it till AB.AD = BX.DY but how is this value constant I don't get it. If we put different values of sides AB and AD we would ...
Roli's user avatar
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1 answer
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Two triangles have an equal angle, inradius, circumradius. Are these two traingles necessarily congruent?

Two triangles have an equal angle, inradius, circumradius. Are these two triangles necessarily congruent? Let $A_1,A_2$ be the areas if the triangles respectively, $s_1,s_2$ be the semi perimeter ...
Ellie_Wong's user avatar
4 votes
2 answers
107 views

Finding all sides and angles of a triangle

So SAS, SSS, ASA, AAS and RHS are reasons for congruent triangles, that means if a triangle, for example, have side lengths of 5, 6 and 8, then the triangle is unique. What I am trying to do is to ...
YesSpoon3's user avatar
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2 votes
0 answers
141 views

Why is superposition not rigorous in Geometry?

In the Elements things that are equal can coincide perfectly with one another. However we cannot show things to be equal by "applying" one to another. If two lines are equal, why can't we ...
soc3id's user avatar
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1 answer
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High School Mathematics: A problem on parallelograms [duplicate]

$ABCD$ is a parallelogram and $O$ is any point. The parallelograms $OAEB$, $OBFC$, $OCGD$, $ODHA$ are completed. Show that $EFGH$ is a parallelogram I did see this question but it doesn't have the ...
Authorism's user avatar
3 votes
1 answer
111 views

Using sine rule to prove triangle congruence

The following problem looks like it should be easy, but I don't know how to prove it rigorously. All I know is the sine rule should be applied somewhere. Let $ABC$ be triangle with angles $\alpha$, $\...
Timothy Skipper's user avatar
0 votes
1 answer
34 views

Show the congruence $YZ+JK=JF$ in this square with trapezoids, triangles constructed with square's midpoints

Show that $YZ+JK=JF$ I tried Pythagorean theorem. OG: Area of a square inside a square created by connecting point-opposite midpoint
user avatar
4 votes
3 answers
248 views

Prove that $\angle AED = 2 \cdot \angle BEC$

Let $ABCDE$ be a pentagon such that $AE = ED$, $BC = DC + AB$ and $\angle BAE + \angle CDE = 180°$. Prove that $\angle AED = 2 \cdot \angle BEC$. So, by constructing it in Geogebra, I noticed that if ...
I'm Ingrid's user avatar
1 vote
1 answer
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Show the equality of two congruence transformations (geometry)

I have some problems in the following task of my geometry studies: Let $A,B,C$ three non-collinear points in $\mathbb{R}^2$ and let $T_1,T_2:\mathbb{R}^2\rightarrow\mathbb{R}^2$ two congruence ...
EuskiPeuski712's user avatar
-1 votes
1 answer
88 views

Definition of congruence of triangles.

In school level geometry,we studied congruence of triangles.Where it is defined that two triangles are congruent if they have same shape and size.But this is not a precise definition,what does it mean ...
Kishalay Sarkar's user avatar
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0 answers
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polyhedrons congruent if faces are all congruent + same connection status?

In 2 dimension, a unit square and a unit rhombus(of certain angle) has the same list of edges and connection status. But the unit square and the unit rhombus are not generally congruent. Can we find ...
imida k's user avatar
  • 305
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2 answers
308 views

How to prove that angle bisector of right angle triangle ABC right angled at B is perpendicular bisector of third side AC. [closed]

I have tried using sine theoram, angle bisector theoram, congruency of type RHS,AA,ASA but haven't been able to do this.
school work's user avatar
1 vote
0 answers
33 views

Congruent triangles that do not use reflections

This is a simple question on terminology in geometry: Suppose $ABC$ and $DEF$ are two triangles that are congruent, but the transformations from one to the other are based solely only on translation ...
max_zorn's user avatar
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2 votes
0 answers
252 views

Sources for IMO Geometry Theorems

The International Mathematical Olympiad contains highly non-standard problems involving the geometry of circles, triangles and lines which usually draws upon quite a few theorems and facts not ...
BeefStew's user avatar
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4 votes
1 answer
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$PQ ∥ BC$ for isosceles $\triangle ABC$ and inscribed equilateral $\triangle PQR$ with $R$ being midpoint of $BC$

Triangle $ABC$ is isosceles. An equilateral triangle $PQR$ is inscribed in it with $R$ being the midpoint of $BC$. How can you prove $PQ \parallel BC$?
Afsheen's user avatar
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1 vote
1 answer
156 views

How to proof the mid-point theorem without triangle congruence theorems?

Is there a way for me to proof the mid-point theorem without using the triangle congruence theorems? I can't seem to find one that's not using the triangle congruence theorems. The reason I'm trying ...
Mohammad muazzam ali's user avatar
1 vote
1 answer
1k views

Is triangle congruence considered as theorems or postulates?

Is triangle congruence like $SSS$, $SAS$, $ASA$ and $AAS$ considered as theorems or postulates? I've seen some people calling it as theorems and some other people calling it as postulates. What I know ...
Mohammad muazzam ali's user avatar
0 votes
0 answers
27 views

Does there exist an efficient way to determine if two $n$-simplices in $\mathbb{R}^n$ are congruent?

Given two $n$-simplices in $\mathbb{R}^n$, does there exist an algorithm to determine if they are congruent which has a time complexity of the form $O(n^c)$ where $c$ is a constant? I'm assuming that ...
Naiim's user avatar
  • 357
5 votes
1 answer
262 views

Prove ABC,A'B'C' are congruent:D is on BC,D' is on B'C', $\angle BAD \angle CAD= \angle B'A'D' \angle C'A'D', AB=A'B', AC=A'C', AD=A'D'$

In $\triangle ABC$ and $\triangle A'B'C'$, $D$ is a point on line segment $BC$ and $D'$ is a point on line segment $B'C'$. $\frac{\angle BAD}{\angle CAD}=\frac{\angle B'A'D'}{\angle C'A'D'}$, $AB=A'B'$...
Alex-Github-Programmer's user avatar
1 vote
1 answer
497 views

Triangle and Median related question

Let BD be a median in triangle ABC. The points E and F divide the median BD in three equal parts, such that BE = EF = FD. If AB = 1 and AF = AD, find the length of the line segment CE. I have tried ...
Mathronza's user avatar
  • 164
1 vote
4 answers
250 views

Find the measure of $\angle G$ in a triangle

In the following figure, $\Delta$ADB, $\Delta$PCB and $\Delta$EFG are right triangles. $PB=AE$,$AC=CB$. Question: What is the value of $\angle G$? I figured out $\angle A = \angle CPB$ , $EF=AC$. ...
Star Bright's user avatar
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0 votes
1 answer
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Geometry find the angle

Good day, excuse me, I am looking at congruence themes in Geometry, and I am trying to solve this problem, but I am not sure how to proceed. The coloured numbers is what I have so far (although now ...
lynneerwell's user avatar
1 vote
3 answers
588 views

Similarity by SSA (side-side-angle) in obtuse triangles

Source: Challenge and Thrills of Pre-College Mathematics, Page 74, Problem 54: "In two obtuse triangles, an acute angle of the one is equal to an angle of the other, and sides about the other ...
Aether162's user avatar
  • 187
2 votes
1 answer
248 views

Finding side lengths of a trapezoid given the distance between its diagonal intersection and midpoint of a diagonal

The Question My friend recently gave me a problem that I was interested in, but could not completely solve. I've already constructed a diagram that roughly represents the problem, and it's below. ...
Darren Yang's user avatar
0 votes
3 answers
414 views

Let $ABCD$ be a square. Points $A,B,G$ are collinear. $AC$ and $DG$ meet at $E$ , and $DG$ and $BC$ meet at $F$.

Let $ABCD$ be a square. Points $A,B,G$ are collinear. $AC$ and $DG$ meet at $E$ , and $DG$ and $BC$ meet at $F$. If $DE = 15$ cm, $EF = 9$ cm, find $FG$. What I Tried: Here is a picture :- I have ...
Anonymous's user avatar
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0 votes
2 answers
626 views

In the diagram, $AB$ $||$ $EF$ $||$ $DC$ . Given that $AC + BD = 250$ , $BC = 100$ and $EC + ED = 150$, find $CF$.

In the diagram, $AB$ $||$ $EF$ $||$ $DC$ . Given that $AC + BD = 250$, $BC = 100$ and $EC + ED = 150$, find $CF$. What I Tried: Here is the diagram :- I have assigned variables for the different ...
Anonymous's user avatar
  • 4,260
1 vote
2 answers
372 views

$\Delta ABC$, $AC = 2BC$ and $\angle C = 90^\circ$ and $D$ is the foot of the altitude from $C$ onto $AB$. Find $AE : EC$ .

$\Delta ABC$, $AC = 2BC$ and $\angle C = 90^\circ$ and $D$ is the foot of the altitude from $C$ onto $AB$. A circle with diameter $AD$ intersects the segment $AC$ at $E$. Find $AE : EC$. What I Tried:...
Anonymous's user avatar
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4 votes
2 answers
442 views

In $\Delta ABC,$ side $AC$ and the perpendicular bisector of $BC$ meet at $D$, where $BD$ bisects $\angle ABC$.

In $\Delta ABC,$ side $AC$ and the perpendicular bisector of $BC$ meet at $D$, where $BD$ bisects $\angle ABC$. If $CD = 7$ and $[\Delta ABD] = a\sqrt{5}$ , find $a$ . What I Tried: Here is a picture:...
Anonymous's user avatar
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3 votes
1 answer
691 views

Let $O$ be the centre of the circumcircle of $\Delta ABC$, $P$ and $Q$ be the midpoint of $AO$ and $BC$, respectively.

Let $O$ be the centre of the circumcircle of $\Delta ABC$, $P$ and $Q$ be the midpoint of $AO$ and $BC$, respectively. Suppose $\angle CBA = 4\angle OPQ$ and $\angle ACB = 6\angle OPQ$ . FiNd $\angle ...
Anonymous's user avatar
  • 4,260
2 votes
0 answers
28 views

Planar convex sets whose self-intersections are similar to themselves

Let $S\subset \mathbb{R}^2$ be a bounded convex set. For which $S$ can we take $S'$ congruent to $S$ (i.e., the image of $S$ under an isometry of the Euclidean plane) such that $S\cap S'$ is similar ...
RavenclawPrefect's user avatar
0 votes
3 answers
853 views

In $\Delta ABC$, $AB = 14, BC = 16, AC = 26$. $M$ is the midpoint of $BC$ and $D$ is the point on $BC$ such that $AD$ bisects $\angle BAC$.

In $\Delta ABC$, $AB = 14, BC = 16, AC = 26$. $M$ is the midpoint of $BC$ and $D$ is the point on $BC$ such that $AD$ bisects $\angle BAC$. Let $P$ be the foot of the perpendicular from $B$ to $AD$ . ...
Anonymous's user avatar
  • 4,260
2 votes
1 answer
771 views

In $\triangle ABC, AB = 28, BC = 21$ and $CA = 14$. Points $D$ and $E$ are on $AB$ with $AD = 7$ and $\angle ACD = \angle BCE$

In $\triangle ABC, AB = 28, BC = 21$ and $CA = 14$. Points $D$ and $E$ are on $AB$ with $AD = 7$ and $\angle ACD = \angle BCE$. Find $BE$. What I Tried: Here is a picture :- I know the side-lengths ...
Anonymous's user avatar
  • 4,260
4 votes
1 answer
1k views

In $\Delta ABC$, $AB:AC = 4:3$ and $M$ is the midpoint of $BC$ . $E$ is a point on $AB$ and $F$ is a point on $AC$ such that $AE:AF = 2:1$

In $\Delta ABC$, $AB:AC = 4:3$ and $M$ is the midpoint of $BC$ . $E$ is a point on $AB$ and $F$ is a point on $AC$ such that $AE:AF = 2:1$. Also $EF$ and $AM$ intersect at $G$ with $GF = 36$ cm, $GE = ...
Anonymous's user avatar
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0 votes
1 answer
99 views

How to prove that a triangle is uniquely determined by an angle, its opposite side and its perpendicular height.

I am trying to solve a homework problem and as part of this problem, I need to show that a certain situation is impossible. I have the following situation. Given some line, I have $2$ points $H$ and $...
Robert Lee's user avatar
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0 votes
2 answers
1k views

When extending the sides $AB,BC,CA$ of $\Delta ABC$ to $B',C',A'$ respectively, such that $AB' = 2AB$ , $CC' = 2BC$ , $AA' = 3CA$ .

When extending the sides $AB,BC,CA$ of $\Delta ABC$ to $B',C',A'$ respectively, such that $AB' = 2AB$ , $CC' = 2BC$ , $AA' = 3CA$ . If $[\Delta ABC] = 1$, find $[\Delta A'B'C']$ . What I Tried: Here ...
Anonymous's user avatar
  • 4,260
1 vote
2 answers
436 views

In $\Delta ABC$, angle bisector of $\angle ABC$ and median on side $BC$ intersect perpendicularly

In $\Delta ABC$, $BE$ is the angle bisector of $\angle ABC$, $AD$ is the median on side $BC$. $AD$ intersects $BE$ at $O$ perpendicularly. If $AD = BE = 4$, find the lengths of each side of $\Delta ...
Anonymous's user avatar
  • 4,260
2 votes
1 answer
170 views

In $\Delta ABC$, $AC = BC$ and $\angle C = 120^\circ$. $M$ is on side $AC$ and $N$ is on side $BC$ .

In $\Delta ABC$, $AC = BC$ and $\angle C = 120^\circ$. $M$ is on side $AC$ and $N$ is on side $BC$ such that $\angle BAN = 50^\circ$ and $\angle ABM = 60^\circ$. Find $\angle NMB$ . What I Tried: ...
Anonymous's user avatar
  • 4,260
1 vote
2 answers
593 views

In right $\Delta ABC$, $\angle C = 90^\circ$. $E$ is on $BC$ such that $AC = BE$. $D$ is on $AB$ such that $DE \perp BC$ .

In right $\Delta ABC$, $\angle C = 90^\circ$. $E$ is on $BC$ such that $AC = BE$. $D$ is on $AB$ such that $DE \perp BC$ . Given that $DE + BC = 1$ and $BD = \frac{1}{2}$, find $\angle B$. What I ...
Anonymous's user avatar
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