Questions tagged [combinatorial-proofs]

Combinatorial proofs of identities use double counting and combinatorial characterizations of binomial coefficients, powers, factorials etc. They avoid complicated algebraic manipulations.

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Let $S_1, S_2, \dots , S_m$ be distinct subsets of $\{1, 2, \dots , n\}$ such that $|S_i \cap S_j | = 1$ for all $i \ne j$. Prove that $m \le n$.

Let $S_1, S_2, \dots , S_m$ be distinct subsets of $\{1, 2, \dots , n\}$ such that $|S_i \cap S_j | = 1$ for all $i \ne j$. Prove that $m \le n$. I got this problem from the double counting handout ( ...
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Find all natural numbers $n$ such that $\binom{n+1}{k}$ is even $\forall~k=1,\dots,n$.

I want to study the parity of $\binom{n}{k}$. I know that there are several ways to do this for a given $n$ and a given $k$, such as Kummer's theorem or Lucas' theorem, which give a method to find the ...
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${r + s \choose r + s - n} = \sum_{p,q,p',q'} {r \choose p} {s \choose q}$

I am fixing $m,n,r,s$ such that $m + n = r + s$ from the beginning. I have the following $4$ conditions that should be satisfied : \begin{align*} r &= p + p'\\ s &= q + q'\\ m &...
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Prove combinatorially that: $\displaystyle {{n}\choose{k}} {{n}\choose{m}} = \sum^{k}_{i=0} {{n}\choose{m+i}}{{m+i}\choose{k}} {{k}\choose{i}}$

Prove combinatorially that: $$\displaystyle {{n}\choose{k}} {{n}\choose{m}} = \sum^{k}_{i=0} {{n}\choose{m+i}}{{m+i}\choose{k}} {{k}\choose{i}}$$ I couldn't solve it by myself. it's to complicated ...
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Proof of recursive relationship between binary permutations. [closed]

I'm tring to figure out a relationship between binary permutations. I note $\sigma_{i, k} $ the set of all binary permutations with $i$ $0$ and $k-i$ $1$. I think it is true to say that : $$\sigma_{i, ...
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Combinatorially proving $F_{n} = \sum_{i=0}^{\left\lfloor n/2 \right\rfloor}\binom{n-i}{i}$, where $F_n$ is the $n$-th Fibonacci number [duplicate]

Prove the following combinatorially: $$F_{n} = \sum_{i=0}^{\left\lfloor n/2 \right\rfloor}\binom{n-i}{i}$$ So, I know that the Fibonacci number counts the number of ways to cover a $1 \times n$ ...
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"halfthink sets" contain n and n+1

A problem: Georgina calls a 992-element subset $A$ of the set $S = \{1, 2, 3, . . . , 1984\}$ a halfthink set if • the sum of the elements in $A$ is equal to half of the sum of the elements in $S$, ...
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Inequality for triple product of Stirling numbers

Let ${n\brace k}$ be the Strirling number of the second kind, such that ${n+1\brace k} =k{n\brace k}+{n\brace k-1}$ with ${0\brace 0}=1$. Let $j,p,n$ integers such that $1 \le j \le p \le n$. I ...
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To prove that no perfect covers exist for the staircase board.

Let $S_n$ denote the staircase board with $1 + 2 + ... + n = $$n( n + 1)\over2$ squares. Prove that $S_n$ does not have a perfect cover with dominoes for any $n \ge 1$. This problem is provided in ...
2 votes
3 answers
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Prove that if $2n$ points are colored red or blue, then we can always connect the red points to the blue points with non-intersecting line segments.

Take any set of 2n points in the plane with no three collinear, and then arbitrarily color each point red or blue. Prove that it is always possible to pair up the red points with the blue points by ...
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Show that player I can always win a Nim game in which the number of heaps with an odd number of coins is odd

Show that player 1 can always win a Nim game in which the number of heaps with an odd number of coins is odd. This question is provided in Richard A. Brauldi's book on Introductory Combinatorics. I ...
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Combinatorial proof of $S(n,n-2)=\binom{n}{3}+\frac{1}{2}\binom{n}{2}\binom{n-2}{2}$ when $n \ge 4$ [duplicate]

$$ n\ge 4, S(n,n-2)=\binom{n}{3}+\frac{1}{2}\binom{n}{2}\binom{n-2}{2} $$ Proving this combinatorially. I understand what the LHS is doing. There are a couple of things I don't follow on the right-...
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Proving $\sum_{1\le x\le y\le t}\frac{2^{t-x}}{xy}=\sum_{1\le x\le y\le t}\frac{C_t^0+C_t^1+\cdots+C_t^{y-1}}{xy}$ for positive integer $t$

Prove that $$\sum\limits_{1\le x\le y\le t}\frac{2^{t-x}}{xy}=\sum\limits_{1\le x\le y\le t}\frac{\text C_t^0+\text C_t^1+\cdots+\text C_t^{y-1}}{xy},$$ where $t$ is a positive integer. I think that ...
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IMO Combinatorics C2 proof check

We have $2^m$ sheets of paper, with the number $1$ written on each of them. We perform the following operation. In every step we choose two distinct sheets; if the numbers on the two sheets are a and ...
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Probability Coin Toss Game Never Ties in N tosses

Question This question is a rewording of the Matching Pennies problem (Question 23) in Frederick Mosteller's "Fifty Challenging Problems in Probability". Here is my rewording: Suppose to ...
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average of pairs sitting next to each other - harder version

The Problem This question comes from "50 Challenging Problems in Probability" By Mosteller. The question is: Eight eligible bachelors and seven beautiful models happen randomly to have ...
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1 answer
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Applications of the pigeonhole principle (strong form)

If $n \ge 25$ and $n = 8r_1 + 5r_2$ (with $r_1, r_2$ being natural numbers), prove that either $r_1 \ge 2$ or $r_2 \ge 2$. So is uttered the question which I found in a book on introductory ...
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Combinatorics: A problem of 2 Discs

Two disks, one smaller than the other, are each divided into 200 congruent sectors. In the larger disk, 100 of the sectors are chosen arbitrarily and painted red; the other 100 sectors are painted ...
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Proving the Pigeonhole Principle: Strong Form

I find my self struggling to understand this proof given by Richard A. Brauldi in his book on "Introductory Combinatorics". It is required to show that If $q_1 + q_2 + \dots + q_n – n + 1$ ...
2 votes
2 answers
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lists with length $k$ with elements $b_1,b_2,\dots,b_k$ such that $|b_1|+|b_2|+···+|b_k| \le n$

Ivan and Alexander write lists of integers. Ivan writes all the lists of length $n$ with elements $a_1,a_2,\dots,a_n$ such that $|a_1| + |a_2|+\dots+|a_n| \le k$. Alexander writes all the lists with ...
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Uniqueness of Radon point

For a set $A\subset\mathbb R^d$ of $d+2$ points, Radon's Lemma states that we find disjoint $B,C\subset A$ with $\mathrm{Conv}(B)\cap\mathrm{Conv}(C)\neq\emptyset$. Elements belonging to such ...
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Consecutive Integer Sum of an m-member Sequence is Divisible by m Proof

This problem is found in Richard A. Brauldi's book on Introductory Combinatorics. It goes as follows: Given m integers $a_1, a_2, ... ,a_m$, there exist integers $k$ and $l$ with $0 \le k \lt l \le m$ ...
2 votes
2 answers
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Prove that $\Sigma_{i=0}^{n-1} (\Sigma_{j=i+1}^n(j(^nC_i) + i(^nC_j))) = n^22^{n-1}$ [duplicate]

I have tried setting $$P=\Sigma_{i=0}^{n-1} (\Sigma_{j=i+1}^n(j(^nC_i) + i(^nC_j))$$ then $$P=\Sigma_{i=0}^{n-1} (\Sigma_{j=i+1}^n((n-j)(^nC_i) + (n-i)(^nC_j))$$ now adding them both $$2P=\Sigma_{i=0}^...
2 votes
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With sachets containing at most 13 seeds, given 2021 rose, jasmine or fennel seeds respectively what is the maximum number of rose seeds used?

I have taken a part of the problem which I did not understand its solution. Basically, there are: $2021$ rose seeds, $2021$ jasmine seeds and $2021$ fennel seeds. So now, with sachets of at most size ...
3 votes
4 answers
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How many different sets of positive integers $(a, b, c, d)$ are there such that $a \lt b \lt c \lt d$ and $a + b + c + d = 41$?

Is there a general formula which I can use to calculate this and if it's with proof or reasoning would be great as well. Even if you could please solve this $4$-variable ordered set of positive ...
2 votes
1 answer
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Probability of getting an overlap of x or more elements drawn from two sets.

So I've got a question for which I was able to run a simulation and calculate the probability from this simulation in R (picture below, following a normal distribution) but now I was wondering if ...
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Understanding the proof of Van der Waerden's theorem by Graham and Rothschild.

I am studying the proof of Van der Waerden's theorem by Graham and Rothschild. I have tried to understand each step, but I need to fill in some gaps. Van der Waerden's theorem says that: $\forall k, r ...
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1 answer
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Why $(n!)^m\cdot m!$ is divisor of $(mn)!$ [duplicate]

For natural number $m, n$, i found out that $\{\{\{a_1, a_2, \cdots a_n\},\{a_{n+1}, a_{n+2}, \cdots a_{2n}\}, \cdots \{a_{mn-n+1}, \cdots a_{mn}\}\}| \{a_1,a_2, \cdots a_{mn}\}=\{1,2, \cdots mn\}\}$ ...
1 vote
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What computational shortcut finds the sum all possible products given any list of n random real numbers taken r at a time? Here's what I tried...

I have the following computational shortcuts for any list of $n=4$ quantities taken r at a time. My goal is to do this for lists of any length. Taken r at a time, what function can similarly output ...
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Possibly wrong Bolyai-tournament solution

Following problem: "We have 100 metal balls, 51 of which are radioactive. Furthermore we have a balance which is designed in such a way that one sphere fits on each of its two plates. If a ...
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Paradox from graph theory

$\scriptsize\text{Though these incorrect contradictory statements aren't well received, I just want it explained.}$ Given graph $G=K_6$ where all edges are red, pick three points and change the color ...
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1 vote
1 answer
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Combinatorial proof of binary partition function $b(n)$ is always even

For all integer $n$, let $b(n)$ be the number of partition of $n$ into power of two. For instance, $b(4)=4$, since \begin{align*} 4 &= 2^2 \\ &= 2^1+2^1 \\ &= 2^1+2^0+2^0 \\ &= 2^0+2^0+...
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2 votes
2 answers
76 views

Identity for Difference of Sum of Products of Binomial Coefficients

Problem Statement I recently came across the following equation that I want to prove: $$ \sum_{i=1}^{n} \left[ \binom{n+i}{m}-\binom{n-i}{m} \right] \binom{2n}{n-i} = \sum_{i=1}^{m}\binom{n+i}{m}\...
7 votes
3 answers
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Supplementary exercise 51, chapter 3 from 'A walk through combinatorics' 4th edition

I'm selfstudying 'A walk through combinatorics' by Miklós Bóna. This book has some supplementary exercises at the end of each chapter, no solution provided. I'm trying exercise 51, chapter 3. ...
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Is there a natural bijective proof of the identity $(2^i)^j = (2^j)^i$?

As is well-known, iterating exponentials is a commutative operation. Assuming that $i$ and $j$ are positive integers, one way to view the integer $2^i$ is as the cardinality of the power set $2^{\{ 1 ,...
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Derivation of Permutation Formula

I've been familiar with the formula of finding the $r$-permutation of an $n$-element set; but I've only been half-so familiar with deriving the formula. See, I know that to prove the truth of $$ P(n,...
1 vote
3 answers
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Show the following holds for $c\leq 1$: $e^{ck^2/n} \frac{(n!)^2}{(n+k)!(n-k)!} \leq M, \quad \text{for } k = 1, \dots, n.$ for some constant $M$

Show that the following inequality holds for $c\leq1$: \begin{equation} \tag{1} e^{ck^2/n} \frac{(n!)^2}{(n+k)!(n-k)!} \leq M, \quad \text{for $k = 1, \dots, n$} \end{equation} for some constant $M$. ...
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To prove an identity related to Gamma function

Question: How to prove the following identity for all positive integers $k$ and $n$: \begin{align}\tag{1} (k+1)(2k+1) \cdots (nk+1) = \sum_{i=1}^n & \binom{n}{i} \left( \frac{i}{n}(k+2)-1 \right) \...
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4 votes
2 answers
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Proving $\sum_{k=0}^{m}\binom{n+k}{k}(1-x)^kx^{n+1}=1-\sum_{k=0}^{n}\binom{m+k}{k}x^k(1-x)^{m+1}$ without calculus

How would you prove this without calculus? $$\forall m,n\in\Bbb N,\ \forall x\in\Bbb R,\ \sum_{k=0}^{m}\binom{n+k}{k}(1-x)^kx^{n+1}=1-\sum_{k=0}^{n}\binom{m+k}{k}x^k(1-x)^{m+1}$$ In this post it is ...
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Is the minimum spanning tree always the optimal solution of spanning tree polytope?

I was studying the proof of $1.5$-Approximate Path TSP problem and found a tiny wrinkle that I just can't get over it. In the proof it says that the minimum spanning tree found by standard MST ...
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bijective proof that $\sum_{k=0}^n {2k \choose k} {2(n-k)\choose (n-k)} = 4^n$ [duplicate]

Provide a combinatorial proof that $\sum_{k=0}^n {2k \choose k} {2(n-k)\choose (n-k)} = 4^n.$ It might be easier to find a non-combinatorial proof first (e.g. a proof by induction). For the bijective ...
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Solving $\sum_{k = 0}^{n} \binom{n}{k} \frac{1}{k+1} = \frac{2^{n+1}-1}{n+1}$ combinatorially? [duplicate]

I have solved $\sum_{k = 0}^{n} \binom{n}{k} \frac{1}{k+1} = \frac{2^{n+1}-1}{n+1}$ using integrals as follows: $$(1+x)^n = \sum_{k=0}^{n}\binom{n}{k}x^k.$$$$\frac{(2)^{n+1}}{n+1} - \frac{1}{n+1} = \...
2 votes
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Probability of runs with cyclical criteria in Bernoulli trials

I am considering an extension of a previously posed problem, for which I have a hand-wave solution. I would like to determine whether the solution is exact and if not, need help with a rigorous ...
-1 votes
1 answer
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arranging p numbered balls in n indistinguishable boxes [closed]

let pDn the number of ways to arrange p numbered balls in n indistinguishable boxes such that p is greater than or = n and no box is empty how to calculate pDp-1. (I tried to dissect the problem and I ...
7 votes
2 answers
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Combinatorial Interpretation of a partition identity

I am working on the book "Number Theory in the Spirit of Ramanujan" by Bruce Berndt. In Exercise $1.3.7$: He wants us to prove that $$ np\left(n\right) = \sum_{j = 0}^{n - 1}p\left(j\right)\...
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Bounding this combinatorial sum

I'm looking to find a closed form expression or to bound the following sum $$ \sum_{\atop \LARGE j\ =\ \left(k + 1\right)/3\ +\ 1} ^{\LARGE 2\left(k + 1\right)/3 \atop} {i - 1 \choose j - 1}{n - {\rm ...
2 votes
5 answers
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Prove that $2^{(n^2)} = \sum_{i=0}^n \binom{n}{i} (2^n-1)^i$ using double counting. [duplicate]

Using a combinatorial proof (counting the same thing in different ways), show that: $$2^{(n^2)} = \sum_{i=0}^n \binom{n}{i} (2^n-1)^i$$ I was thinking of having some set $A$ where $|A| = n$, and then ...
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Number of ways to choose $m$ boys and $k$ girls from $n$ boys and $n$ girls?

Suppose there are $n$ boys and $n$ girls and we want to choose $m$ boys and $k$ girls such that $k \le m$. Then there are $\binom{n}{m} \binom{n}{k}$ ways to do it. Now, using counting in two ways, I ...
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1 answer
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Ways to colour elements of matrix using two colours

Let $A$ be a $n \times n$ matrix and suppose we want to colour elements of this matrix using black and white colours. Since each element can be either white or black, so total number of ways are $2^{n^...
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2 votes
3 answers
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How to prove the binomial identity $\binom{n + 1}{a + b + 1} = \sum_{k = 0}^n \binom{k}{a}\binom{n - k}{b}$

Prove the identity: $$\binom{n + 1}{a + b + 1} = \sum_{k = 0}^n \binom{k}{a}\binom{n - k}{b}$$ So far I understand the left side represents how many ways there are picking a+b+1 elements from a set (...

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