Questions tagged [cobordism]

Literally "together boundary", a cobordism is a relation between two compact manifolds stating that their disjoint union forms the boundary of a higher dimensional manifold. This defines an equivalence relation between compact manifolds that is very coarse: two manifolds may be cobordant but not homeomorphic. This flexibility makes it the right notion for classifying manifolds in higher dimensions. See also (geometric-topology) and (algebraic-topology).

Filter by
Sorted by
Tagged with
0 votes
0 answers
25 views

Help understanding Morse theory proof (Milnor)

I'll start with the statement of the theorem and its proof, and I'll end by explaining my difficulty understanding the proof. What follows are not Milnor's original words, but rather my best attempt ...
JMM's user avatar
  • 1,074
1 vote
0 answers
54 views

Geometric interpretation of pairing between bordism and cobordism

In page 448 of these notes, a pairing between bordism and cobordism $$\langle \ ,\ \rangle: U^m(X)\otimes U_n(X)\rightarrow \Omega^U_{n-m}$$ is defined as follows. Assume $x\in U^m$ is represented by $...
timaeus's user avatar
  • 119
2 votes
0 answers
23 views

Spaces distinguished by cobordism homology

Recently I have been learning about cobordisms. While I have seen many applications of cobordism to stable homotopy theory and immersion problems, I couldn't find an example of spaces that can be ...
Reihe27's user avatar
  • 66
0 votes
1 answer
82 views

Relation of Algebraic Cobordism to Cobordism of Smooth Manifolds

(I have almost no background in algebraic geometry, so excuse the naivete of my question.) Some ideas I've been thinking about recently led to the question of whether there is a notion of 'cobordism' ...
LeonardoOiler's user avatar
1 vote
0 answers
72 views

Equivalent definitions of cobordism

I am reading Stong's notes on Cobordism, and he defines a Cobordism category $\mathcal{C}$, with direct sums and a boundary functor $\partial:\mathcal{C}\longrightarrow \mathcal{C}$, and says that two ...
kindasorta's user avatar
  • 1,178
2 votes
0 answers
41 views

A $\pi_1$-neglibility criterion in 4-dimensional manifolds

I'm reading about the h-cobordism theorem in boundary dimension 4. Most of the steps are the same as in the classical statement, but finding whitney disks to homotope the 2- and 3-handles into ...
Timotheus Hauptinius's user avatar
2 votes
0 answers
52 views

A question about the theorem of Kervaire and Milnor that the group $\Theta^n$ is finite for $n\neq 3$

In 1963, Kervaire and Milnor proved that the group $\Theta^n$ is finite for $n\neq 3$ (https://www.math.kit.edu/iag5/lehre/semgeo2014w/media/kervaire%20milnor.pdf). Here $\Theta^n$ is the group of h-...
user302934's user avatar
  • 2,076
3 votes
0 answers
56 views

How did Thom calculate $MSO(k)$ using Silber's polyhedron in his 1954's paper?

I am now reading Thom's famous paper Quelques propriétés globales des variétés différentiables. In page 48, Thom used an auxiliary space $K$, which is a principal fiber bundle with base space $K(\...
Tongtong Liang's user avatar
5 votes
1 answer
94 views

Are invertibly cobordant manifolds diffeomorphic

Let $M$ and $N$ be oriented, closed, $n-1$ manifolds and $F$ a cobordism from $M$ to $N$ and $G$ a cobordism from $N$ to $M$ such that the composite cobordism $G\circ F\cong M\times I$ and $F\circ G\...
J.V.Gaiter's user avatar
  • 1,882
1 vote
0 answers
108 views

Question about Milnor hypersurface

Good time of day. I have the following question Milnor hypersurface $H_{ij}$ is a smooth hypersufrace in $\mathbb CP^i \times \mathbb CP^j$ for fix pair of integers $j \ge i\ge 0$. Its algebraic ...
Victory's user avatar
  • 411
1 vote
0 answers
28 views

Does dimensional reduction of TQFTs have an adjoint?

If $Cob_n$ is $n$-dimensional cobordisms, and $Z \colon Cob_n \to \mathcal{V}$ is an $n$-dimensional TQFT (i.e. a symmetric monoidal functor - in particular, $\mathcal{V}$ is symmetric), then one can ...
Jo Mo's user avatar
  • 2,035
2 votes
1 answer
80 views

Doubt in proof of Thom's Cobordism theorem

When proving the Thom's Cobordism theorem for unoriented manifolds, at some point we are able to create a map $$\phi: MO\rightarrow \bigvee_{i}\Sigma^{|d_i|}K(\mathbb{Z_2})$$ where $MO$ is the Thom ...
Someone's user avatar
  • 4,537
3 votes
1 answer
72 views

cancellation theorem in h-cobordism

I'm reading milnor's book h-cobordism, in beginning of the section cancellation theorem, milnor give an example that composition of two elementary cobordism with index $0$ and $1$ may be a product ...
taiat's user avatar
  • 1,107
1 vote
1 answer
51 views

Problems on definition of genus with multiplicative sequence.

I’m reading Manifolds and Modular Forms. According to its introduction chapter, the definition of genus is a ring homomorphism $\varphi:\Omega\otimes\mathbb{Q}\rightarrow R$ with $R$ an integral ...
Sqr's user avatar
  • 138
2 votes
1 answer
105 views

Milnor's Lectures on h-cobordism theorem: Lemma 6.2

In the book, Lemma 6.2 (stated below) talks about a corollary of the Thom's isomorphism theorem and Tubular neighbourhood theorem. The proof of the lemma is not provided by the author. And the ...
Prerak Deep's user avatar
2 votes
1 answer
116 views

Embedded null-homologous circle in high dimension is bound by disc

Assume we have an oriented manifold $M$ of dimension say $n > 2$ (or if necessary $n > 3$) and an embedded circle $S$ whose fundamental class $[S]$ is zero in homology. Is that circle always the ...
YoungMath's user avatar
  • 571
2 votes
1 answer
94 views

Elementary Morse Cobordism of Diffeomorphic Boundary Components

Let $(M,V,V')$ be a smooth manifold triads. I would like to find a Morse cobordism which is elementary, i.e. there exists Morse function $f:M\to[0,1]$ such that $f^{-1}(0)=V, f^{-1}(1)=V'$ and of only ...
user avatar
8 votes
1 answer
3k views

Why care about homotopy equivalence up to $\vee S^2$ or $\# (S^2 \times S^2)$?

I have read that in the study of 4-manifolds (specifically, their classification up to homotopy) that a popular/useful notion of equivalence is that up to a wedge of 2-spheres or connected sum of $S^2\...
Descartes Before the Horse's user avatar
2 votes
0 answers
63 views

Need help understanding the existence of a projection map $pr_2:M \wedge X_+ \rightarrow X$

I am reading these introductory notes to cobordism theory, however cobordism theory is not required to understand my question. I just need help understanding a certain map. On page number 8 the author ...
Noel Lundström's user avatar
3 votes
1 answer
121 views

Lifting a map to a homeomorphism of coverings

This is a part of the proof of Lemma 4 of "Cobordism of classical knots" by Casson and Gordon. Here, $\widetilde{X}$ denotes a prime-fold cyclic covering of $X$. Let $h\colon X\to X$ ...
NothingInSense's user avatar
0 votes
0 answers
98 views

$\mathbf{RP}^m \times \mathbf{RP}^n$ bounds a $(m+n+1)$-d manifold?

How to show whether $\mathbf{RP}^m \times \mathbf{RP}^n$ bounds a $(m+n+1)$-d manifold or not? For example, could we prove or disprove $\mathbf{RP}^2 \times \mathbf{RP}^2$ bounds a 5d manifold?
annie marie cœur's user avatar
1 vote
0 answers
38 views

Quadratic enhancements of the intersection form and spin structures

If we search spin structures and quadratic enhancements of the intersection form, there are many papers discussing the issue. What are the relations and basic intuitions between the quadratic ...
annie marie cœur's user avatar
0 votes
0 answers
69 views

all unoriented bordism groups are $\mathbb{Z}/2$s

Is it true that all unoriented bordism groups are $\mathbb{Z}/2$ vector spaces? This means that any unoriented bordism groups must be of the form: $$ \mathbb{Z}/2 \oplus \mathbb{Z}/2 \oplus \mathbb{Z}/...
annie marie cœur's user avatar
3 votes
0 answers
50 views

Smooth functions defined on connected sums

The following is Theorem 9.29 in Lee's Introducton to Smooth Manifolds. Theorem 9.29. Let $M$ and $N$ be smooth $n$-manifolds with nonempty boundaries, and suppose $h:\partial N\to \partial M$ is a ...
blancket's user avatar
  • 2,076
1 vote
0 answers
94 views

A non modern theory of generalized Thom spectra

I've already posted this question on mathoverflow a few days ago and I had no reaction, I hope it is not illegal to repost it on math.stackexchange. I'm new in the subject of stable homotopy theory, ...
elidiot's user avatar
  • 2,149
1 vote
0 answers
44 views

Inclusion of a punctured disk inside a cylinder with the strings cut off.

This is slightly related to my previous question Higher homotopy groups of a string complement in a cylinder., but now I'm only interested in a following one: We call the image of a smooth embedding $...
Mihail's user avatar
  • 2,211
3 votes
1 answer
199 views

What is the zipper?

1. Defining an "open-closed TFT" Consider the following category of open-closed cobordisms $Cob_2^{o/c}$: Objects are compact oriented smooth one-dimensional manifolds possibly with ...
Max Demirdilek's user avatar
2 votes
0 answers
49 views

Rigidity in the monoidal cobordism category

1. Defining $Cob_n$ Let $n$ be a positive integer. Define the cobordism category $C=Cob_n$ as follows: Objects are $(n-1)$-dimensional closed, smooth oriented manifolds. A morphism from $M \in Obj(C)$...
Max Demirdilek's user avatar
1 vote
0 answers
59 views

Embedding of a boundary component induces isomorphism on homologies

Let $(A,\partial)$ be a surface with boundary. Pick a relative bordism $W$ from $A$ to itself, i.e. $\partial W \cong (A\cup_{\partial}-A)$. Is it true that inclusion $i:A\hookrightarrow W$ induces ...
Mihail's user avatar
  • 2,211
2 votes
0 answers
58 views

Relationship between a certain scalar and any known notions of curvature in geometry

Disclaimer. I'm not an expert geometer, so feel free to fix my language if I use the wrong words... Let $S$ be a smooth $(n-1)$-dimensional surface in $\mathbb R^n$, with "inside" $A \subseteq \...
dohmatob's user avatar
  • 9,220
3 votes
1 answer
112 views

Bordism invariants as integrals of Stiefel-Whitney classes

I am trying to understand this mathematical physics paper by A. Kapustin, which assumes knowledge of bordism invariants of smooth compact manifolds: https://arxiv.org/abs/1403.1467v3 For example, ...
Tomáš Bzdušek's user avatar
2 votes
1 answer
97 views

Existence of a transversal map prevents density?

Let $S$ be a $C^{\infty}$-submanifold of $N$ and suppose that $N-S$ is dense in $N$, where $M,N$ are $m$ and $n$ dimensional $C^{\infty}$-manifolds, respectively. In this post the answering poster ...
user avatar
1 vote
1 answer
61 views

Additional structure on complex cobordism?

So I want to understand does the following addition give stricter condition for equivalence of two stably-complex manifolds? Assume the following relation: let two stably-complex $n$-manifolds $M^n,...
Grisha Taroyan's user avatar
1 vote
1 answer
146 views

Cobordism of points

On the wiki page about cobordism, it is stated that the cobordism of oriented 0-dimensional manifolds is $\mathbb Z$. That seem surprising since One can always draw a line between two points. I ...
Anne O'Nyme's user avatar
  • 1,039
4 votes
2 answers
258 views

Does the normal bundle of a manifold depend on embedding?

In the proof of unoriented cobordism ring being isomorphic to homotopy group of Thom spectra, one considers a large enough dimensional Euclidean space where a given manifold has all the embeddings ...
Paladin's user avatar
  • 1,053
1 vote
1 answer
322 views

Mapping cylinder of homeomorphism is not homeomorphic to product

Let $X$ be a topological manifold, and $f:X\to X$ be a homeomorphism. The mapping cylinder is defined as $M_f:=(X\times[0,1]\sqcup X)/(x,1)\sim f(x)$. I am told somewhere that there exists an example ...
Aliceyuenyuen's user avatar
0 votes
1 answer
58 views

Question on concept of homology in calibrated geometry

The fundamental lemma of calibrated geometry states that calibrated submanifolds are absolutely volume minimising in their homology class. In the proof, homology equivalent is used synonymously with ...
deepfloe's user avatar
  • 446
0 votes
1 answer
221 views

J. Milnor: smooth manifold triad vs cobordism

I started studying Milnor's "Lectures on the H-cobordism theorem". On page 2 he provides the following definitions Definition 1.3. $(W;V_0,V_1)$ is a smooth manifold triad if $W$ is a compact ...
Zest's user avatar
  • 2,382
4 votes
1 answer
164 views

Unreadable lines of Milnor's book

What are the (exact sentence of) Unreadable lines of the following images of Milnor's Lecture on h-cobordism theorem? (pages number: 28, 30, 15 respectively)
C.F.G's user avatar
  • 8,425
0 votes
0 answers
41 views

What is the orientation of the normalized boundary $\partial(M\times N)$ of product manifold?

Assume $M$ and $N$ are two oriented smooth manifold with or without boundaries. Then $M\times N$ is an oriented manifold with corners. Inspired by the theory of cobordism or differential forms, the ...
Hang's user avatar
  • 2,692
1 vote
1 answer
156 views

Which spaces are homotopy equivalent in an h-cobordism?

All the definitions I've found for h-cobordisms define it as a cobordism $(W,M,N)$ such that the inclusions $i_M:M\rightarrow W$ and $i_N:N\rightarrow W$ are homotopy equivalences. But this doesn't ...
Sam Jaques's user avatar
  • 2,020
12 votes
1 answer
354 views

What is Bordism good for?

I am doing a course in algebraic topology, and recently we have defined bordism in the following way: Let $M_1,M_2$ be connected oriented n-dimensional manifolds, $f_i:M_i\rightarrow X$ be continuous ...
Angelo Brillante Romeo's user avatar
0 votes
0 answers
178 views

Orientation of the unit interval

Let the unit interval have postive orientation induced from the standard orientation of $\mathbb{R}$, and let $\{0\}$ and $\{1\}$ be equipped with orientation $+$. Why is $\{0\}$ then an in-boundary ...
deeppurp's user avatar
  • 105
1 vote
1 answer
76 views

Factorization of the orientation map $MU\to H\mathbb{Z}$ through $ku$?

Let $MU$ denote the complex cobordism spectrum and $ku$ the connective cover of the complex $K$-theory spectrum. Is it true that the orientation map $MU\to H\mathbb{Z}$ factors through $ku$?
Tsk's user avatar
  • 207
0 votes
1 answer
34 views

Examples of codim-2 objects in extended TQFT

I'm scratching my head trying to understand what an extended TQFT associates to $(n-2)$-hypersurfaces. Here's some intuition that I've developed. For an $(n-1)$-hypersurface chopped into $(n-2)$-...
Prof. Legolasov's user avatar
6 votes
2 answers
454 views

Stiefel-Whitney numbers of manifolds that are boundaries of non-smoothable manifolds

Can a smooth compact manifold be the boundary of a non-smoothable manifold? If so can any of its Stiefel-Whitney numbers be non-zero? Thom's theorem says that a compact smooth manifold has zero ...
Joe S's user avatar
  • 1,152
1 vote
0 answers
115 views

Spin structure and characteristic classes

I do not know if anyone can help me with these doubts of spin structures and characteristic classes. 1) Is there an orientable manifold that is not spin? 2) Is there a finite group $ G $ such that ...
Erick David Luna Núñez's user avatar
5 votes
1 answer
347 views

Spin structure and bordism

I have some questions about bordism and spin structures on manifolds. If you have any examples or references I would appreciate it. Is there a 3-manifold $ M $, orientable, which does not support 3 ...
Erick David Luna Núñez's user avatar
2 votes
1 answer
74 views

Cobordant Map from May's Book

I have a question about an argument that occurred in the discussion about consequences of Bott periodicity in A Concise Course in Algebraic Topology by P. May on page 221. Here is the excerpt: ...
user267839's user avatar
2 votes
1 answer
55 views

Contruction of a New Manifold via One-Parameter Families of Embeddings

Let $M$, $N$ be two manifolds of dimension $n$. Fix $m>n$. Let $i:[0,1)\times M \to \mathbb{R}^m$, $j:(1,2]\times N \to \mathbb{R}^m$ be embeddings such that for each $s\in[0,1)$, $t\in(1,2]$, $i_s:...
J1U's user avatar
  • 1,014