Questions tagged [arzela-ascoli]

The Arzela-Ascoli theorem is a fundamental result of mathematical analysis giving necessary and sufficient conditions to decide whether every sequence of a given family of real-valued continuous functions defined on a closed and bounded interval has a uniformly convergent subsequence. The main condition is the equicontinuity of the family of functions. The theorem is the basis of many proofs in mathematics. Use this tag alongside (real-analysis).

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Compactness of integral operators

came across this exercise I haven't been able to solve. I saw a very similar exercise (to prove an integral operator with a kernel is compact), but it is just different enough, I think, to warrant its ...
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Constructing an RKHS from a Kernel

I'm reading the book "High Dimensional Statistics" by Martin Wainwright just for fun (also as preparation of my PhD in computer science/Machine Learning). In particular, I'm currently ...
John's user avatar
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On Schoen and Yau's proof of the positive mass theorem: extracting a minimal surface in the limit

I'm reading Schoen and Yau's 1979 paper on the Positive Mass theorem. I'm having trouble understanding the proof of how they extracted a minimal surface as the limit of solutions to the Plateau ...
IsomorphicBunny's user avatar
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Do we have Arzela-Ascoli theorem on the space of all continuous stochastic process?

Let $\Omega$ be a polish space and $(\Omega,\mathcal{F},\mathbb{P})$ be a complete filtered probability space with the filtration generated by the standard Brownian motion. Let the space $U:=L^2\big(\...
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Arzela-Ascoli theorem on $C([a,b];\mathcal{H})$ with $\mathcal{H}$ a Hilbert space

To give some context: I need prove that a family $\mathcal{C}:=\{y: \|y(t)-y(s)\| \leq a(t) - a(s),\ \|y(t)\| \leq b(t)\}\subseteq C([0,T];\mathcal{H})$ is compact, for appropiated $a\in\operatorname{...
p-adic-manimanito's user avatar
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Class of Lipschitz Functions on the unit d-dimensional ball

Let $\mathcal{F} = \{f:\mathcal{B}_d \to \mathbb{R}\;:\; \text{f is Lipschitz}\}$, where $\mathcal{B}_d = \{x \in \mathbb{R}^d\;:\: \|x\|_2 \leq 1\}$ is the unit ball in $d$ dimension. Is the class $\...
rostader's user avatar
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Prove space of strict contractions is closed

I am given the following subset of $C([0,1])$ of continuous real-valued functions on $[0,1]$, satisfying $$ \lvert f(x) - f(y) \rvert < \lvert x - y \rvert, \quad \int_0^1 f(x)^2 dx = 1 $$ (I am ...
pongdini's user avatar
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How to use Arzelà-Ascoli here?

The problem is Suppose $\Omega\subset\mathbb{R}^{n}$ is a bounded open set. Consider the initial-boundary value problem $$\begin{cases} \partial_{t}u(x,t)-\Delta u(x,t)=0 & \text{in}\ \Omega\...
mio's user avatar
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Ascoli-Arzela theorem with incomplete codomain

Wikipedia (https://en.wikipedia.org/wiki/Arzel%C3%A0%E2%80%93Ascoli_theorem#Compact_metric_spaces_and_compact_Hausdorff_spaces) asserts the following (specialized from Hausdorff spaces to metric ...
oggius's user avatar
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Compactness of Differential Operator between Sobolev and $L^p$-spaces

I was wondering under which conditions the (weak) differential operator $D: W^{k,p}(\Omega)\rightarrow L^p(\Omega)$, $u \mapsto Du$ from a Sobolev space into the underlying $L^p$-space (on some open ...
LarsB's user avatar
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Compactness of the immersion $C^1(\bar\Omega)\subseteq C^{\alpha}(\bar\Omega)$

Thanks to all who will answer me! (and sorry for my bad english...) I have to prove the compactness of the immersion $C^1(\bar\Omega)\subseteq C^{\alpha}(\bar\Omega)$ with (respectively) the usual ...
Mirco Cappato's user avatar
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Family of continuous bounded functions has uniformly convergent subsequence

Let $\{f_n\} \subset C(-2,2)$ with $||f_n||_{L^\infty(-2,2)}\leq 1$. Assume for any $x,y\in (-1,1)$, there holds $|f_n(x)-f_n(y)|\leq |x-y|^\alpha $ for some $\alpha\in (0,1)$ whenever $|x-y|>\frac{...
RipCheck's user avatar
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Continuity vs Uniform Continuity vs Pointwise Equicontinuity vs Uniform Equicontinuity

I recently started studying analysis and I'm (again) lost on some near concepts. Intuitively, what is the difference between (i) Continuity, (ii) Uniform (iii) Continuity, Pointwise Equicontinuity and ...
Vinícius Hector's user avatar
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Countability of R in diagonalization argument of Arzela-Ascoli theorem proof

I have an intricate issue with the diagonalization argument used in the proof of Arzela-Ascoli theorem. It goes as follows: So assume that $\scr F$ has these three properties [closed, bounded, ...
Stanislav Veklenko's user avatar
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Some problems in the application of Arzelà–Ascoli theorem

Let $\Omega$ be a bounded domain in $\mathbb{R}^d$ with a smooth boundary. Consider the sequence $\{u_n(\cdot,s)\} \subset L^2(0,T;L^2(\Omega))$ such that $\lVert u_n(\cdot,s) \rVert_{ L^2(\Omega)} $ ...
mnmn1993's user avatar
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Proving that $x_n(t)=\sin\left(n\frac{(t-n^2)}{n+1}\right)$ has subsequence that converges

I'm having some trouble with the following exercise: Let $x_n:[a,b]\to\mathbb R$ be a sequence of functions given by$$x_n(t)=\sin\left(n\frac{(t-n^2)}{n+1}\right)$$ Prove that $x_n$ has a subsequence ...
Eduardo Magalhães's user avatar
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Equicontinuity and uniformly convergent subsequences

I have been trying to grasp equicontinuity lately and with it, the Arzela-Ascoli Theorem. It says that if ${f_k}$ is a sequence of functions on a compact interval that is uniformly bounded and ...
DjuroPucar's user avatar
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Show that $\left\{x\in[0,1] \rightarrow F(x) = \int_{0}^{x} f(t)dt : f\in C([0,1])\text{ and }||f||_\infty \leq B\right\}$ is compact.

I am trying to show that $\mathscr{F}$ is compact, where $$\mathscr{F} = \left\{F(x) = \int_{0}^{x} f(t)dt\mid x \in [0,1],f\in C([0,1]) \text{ and } ||f||_\infty \leq B\right\}$$ To do so, I was ...
The Wanderer's user avatar
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Equivalent conditions of the Arzela-Ascoli theorem

I am taking functional analysis class and we stated the Arzela-Ascoli theorem in the following way: Let $(K, d)$ be a compact metric space, $(Y, \| · \|_{Y} )$ a Banach space and $\mathcal{F} \...
tornt's user avatar
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Compact embedding in $C^{k,2+\alpha}$ space

Could anyone please help me understand the compact embedding of $C^{k,2+\alpha}$ space? I am reading a paper about second order elliptic pde on $C^{k,2+\alpha}$ space. Here is the link of the paper ...
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Arzelà-Ascoli and Compactness

Currently I'm reading baby Rudin and I've come across Arzelà-Ascoli Theorem (Theorem 7.25 in Rudin). I've read online that equicontinuity is exactly the additional property that we need to get ...
Benny's user avatar
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A question related to a family of continuously differentiable functions

Consider $X=C^{1}([-1,1])$, the space of real valued $C^1$ functions defined on the interval $[-1,1]$. Define a norm on $X$ by $||f||:=\sup_{x\in[-1,1]}(|f(x)|+|f'(x)|)$. Consider the set $Y:=\{g:||g||...
neophyte's user avatar
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1 answer
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A question related to a family of continuous functions

Let $X:=\{g:[0,1]\rightarrow \mathbb{R}\:|\:g\in C^1,|g|\leq 10, |g^{'}| \leq 10\}$. I am interested in showing that $X$ is a relatively compact subset of $C([0,1])=\{g:[0,1]\rightarrow \mathbb{R}\:|\:...
neophyte's user avatar
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Prove that the integral operator $T:\mathcal{C}([0,1]) \to \mathcal{C}([0,1])$ is compact

Let $T:\mathcal{C}([0,1]) \to \mathcal{C}([0,1])$ be the operator given by $(Tf)(x) = \int \limits_{0}^{x} e^y \cdot f(y) dy, \: \forall f \in \mathcal{C}([0,1])$. where $\mathcal{C}([0,1])$ is ...
Paul Joh's user avatar
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2 answers
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Some version of the theorem of Arzelà-Ascoli

I have a question concerning the theorem of Arzelà-Ascoli. Let $(f_n)_n:[0,T]\to \mathbb{R}$ be a family of functions so that $(f_n)_n$ is uniformly bounded on $[0,T]$ and $(\frac{d}{dt}f_n)_n$ is ...
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$(X,d)$ separable implies uniformly equicontinuous subset of $C(X,\mathbb{R})$ is separable?

I'm trying to prove a certain class of subsets of $C(X)$ (made into a metric space, equipped with the sup-norm) are separable iff $X$ is (where $X$ is a metric space) and while one direction is easy, ...
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Arzelà–Ascoli propagation theorem

Let $E$ be a metric space and $F$ be a Banach space, $A\subset E$ dense. Let $(f_{n})$ be a squence of continuous and bounden functions from $E$ to $F$ such that the restriction of $f_{n}$ to $A$ ...
Dagoberto Mares's user avatar
2 votes
1 answer
151 views

Space of Lipschitz functions is finite dimensional

Let $(X,d)$ be a compact metric space. Let $V$ be a closed subspace of $C_{\mathbb{R}}(X)$ such that every $f\in V $ is Lipschitz. Show that $V$ is finite dimensional. Hint: Show that $A_n=\{f\in V: |...
Korn's user avatar
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Check the definition of "pointwise bounded under $d$"

The above definition is from Munkre's topology in Section 45.I want to know whether the definition is correct?I think it contains a typo, in place of '$a$' it should be '$x$'... Please clarify this
P.Styles's user avatar
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Uniform convergence via Arzela-Ascoli [closed]

I want to show that $u_\epsilon = -\epsilon \log\left(\frac{ e^{\frac{x}{\epsilon}} + e^{-\frac{x}{\epsilon}}}{e^{\frac{1}{\epsilon}} + e^{-\frac{1}{\epsilon}}} \right)$ converges uniformly to $1-|x|$ ...
HelloEveryone's user avatar
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When is the compact-open topology on homomorphisms locally compact?

Let $X$ and $Y$ be topological groups. The space $\mathrm{Cont}(X,Y)$ of continuous functions will be given the compact-open topology. The subspace $\mathrm{ContHom}(X,Y)$ of continuous homomorphisms ...
Thomas Browning's user avatar
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Set of functions with same Lipschitz constant attains a maximum

Let $E$ be the set of all functions $u : [0, 1] \to R$ such that $u(0) = 0$ and $u$ satisfies a Lipschitz condition with Lipschitz constant $1$. Define φ : E → R according to the formula: $$ \phi(u) = ...
shdwpuppy's user avatar
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1 answer
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Proved that the given set is not closed in the function space $\mathcal{C}([0,1])$

The problem is actually taken from Davidson's Real analysis: Prove that the set $S= \{ F:F(x) = \int_0^x f(t)dt, ||f|| \leq 1 ,\, f\in \mathcal{C}([0,1])\}$ is not closed. This means we should find ...
Kyle H.'s user avatar
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9 votes
2 answers
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When is the compact-open topology locally compact?

Let $X$ and $Y$ be topological spaces, and consider the compact-open topology on $C(X,Y)$, which is generated by open sets of the form $$\{\text{continuous }f\colon X\to Y:f(K)\subseteq U\}\text{ for ...
Thomas Browning's user avatar
3 votes
1 answer
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Extraction of pointwise convergenct subsequence using Arzela-Ascoli theorem

Let $f_n:[a, b] \rightarrow \mathbb{R}$ be a sequence of continuous functions which is uniformly bounded i.e. $||f_n||_{L^{\infty}} \leq M <\infty$ and satisfies $f_n(a)=A$ for all $n\in \mathbb{N}....
Celestina's user avatar
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Solution verification of a proof of the Peano existence theorem, using Arzela-Ascoli

$\newcommand{\o}{\mathcal{O}}\newcommand{\d}{\,\mathrm{d}}$I believe what I was required to show is a general version of the Peano existence theorem. Let $\o\subseteq\Bbb R\times\Bbb R^n$ be open and ...
FShrike's user avatar
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A version of Ascoli-Arzelà using modulus of continuity and nth entropy numbers

The classical Ascoli-Arzelà theorem could be stated as follows: Let $K$ be a compact metric space and let $\mathcal{H}$ be a bounded subset of $C(K)$ - the space of continuous functions over $K$ with ...
Daniel Akech Thiong's user avatar
3 votes
1 answer
436 views

Sequence of contraction mapping and convergence of fixed point

Let $(𝑆,||_{\infty})$ be a metric space and $𝑇 : 𝑆→𝑆$ be a function mapping S into itself. $S$ is a space of bounded and Lipschitz continuous function. For each $𝑛\inℕ$, $\tau_{n}\in T$ satisfies ...
Anonymously lost student's user avatar
3 votes
1 answer
122 views

Variation of Ascoli-Arzelà theorem for $C^1$ functions

Let $\Omega \subset \mathbb{R}^n$ be an open set and let $(f_n)_n \subset C^1(\Omega)$ such that $\exists C > 0, \, \sup_{x \in \Omega} |f_n(x)| + \sup_{x \in \Omega} |Df_n(x)| \le C$ for all $n \...
Hilbert1234's user avatar
2 votes
1 answer
257 views

Arzelà–Ascoli $\implies$ Dini's theorem

If $K$ is compact Hausdorff then $f_n\in C_\mathbb{R}(K)$ with $f_{n+1}(x)\lt f_n(x) \quad \forall x\in K$ and $f_n$ converges pointwise to a continuous limit $\implies$ $f_n$ converges uniformly I ...
janes's user avatar
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3 votes
1 answer
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Is the integral operator $I: L^1([0,1])\to L^1([0,1]), f\mapsto (x\mapsto \int_0^x f \,\mathrm d\lambda)$ compact?

Is the integral operator $I: L^1([0,1])\to L^1([0,1]), f\mapsto (x\mapsto \int_0^x f \,\mathrm d\lambda)$ compact? For $I: L^p([0,1]) \to C([0,1])$ with $p\in (1,\infty]$ this can be shown quite ...
Michael's user avatar
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2 votes
3 answers
81 views

Given a bounded sequence in $L^1([a,b])$, is $(t\mapsto \int_a^t f_n \,\mathrm d\lambda)_n$ equicontinuous?

We are given a bounded sequence $(f_n)_{n\in \mathbb N}$ in $L^1([a,b])$. This means there is some $M>0$ such that for all $n\in\mathbb N$, $\int_{[a,b]} |f_n|\,\mathrm d\lambda \leq M$. I wonder ...
Michael's user avatar
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4 votes
0 answers
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Arzelà-Ascoli for $C_b(0,1)$? Or more generally, why is that continuous functions "live most naturally" on compact spaces?

I’m wondering if there is a version of Arzelà-Ascoli for continuous functions on not-necessarily compact metric spaces $X$, i.e. a characterization of the compact subsets of $C_b(X)$ for $X$ not-...
D.R.'s user avatar
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4 votes
1 answer
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What's the role of domain compactness in the Ascoli-Arzela theorem?

The problem From what I've read in the literature I get the idea that domain compactness is quite crucial in the theorem, and yet looking at the proof it seems to me as an unnecessary assumption. I ...
Khalid Wenchao Yjibo's user avatar
1 vote
0 answers
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Continuous extension in the proof of Arzela - Ascoli theorem

I'm reading a proof of Arzela - Ascoli theorem (complex analysis version) and I've come to the part where we want to extend a function that is defined on one set to the closure of that set. The ...
blue's user avatar
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1 answer
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Question about applying a combination of Arzela Ascoli and Schauder (also called Krasnoselskii)

Consider the equation \begin{align} 3u(x) = x + u^2(x) + \int_0^1 | x - u(y) |^{1/2} \,dy \qquad (\ast) \end{align} Using Krasnoselskii's fixed point theorem, show that $(\ast)$ has a continuous ...
infinity558's user avatar
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0 answers
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If $(\varphi_n)$ is uniformly equicontinuous and $0\le f_n\le-3\ln\varphi_n$, show that $(f_n)$ is equicontinuous at $0$

Let $d\in\mathbb N$, $(\varphi_n)_{n\in\mathbb N}\subseteq C(\mathbb R^d)$ be uniformly equicontinuous with $\varphi_n(0)=1$ and $\varphi_n>0$ for all $n\in\mathbb N$ and $(f_n)_{n\in\mathbb N}\...
0xbadf00d's user avatar
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How can we derive the Arzelà-Ascoli theorem for a $\sigma$-compact space from the ordinary Arzelà-Ascoli theorem?

Let $X$ be a compact topological space and $\mathcal F\subseteq C(X,\mathbb C)$. By the ordinary Arzelà-Ascoli theorem, we know that If $\mathcal F$ is relatively compact in the uniform topology, ...
0xbadf00d's user avatar
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Pointwise convergence of $F_n(t) = \max_{y \in \mathbb R^N} \int_{B_t(y)} |u_n|^2 \ dx$

The following is a claim in some lecture notes I am reading: Consider a bounded sequence $(u_n) \subset H^1(\mathbb R^N)$ with $\|u_n\|_{L^2} \to \lambda > 0$. For $n \in \mathbb N$, the ...
Danilo Gregorin Afonso's user avatar
2 votes
1 answer
510 views

Set of functions on $C[0,1]$ with bounded derivative is compact

Just want to check if my proof works or not. Question: Given $K > 0$, determine if the set \begin{equation*} Y = \{f \in C^1[0,1], f(0) = 0, \Vert f'\Vert_\infty\leq K\} \end{equation*} is ...
Rishi's user avatar
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