Questions tagged [algebras]

For questions about algebras, their properties, and their structures. Use [tag:algebra-precalculus] or [tag:abstract-algebra] if your question is about algebra, not algebras.

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A question about the minimal number of operations required to obtain a matrix with generic eigenvalues

Let $A,M \in \operatorname{Mat}_n(\mathbb{C})$ be $n \times n$ matrices such that $M$ is invertible and $MA \neq AM$. Consider the algebra $\mathcal{A}$ generated by the set $\{I,A,MAM^{-1}\}$, where $...
hugo's user avatar
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2 votes
1 answer
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Homotopy of maps of $A_{\infty}$-algebras

Let $f, g: A \to B$ be maps of $A_{\infty}$-algebras. What is the correct (explicit) notion of a homotopy between $f$ and $g$? This is given in the expository paper of Keller in terms of maps of the ...
Jack Davidson's user avatar
1 vote
0 answers
57 views

On the homomorphism as $M_n(A)$-modules.

I'm trying to prove that, if $A$ is an Algebra over a field $F$, and $U,V$ are $A-$modules. Then any element in $Hom_{M_n(A)}(U^n, V^n)$ (recall that $U^n, V^n$ is the set of size $n$ vectors as an $...
Nestor Bravo's user avatar
0 votes
0 answers
21 views

Turning a subalgebra into an ideal by changing the algebra it is contained in

Let $B$ be an (not necessarily unital) algebra and $A \subseteq B$ a subalgebra. Is there some sort of quotient $C$ of $B$ (or any other interesting construction not necessarily found by taking ...
Francisco's user avatar
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1 answer
52 views

Semisimplicity implies separability for a perfect field

Let $k$ be a field, $A$ a finite-dimensional semisimple $k$-algebra. If $k$ is a perfect field (every finite field extension of $k$ is seperable), then $A$ is separable. I know a proof that uses the ...
Margaret's user avatar
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3 votes
1 answer
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Does there exist a topological power-associative non-metric unital algebra $V$ such that $\exp x$ is defined for all $x\in V$?

From what I understand, we normally define the operator $\exp$ only on unital Banach algebras, because the triangle inequality ensures that the infinite series converges: $$\lim_{n\to\infty}\left\|\...
Kyky's user avatar
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$\operatorname{Hom}_A(M, N)$ and $M^* \otimes_A N$

If $U$ and $V$ are vector spaces over some field $k$ and $U$ is finite dimensional with basis $\{u_i\}_i$, then we know that $\def\Hom{\operatorname{Hom}}$ $$\Hom_k(U, V) \to U^* \otimes_k V,\quad f \...
Bubaya's user avatar
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22 votes
6 answers
3k views

Proof the quaternions are 4-dimensional?

The quaternions can be defined as $$\mathbb{R}\langle X,Y\rangle/(X^2+1,Y^2+1,XY+YX)$$ From these relations, it is relatively easy to prove that $1,X,Y,XY$ span the quaternions over $\mathbb{R}$. But ...
Zoe Allen's user avatar
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Inferring classification of Clifford algebras from classification of Clifford modules

Let $Cl_n$ be the Clifford algebra (over reals) $$ Cl_n = T^{*}\mathbb{R}^n/\langle v\otimes v - q(v) \rangle. $$ There is a periodic table of $K$-representations of $Cl_n$, i.e. $\mathbb{R}$-linear ...
Hyeongmuk LIM's user avatar
3 votes
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Equivalent definitions of Hopf algebras

Recently, I started to study the book Hopf algebras by Moss Sweedler, in such book, given a coalgebra $(C,\Delta,\epsilon)$ and an algebra $(A,\mu,\eta)$, the autor defines the convolution of two ...
ferolimen's user avatar
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2 votes
1 answer
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Jordan-Holder theorem for group algebras

I'm currently studying the Jordan-Holder theorem for modules and representations of associative algebras over fields. I was wondering if there is a way to prove the Jordan-Holder theorem for finite ...
Lorenzo Ferraiuolo's user avatar
2 votes
1 answer
62 views

Definition of splitting field: Why do we require centrality?

Let $k$ be a field. Let $D$ be a division algebra over $k$. Call a field extension $K/k$ a splitting field for $D$ if there exists a positive integer $n$ such that $D\otimes_k K\cong M(n\times n,K).$ ...
Margaret's user avatar
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1 answer
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Complete Subalgebras and Dense Subalgebras of Complete Boolean Algebras are Regular Subalgebras

In Thomas Jech's Set Theory book, he states that If $A$ is a complete subalgebra of a complete Boolean algebra $B$ then $A$ is a regular subalgebra of $B$. Also, if $A$ is a dense subalgebra of $B$ ...
Ali Dursun's user avatar
1 vote
0 answers
112 views

Finding the discriminant of a quaternion algebra

Consider the totally real number field $ F=\mathbb{Q}(\zeta_{10}+\zeta_{10}^*) $. Consider the quaternion algebra $ Q=(\frac{-1,-1}{F}) $. How do I compute the discriminant of this algebra? I gave ...
Ian Gershon Teixeira's user avatar
1 vote
1 answer
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On the property of a ring modulo its Jacobson radical being a division ring

Let $(R,\mathfrak m)$ be a commutative Noetherian local ring. Let $A$ be a finitely generated associative $R$-algebra. Let $x\in \mathfrak m$ be a non-zero-divisor on $A$ such that $xA\neq A$. If $A/J(...
uno's user avatar
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1 vote
0 answers
60 views

Definition of finite-dimensional 'self-dual algebra' over a field

In some informal notes that are not publicly available and for which I do not have permission to reproduce here, there is a reference to a 'finite-dimensional self-dual algebra over a field $K$'. I ...
user829347's user avatar
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1 vote
0 answers
81 views

What is precisely an anti-linear anti-involution?

Given an arbitrary $\mathbb{C}$-algebra $A$, what should be required from a function $f:A\to A$ for it to be an anti-linear anti-involution? As I understand “anti-linear” for $A$ as a vector space ...
Matthew Willow's user avatar
1 vote
0 answers
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A sort of "minimal presentation " for a local ring essentially of finite type over a field

Let $k$ be a field of characteristic $0$. Let $(R,\mathfrak m)$ be a local ring essentially of finite type over $k$ (https://stacks.math.columbia.edu/tag/07DR). Then, $R$ is the homomorphic image of ...
strat's user avatar
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2 votes
1 answer
50 views

In what sense is the Temperley-Lieb algebra related to the Braid group?

Question: In what sense is the Temperley-Lieb algebra $ TL_n $ related to (a representation of?) the braid group $ B_n $? For example, is $ TL_n $ the algebra of matrices generated by the image of $ ...
Ian Gershon Teixeira's user avatar
2 votes
0 answers
51 views

What is the dual Hopf algebra of T(V)?

I am reading "Geometric versus Non-Geometric Rough Paths" by Martin Hairer and David Kelly. I don't know much about Hopf algebras but $T(V)$ is the one example I'm comfortable with so far ...
Theo Diamantakis's user avatar
1 vote
0 answers
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I need help to prove this inequality, I'm not really sure what the question means.

Question Let n be a positive integer and $x>y$. Prove that $$\frac{x^n-y^n}{x-y}>ny^{n-1}$$ By choosing suitable values of x and y, further prove than $$\left(1+\frac{1}{n}\right)^n<\left(1+\...
Namura's user avatar
  • 121
1 vote
0 answers
22 views

An associative k-algebra whose enveloping algebra $A \otimes_k A^{op}$ is not iso to $A \otimes_k A$

I'm trying to find an example of a finite-dimensional $k$-algebra $A$ for some field $k$, ideally $\mathbb R$, such that $A \otimes_k A \not\cong A \otimes_k A^{op}$. A lot of algebras have $A \cong A^...
wlad's user avatar
  • 8,155
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0 answers
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Let a, b, c, d be complex numbers satisfying $a+b+c+d=a^3+b^3+c^3+d^3=0$. Prove that a pair of the a, b, c, d must add up to 0 [duplicate]

When doing this I tried using the identity $x^3+y^3+z^3=3xyz$ if $x+y+z=0$ I take $x=a$, $y=b$, and $z=c+d$ So $a+b+(c+d)=0$ $a^3+b^3+(c+d)^3=3ab(c+d)$ $a^3+b^3+c^3+d^3+3cd(c+d)=3ab(c+d)$ $(a^3+b^3+c^...
Namura's user avatar
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1 answer
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Is the Galois action on $k$-algebra homomorphisms transitive?

I am reading the proof of Proposition 2.19 in Liu's book on Algebraic Geometry and Arithmetic Curves. The proposition is as follows: Let $X$ be an algebraic variety over $k$, and let $K / k$ be a ...
stillconfused's user avatar
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1 answer
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Is $x\mapsto 1_A\otimes x:V\rightarrow A\otimes V$ injective for $K$-algebra $A$ and $K$-vector space $V$?

Let $K$ be a field, $A$ be a commutative unital $K$-algebra and $V$ be a $K$-vector space. Is the $K$-linear map $$x\mapsto 1_A\otimes x:V\to A\otimes V$$ injective? The specific case that I am ...
user829347's user avatar
  • 3,304
-1 votes
1 answer
82 views

Is there more than one notion of algebras? [duplicate]

I know that an algebra is an algebraic structure, that can be seen as a vector space with a multiplication operation or as a ring with a vector space structure. However, in measure theory we define an ...
Labi's user avatar
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1 answer
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Question about a proof that simple algebras are semi-simple

In the book Clifford Algebras: An Introduction by D. J. H. Garling, Theorem 2.7.2 states that a finite-dimensional simple unital algebra $A$ is semi-simple. My question is specifically about the proof ...
zbrads2's user avatar
  • 1,054
1 vote
1 answer
64 views

$R[x]$-algebra structure that on $R[y]$ seen as quotient of $R[x,y]$

In a broader exercise about the fibered product of schemes, I'm given a ring (commutative and unitary) $R$ and the following ring homomorphism: $\begin{align*} R[x]&\to R[y]\\ x&\mapsto y^2\\ \...
Avenavolo's user avatar
  • 304
3 votes
1 answer
81 views

Tensor Products of R-Algebras from Atiyah and Macdonald

I know this part of Atiyah and Macdonald has a typo, but that is not what this question is about. Let $R$ be a commutative ring and $S$ and $T$ be $R$ algebras. I am trying to show that $S\otimes_R T$ ...
Chris's user avatar
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0 votes
0 answers
37 views

Enumerating monomorphisms of finite-dimensional $\mathbb{F}_2$-algebras

I want to enumerate the monomorphisms of finite-dimensional $\mathbb{F}_2$-algebras. Of course, each such monomorphism is a linear map between finite-dimensional $\mathbb{F}_2$-vector spaces, and so ...
user829347's user avatar
  • 3,304
0 votes
0 answers
20 views

conditions that an annihilator banach algebra will be a dual banach algebra

a banach algebra $\frak{A}$ is called an annihilator algebra if, for arbitrary closed left ideal $\frak{L}$ and closed right adeal $\frak{R}$ in $\frak{A}$, both of the following conditions are ...
Amirhossein Haddadian's user avatar
4 votes
1 answer
197 views

Finite order automorphisms of semi simple lie algebras (Kac Lemma 8.1)

I am currently reading Kac's book on infinite dimensional Lie algebras and have some trouble with Lemma 8.1. The setup is as follows: Let $\mathfrak{g}$ be a finite dimensional semisimple Lie algebra ...
LT1918's user avatar
  • 172
1 vote
1 answer
157 views

What is the difference between an $FG$-module and a group algebra?

I am beginning the study of representation theory, and am having trouble understanding the difference between an $FG$-module and a group algebra of $G$. This seems to be the only other question on ...
Clyde Kertzer's user avatar
1 vote
1 answer
44 views

Voight's Quaternion Algebras, Corollary 7.1.2

I am reading the proof that if $B$ is a central simple $F$-algebra of dimension $4$ ($\operatorname{char}(F) \neq 2$), then $B$ is a quaternion algebra in John Voight's book Quaternion Algebras (...
stillconfused's user avatar
0 votes
1 answer
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If $G$ is cyclic of order n, $\mathbb{Q}[G]\cong \oplus_{d|n}\mathbb{Q[\xi_d]}$

I am trying to find a proof of this result. If $G$ is cyclic of order n, $\mathbb{Q}[G]\cong \oplus_{d|n}\mathbb{Q[\xi_d]}$. I think the proof will involve the use of characters of finite abelian ...
ABC's user avatar
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1 vote
1 answer
37 views

Why quotient ring $ k[x_1,...x_n]/I(Y)$ is k - algebra?

Let $Y \subseteq \mathbb{A}^n $ and $f,g \in k[x_1,...,x_n]$ have the same restriction to $T$ if and only if $f-g \in I(Y)$. Why the quotient ring $ k[x_1,...x_n]/I(Y)$ is k - algebra? Definition k-...
Artur111's user avatar
1 vote
1 answer
45 views

Examples of rings by their relation to projective coverings

A projective covering of an $R$-module $M$ is an epimorphism $\pi:P\rightarrow M$ s.t. $P$ is a projective $R$-module and $\textrm{Ker}(\pi)$ is co-essential in $P.$ The existence theorem for ...
Maxim Nikitin's user avatar
1 vote
0 answers
36 views

$𝑅$ a $\mathbb C$- algebra and $𝑀$ a simple $𝑅$-module with a countable basis. Then $\textrm{End}_R(M)\cong \mathbb C.$ [duplicate]

Sсhur's lemma states: Lemma. Let $R$ be a finite-dimensional algebra over an algebraically closed field $K$ and let $M$ be a simple $R$-module. Then $\textrm{End}_R(M)\cong K.$ Proof. Since $M$ is ...
Maxim Nikitin's user avatar
3 votes
1 answer
45 views

The pre-image sigma algebra of the greatest integer function [x].

The first exercise in my Measure and Integration book is to find the pre-image sigma algebra of various functions, namely $f(x)=x^3$, $x^2$ and $[x]$. You can correct me if I'm wrong but I'm fairly ...
murpw2011's user avatar
  • 305
16 votes
1 answer
708 views

Does the product rule imply the chain rule?

Let $\mathbb{F}$ be a field, and consider $\mathbb{F}^\mathbb{F}$ as an algebra over $\mathbb{F}$ with the standard function multiplication. Let $D$ be a derivation on a subalgebra of $\mathbb{F}^\...
mathlander's user avatar
  • 3,905
0 votes
1 answer
275 views

Einstein notation with three indexes

I met in a book a mention of Sklyanin algebra for $(S_0,S_1,S_2,S_3)$: $$\{S_0,S_{\alpha}\}=\varepsilon_{\alpha\beta\gamma}S_{\beta}S_{\gamma}(J_{\beta}-J_{\gamma})$$ $$\{S_{\alpha},S_{\beta}\}=\...
islam's user avatar
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2 votes
1 answer
191 views

Is there a finite-dimensional algebra over $\mathbb C$ with no zero divisors?

Every non-trivial finite dimensional associative algebra over an algebraically closed field has zero divisors. Is there a non-trivial finite dimensional non-associative algebra over $\mathbb C$ or ...
Subscribe for more Minecraft's user avatar
2 votes
1 answer
110 views

A division quaternion algebra in which the integral elements don't form a ring

I wish to find a division quaternion algebra $B$ over $\mathbb{Q}$ and elements $\alpha, \beta\in B$ such that $\alpha, \beta$ are integral over $\mathbb{Z}$ but both $\alpha + \beta$ and $\alpha \...
rationalbeing's user avatar
0 votes
1 answer
109 views

Module over algebra is free iff it has a basis

$ \newcommand{\cn}{\colon} \newcommand{\<}{\leqslant} \newcommand{\>}{\geqslant} \newcommand{\ss}{\subset} \newcommand{\k}{\mathrm{k}} \newcommand{\gr}{\mathrm{gr}} \newcommand{\R}{\mathrm{R}} \...
Dmitry's user avatar
  • 145
0 votes
0 answers
94 views

Rees algebra is finitely generated if associated graded algebra is

$ \newcommand{\cn}{\colon} \newcommand{\<}{\leqslant} \newcommand{\>}{\geqslant} \newcommand{\ss}{\subset} \newcommand{\k}{\mathrm{k}} \newcommand{\gr}{\mathrm{gr}} \newcommand{\R}{\mathrm{R}} \...
Dmitry's user avatar
  • 145
2 votes
0 answers
118 views

Algebra is noetherian if associated graded algebra is noetherian

$ \newcommand{\cn}{\colon} \newcommand{\<}{\leqslant} \newcommand{\>}{\geqslant} \newcommand{\ss}{\subset} \newcommand{\gr}{\mathrm{gr}} $ Let $A$ be associative commutative algebra with unity ...
Dmitry's user avatar
  • 145
1 vote
0 answers
103 views

Uniqueness of direct product of two $A$-modules

$ \newcommand{\cn}{\colon} \newcommand{\<}{\leqslant} $ Let $k$ be a field. Def. Algebra $A$ is associative ring with unity and a ring homomorphism $f\cn k\to A$ such that $f(1_k)=1_A$ and $f(a)x=...
Dmitry's user avatar
  • 145
0 votes
0 answers
35 views

When an Isomorphism between two algebras is an equivalence?

I'm currently involved in the study of algebraic structures, and there's a concept that seems to appear every so often. Given an Algebra $ A=<A,F_i> $ an isomorphism $ f $ is a bijective ...
LUCA SCARPELLI's user avatar
1 vote
1 answer
43 views

Subring is integral over finitely generated subalgebra

Let $R \subseteq S$ be unital rings and let $G \leq \mathrm{Aut}_R(S)$ be a finite group of automorphisms of $S$ as an $R$-algebra. We define the invariant subring: $$S^G = \{a \in S \mid \forall \...
Mabel Najdovska's user avatar
1 vote
1 answer
81 views

The forgetful functor $U:T-Alg\rightarrow C$ preserves limits

Suppose $F$ is an endofunctor of a complete category $C$. Let $F-Alg$ be the category that has objects the pairs $(X, \ a:FX\rightarrow X)$ where $X$ is an object in $C$, and that has morphisms $f:(X,...
Meneer-Beer's user avatar

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