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Questions tagged [algebraic-numbers]

Use this tag for questions related to numbers that are roots of a non-zero polynomial in one variable with rational coefficients.

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7 votes
2 answers
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What's the structure of the sequence of fields $\mathbb Q(\alpha^n)$?

Given an algebraic number $x$ and a natural number $n>0$, we define the $n$th powerfield of $x$ as $\mathbb Q(x^n)$. $$\mathbb Q(x),\; \mathbb Q(x^2),\; \mathbb Q(x^3),\; \mathbb Q(x^4),\; \mathbb ...
mr_e_man's user avatar
  • 5,864
8 votes
1 answer
359 views

Does there exist a power series which sends every algebraic number in its radius of convergence to a rational number?

Section 1.3 of https://swc-math.github.io/aws/2008/08BeukersNotesDraft.pdf claims there exists a non-constant power series $f(x)$ with positive radius of convergence $\rho,$ such that for any ...
Michael Barz's user avatar
6 votes
2 answers
387 views

How to determine multiplicative dependence of two algebraic numbers?

Given a pair of algebraic numbers $x,y \in \mathbb F^*$, where $\mathbb Q \subseteq \mathbb F \subset \mathbb C$, how can we find (or prove that there isn't) a pair of exponents $m,n \in \mathbb Z$ (...
mr_e_man's user avatar
  • 5,864
2 votes
0 answers
56 views

Example of non supersingular Weil number

This question aims mainly at some misconception I may have regarding the formalism of Weil numbers. These are defined as some algebraic integers with a fixed complex modulus under all possible ...
Suzet's user avatar
  • 5,571
3 votes
1 answer
63 views

We know existence of Transcendental raised to Algebraic Irrational equals rational, but what about opposite?

Introduction: If we take $a=2^\sqrt[3]{2}$ which is transcendental by Gelfond-Schneider Theorem, and $b=\sqrt[3]{4}$ which is algebraic irrational because it is root of monic-irreducible polynomial ...
Math Admiral's user avatar
  • 1,554
1 vote
0 answers
34 views

Degree of sum or product of linearly independent algebraic numbers.

Let $\alpha,\beta \in \mathbb{A}$ such that $\alpha,\beta$ are linearly independent over $\mathbb{Q}$ and $deg(\alpha)=k_{1}, deg(\beta)=k_{2}$. Can I deduce that $deg(\alpha \beta)=lcm(deg(\alpha),...
Math Admiral's user avatar
  • 1,554
4 votes
1 answer
106 views

Baby Rudin Chapter 2, Exercise 2 proof check

I am currently self-studying Baby Rudin and I have written what I think is a solution to Exercise 2 of Chapter 2. It reads: $\textbf{Exercise 2}:$ A complex number $z$ is said to be algebraic if there ...
Casey Malone's user avatar
3 votes
3 answers
77 views

Notable algebraic numbers with high minimal polynomial degree

In this question I'll be referring to certain numbers as "notable". To remove the possible objection of this being opinion-based, we may define "notable" to mean someone has ...
Robin's user avatar
  • 3,950
1 vote
0 answers
106 views

Does there exist a number $z$ algebraic over $ℚ$ and a prime $p$ such that $\operatorname{MinDeg}(p,z)\notinℕ$?

Let $\mathbb P$ denote the set of primes. Let $\operatorname{A^*}$ denote the set of (complex) numbers algebraic over $ℚ$ Let $p\in\mathbb P$ and $z,w\in\operatorname{A^*}$ Let $p^ℤ[z]$ denote the set ...
Simon M's user avatar
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7 votes
1 answer
199 views

Factorization and irreducibilty for $x^n-2x^m+1$ trinomials.

I have encountered a weird phenomenon while trying to solve a problem on Reddit. Here is the phenomenon. Let $a>b \in \mathbb{N}$ and $p_{(a,b)} = x^a - 2x^b + 1$ It seems that if $gcd(a,b,c,d) = 1,...
Vatsa Srinivas's user avatar
4 votes
2 answers
205 views

Can $x\sin(x)$ be algebraic when it is not $0$?

It's easy to show (using the Lindemann-Weierstrass theorem) that, for $x\ne 0$, at least one of $x$ and $\sin(x)$ must be transcendental. But what about $x\sin(x)$? After all, the product of two ...
Ted Hopp's user avatar
  • 645
9 votes
0 answers
300 views

Is there an elementary proof that $2^{\sqrt{2}}$ is irrational?

Is there an elementary proof that $2^{\sqrt{2}}$ is irrational? The Gelfond-Schneider theorem states that if $a$ and $b$ are complex algebraic numbers such that $a \not\in \{0, 1\}$ and $b$ is ...
marty cohen's user avatar
0 votes
0 answers
60 views

Show that $\pi$ is not algebraic over the field $\mathbb A$ of algebraic numbers.

This is one of the exercises in my abstract algebra book (Nicholson) and it's just the title: Show that $\pi$ is not algebraic over the field $\mathbb A$ of algebraic numbers. All I know what to do ...
iwjueph94rgytbhr's user avatar
0 votes
1 answer
67 views

Confused about lemma in Ivan Niven's Irrational Numbers about conjugate elements in a number field

Page 136 of Ivan Niven's "Irrational Numbers" states, "Lemma 10.4: Let $\alpha$, $\beta$ be algebraic numbers in a field $K$ of degree $h$ over the rationals. If the conjugates for $\...
hamburglar's user avatar
1 vote
1 answer
42 views

On Roots of Non-Abelian Extentions of Q and the Abelian Closure of Q

This is somewhat nagging me. I just with to run it by some one cause it seems slightly unintuitive to me (in some regards). Let us consider $r$ to be an algebraic number in $\mathbb{C}$ not in $\...
user13953's user avatar
2 votes
1 answer
84 views

Equivalent of complex analysis over the algebraic numbers

I was wondering what would happen if we wanted to do "complex-like" analysis but, instead, of $\mathbb{C}$, we would use the simplest (in terms of inclusion) characteristic $0$ algebraically ...
Weier's user avatar
  • 793
2 votes
0 answers
109 views

Can three antiprisms (uniform polyhedra) fit exactly around an edge, leaving no gaps?

Let $\tau=2\pi$ $=360^\circ$. An $n$-gon antiprism has dihedral angles $$\theta_n = \arccos\left(-\frac1{\sqrt3}\tan\frac\tau{4n}\right)$$ (where an $n$-gon meets a triangle) and $$\phi_n = 2\arccos\...
mr_e_man's user avatar
  • 5,864
1 vote
0 answers
53 views

Are there any generalizations of continued fractions to approximations of other polynomial equations? [closed]

One of the more interesting results about continued fractions, is that the continued fraction representation of a number repeats if and only if the number is a solution to a polynomial of degree 2 (or ...
levav ferber tas's user avatar
0 votes
3 answers
65 views

Criterion for subfield of $ \mathbb{C} $ to be dense

Question: Is it true that a subfield $ K $ of $ \mathbb{C} $ is dense if and only if the roots of unity in $ K $ are dense in the unit circle? Context: I was thinking about the infinite degree ...
Ian Gershon Teixeira's user avatar
3 votes
0 answers
50 views

Example of a non-reciprocal polynomial with nontrivial multiplicative relations between its roots

I'm trying to find an example of a polynomial with some special properties, or an idea of why there can't be one, if that's the case. Here's my setting: Let $p(x)\in\mathbb{Z}[x]$ be an irreducible, ...
Ash's user avatar
  • 51
4 votes
1 answer
210 views

Question about Rudin's PMA, Chapter 2 Exercise 2

I know that there are many questions related to this exercise that have been answered, and I have found a couple of different solutions to this exercise as well. But the solutions usually ignore the ...
Beerus's user avatar
  • 2,779
2 votes
1 answer
73 views

Rational dependences between algebraic numbers not closed under Galois conjugation [closed]

Let $p \in \mathbb{Z}[x]$ be an irreducible polynomial of degree $d > m > 1$ and $\alpha_1, \ldots, \alpha_m$ be a (strict) subset of all the distinct roots of $p$. Can the value of $c_1\alpha_1 ...
toghrul's user avatar
  • 41
3 votes
0 answers
48 views

Known "families" of algebraic numbers

Contrary to simple transcendental extensions of $\mathbb{Q}$, which are necessarily isomorphic to a field of rational functions over $\mathbb{Q}$, simple algebraic extensions are very varied - which ...
Gauss's user avatar
  • 2,685
0 votes
0 answers
25 views

Primes in quadratic rings that are not UFD's [duplicate]

In a quadratic ring $\mathbb{Z}[\sqrt{d}]$ that is not a UFD, is there a simple proof that if an element has a norm that is a prime integer, then that element of the ring is prime, not merely ...
akay's user avatar
  • 9
0 votes
0 answers
28 views

Primitive Elements and Bases of Fields [duplicate]

Good people! I'm trying to prove a certain something, and I've reached a point where the whole thing will be complete if I can just prove the following lemma, which I'm actually not entirely certain ...
StormyTeacup's user avatar
  • 2,052
0 votes
1 answer
53 views

is the degree of an algebraic number in a fixed algebraic number field bounded?

Let $K$ be an algebraic number field $K=\mathbb Q(\theta)$ with $\theta$ being a root of a minimal polynomial $f(x)$ of degree $n$ with rational coefficients. Let $\alpha$ be an arbitrary element of $...
mathreader's user avatar
  • 2,062
3 votes
0 answers
48 views

Classification of linear algebraic subgroups of $GL(2,\overline{\mathbb{Q}})$

In the article "An algorithm determining the difference Galois group of second order linear difference equations" by Peter Hendriks from 1998, Lemma 4.1 is a consequence of, among other ...
oneequalstwo's user avatar
2 votes
0 answers
70 views

Guessing algebraic number by its binary digits

Positive integers $d$, $H$ are given. It's known that $r\in(0,1)$ is such that $p(r)=0$ for some nonzero $p\in\mathbb Z[x]$ with $\deg p\leq d$ and coefficients $c_i$, such that $|c_i|\le H$, $i=0,\...
te4's user avatar
  • 235
1 vote
0 answers
76 views

Is the statement of Baker's Theorem on wikipedia inaccurate?

The Wikipedia article on Baker's theorem states it as follows: If $\lambda_1,\ldots,\lambda_n\in\mathbb{L}$ are linearly independent over the rational numbers, then for any algebraic numbers $\beta_0,...
Frousse's user avatar
  • 434
5 votes
0 answers
82 views

Which numbers can be a minimal value of a polynomial with integer coefficients?

Problem. Let $P$ be a polynomial with integer coefficients and consider $m(P) = \min_\limits{x\in\mathbb{R}} P(x)$. The problem is to describe all possible values of $m(P)$. Necessary condition. If $m(...
Pavel Gubkin's user avatar
  • 1,116
3 votes
1 answer
125 views

$p$-adic Algebraic Number Fields: Their Primes and Units

So I've been going through Kurt Hensel's old German classic Theorie der algebraischen Zahlen, and I've reached the point where he begins discussing $p$-adic algebraic number fields $\mathbb{Q}(p , \...
StormyTeacup's user avatar
  • 2,052
1 vote
1 answer
95 views

Prove $\sqrt{2}+\sqrt{3}+\sqrt{5}+...+\sqrt{p_{n}}$ is irrational, where $p_{n}$ is the nth prime.

My motivation is making general proof , instead of trying to prove special cases. To which branch of mathematics does my question belong? I am highly interested in irrational numbers. Is it good idea ,...
Math Admiral's user avatar
  • 1,554
1 vote
0 answers
96 views

Non-positively algebraic number

Let us say that an algebraic number $\alpha \in \mathbf{R}$ is non-positively algebraic if it is the root of a monic polynomial $p(x) = x^n + a_{n-1}x^{n-1} + a_{n-2}x^{n-2} + \dots + a_1 x + a_0$ ...
Jean Charles's user avatar
0 votes
0 answers
73 views

Why does this entropy equation $H(p) = H(2p - p^2)$ have an algebraic solution?

The recent breakthrough paper of Justin Gilmer on the Union-Closed Set conjecture contains this mysterious coincidence: Let $$H(p) := - p \log p - (1 - p) \log (1- p)$$ be the entropy of a Bernoulli ...
John Jiang's user avatar
1 vote
0 answers
114 views

Why is the image of an element in $\mathbb Q(\zeta_m, \zeta_p)$ under an automorphism of $\mathbb Q(\zeta_m)$ defined?

This is a part of page 214 in Ireland and Rosen's "A Classical Introduction to Modern Number Theory". $p$ is a prime coprime to $m$, $\zeta_m = e^{\frac{2\pi i}m}$, $D_m$ is the ring of ...
רוי רז's user avatar
0 votes
0 answers
35 views

Why does $w^{p^n} - w \in P^2$ imply $w\in P^2$ for $P$ prime?

The corollary mentioned: This is proposition 13.2.5 from Ireland and Rosen's "A Classical Introduction to Modern Number Theory". $D$ is the ring of algebraic integers of a cyclotomic field ...
רוי רז's user avatar
3 votes
2 answers
189 views

Computing the Minimal Polynomial of $\sqrt{3} + \sqrt[3]{5} $ over $\mathbb{Q} $

In trying to compute the minimal polynomial of $\sqrt{3} + \sqrt[3]{5} $ over $\mathbb{Q} $ I employed the usual approach of considering: $x - (\sqrt{3} + \sqrt[3]{5})=0$ Then from there take the ...
Diego Vera's user avatar
1 vote
1 answer
49 views

Question about the proof that quotients of a ring of algebraic integers are finite

This is proposition 12.2.3 from Ireland and Rosen's "A Classical Introduction to Modern Number Theory". $D$ is the ring of algebraic integers of some algebraic number field, and $A$ is an ...
רוי רז's user avatar
1 vote
1 answer
38 views

Why does $P^e \subset (\alpha) + P^e$ imply that $(\alpha) + P^e$ is a power of $P$?

This is proposition 12.3.2 from Ireland and Rosen's "A Classical Introduction to Modern Number Theory". $D$ is the ring of algebraic integers of some algebraic number field, and $e$ is the ...
רוי רז's user avatar
1 vote
0 answers
129 views

Why is the order of an ideal with respect to a prime ideal well defined?

This is the definition of $\text{ord}_P A$ in Ireland and Rosen's "A Classical Introduction to Modern Number Theory". $D$ is the ring of algebraic integers of some algebraic number field and ...
רוי רז's user avatar
1 vote
0 answers
69 views

Why can we change the order of "exists" and "for all"?

This is lemma 5 in section 12.2 from Ireland and Rosen's "A Classical Introduction to Modern Number Theory". $D$ is the ring of algebraic integers of an algebraic number field $F$, and $N(x)$...
רוי רז's user avatar
0 votes
0 answers
100 views

Is my solution ok? The set of the algebraic numbers obtained as roots of polynomials with integer coefficients that have degree $n$ is countable.

I am reading "Understanding Analysis Second Edition" by Stephen Abbott. The following exercise is Exercise 1.5.9(b): Exercise 1.5.9(b) Fix $n\in\mathbb{N}$, and let $A_n$ be the algebraic ...
tchappy ha's user avatar
  • 8,790
1 vote
1 answer
179 views

What gives the golden ratio its unusual numerical properties?

Why does the golden ratio (and by extension the other metallic means) have such unusual numerical properties? For those who don't know, the golden ratio ($\varphi$) is the positive root of the ...
zenzicubic's user avatar
1 vote
0 answers
149 views

Understanding Liouville numbers and irrationality measure

Every number $x \in \mathbb{R}$ has an associated irrationality measure $\mu(x)$. Let $\mathbb{A}$ be the algebraic numbers and let $x_\mathbb{Q} \in \mathbb{Q}, x_{\mathbb{A}\setminus\mathbb{Q}} \in \...
Daniel S.'s user avatar
  • 532
0 votes
2 answers
108 views

Problem in trigonometry solved with more advanced topics - $\displaystyle \cos(q\pi) \in \mathbb{Q} \to \cos(q\pi) \in \{0, \pm \frac{1}{2}, \pm 1\}$

Prove the following affirmation: If $q$ is a rational number and $\cos(q\pi)$ is also a rational number, prove that $\cos(q\pi)$ must be one of the elements of the set $\{0, \pm \frac{1}{2}, \pm 1\}$. ...
MathStackExchange's user avatar
4 votes
1 answer
122 views

Degree of $\sqrt[5]{2+\sqrt[3]{5+\sqrt{2}}} \cdot e^{2\pi i /3}$ as algebraic number

In this post, ‘degree’ means ‘degree as an algebraic integer’. Let $\alpha = \sqrt[5]{2+\sqrt[3]{5+\sqrt{2}}}$ I see that $f(\alpha)=0$ for the polynomial $f(x) = \big((x^{5}-2)^{3}-5)\big)^{2}-2$, ...
Gafar Maulik's user avatar
1 vote
1 answer
252 views

Is every element of GF(p^k) whose degree is k a generator?

I'm reading notes on minimal polynomials and finite fields taken from Jim Belk's webpage Proposition 7 goes: It seems to me there exists a counterexample to this statement: The number of elements of ...
Zhiltsoff Igor's user avatar
0 votes
2 answers
49 views

Algebraic independence of a family of numbers

I need to show that given $a_1,\cdots,a_n\in\mathbb{C}$ algebraic numbers linearly independent over $\mathbb{Q}$, then the numbers $e^{a_1},\cdots,e^{a_n}$ are algebraically independent over rationals....
user avatar
0 votes
1 answer
219 views

If $\alpha ,\beta$ algebraic over $F$ then there exist a isomorphism $\psi:F(\alpha) \to F(\beta) $iff $\alpha,\beta$ have same minimal polynomial

Let $K$ be a field extension of $F$ and $L$ be also a field extension of F. If $\alpha \in K$ and $\beta \in L$ are both algebraic over $F$, then show that there is an isomorphism of fields: $\mu : F(\...
Alexander's user avatar
  • 293
1 vote
2 answers
399 views

$F(\alpha)$ is isomorphic to the field $F(x)$ of rational functions over $F$ in the indeterminate $x$ where $\alpha$ is transcendental over $F$

Q.$(a)$ If $\alpha$ is transcendental over a field $F$, then show that $(i)$ the map $\mu : F[x] → F[\alpha],f (x) \mapsto f (\alpha)$ is an isomorphism; $(ii)$ $F(\alpha)$ is isomorphic to the field $...
Alexander's user avatar
  • 293