Questions tagged [adjoint-operators]

For questions about adjoint operators in inner product spaces. For adjoint functors from category theory, use the tag (adjoint-functors).

300 questions with no upvoted or accepted answers
Filter by
Sorted by
Tagged with
10 votes
1 answer
285 views

Derivative of adjoint operator-valued function

Consider an infinite dimensional complex Hilbert space $H$. I think that for a bounded operator-valued function $A: x\mapsto A(x) \in \mathcal B(H)$, where $x\in \mathbb R$, we can define the ...
Jakob's user avatar
  • 374
10 votes
0 answers
4k views

Gradient operator the adjoint of (minus) divergence operator?

Recently I found this statement -- the gradient operator is the adjoint of the minus divergence operator -- in one of my lecture notes. Knowing only a little about functional analysis, I'm looking for ...
Ailurus's user avatar
  • 1,182
8 votes
0 answers
154 views

Why is it called *adjunction* formula?

Let $X$ be a complex manifold, $Y$ a sub-manifold, and $i \colon Y \to X$ the corresponding embedding. Then one can prove that the corresponding canonical bundles satisfy $$ \omega_X \big|_Y = \...
A.P.'s user avatar
  • 9,728
7 votes
0 answers
238 views

$T$-invariance of $U$ is equivalent to $T^{*}$-invariance of $U^{\perp}$

Is the Following argument correct? Suppose $T\in\mathcal{L}(V)$ and $U$ is a subspace of $V$. Prove that $U$ is invariant under $T$ if and only if $U^{\perp}$ is invariant under $T^*$. Proof. Given ...
atifcppprogrammer's user avatar
7 votes
0 answers
207 views

Find the adjoint under the inner product $\langle f, g \rangle = \int_0^1 f(t)g(t)t \ dt$ of $\mathcal{L}(f)(t) = \frac{d^2 f}{dt^2} + f$.

Find the adjoint under the inner product $\langle f, g \rangle = \int_0^1 f(t)g(t)t \ dt$ of $\mathcal{L}(f)(t) = \dfrac{d^2 f}{dt^2} + f$ with $f(0) = 0$ and $f'(1) = 0$. Note: The weight function is ...
The Pointer's user avatar
  • 4,470
6 votes
0 answers
1k views

Inverse vs. adjoint operators

I hope this is enough of a question (and less of a start of a discussion) to be allowed here. I am trying to get my head around the ideas of inverse and adjoint operators. To keep it simple, let's ...
bers's user avatar
  • 532
5 votes
1 answer
140 views

Show properties of the linear operator $L((a_n)_n)=\left(\frac{1}{n}*a_n\right)_n$

Let $L\colon \ell^p \rightarrow \ell^p$ such that $L((a_n)_n)= \left(\frac{1}{n}*a_n\right)_n$. 1) Determine $L'$(adjoint operator), $\ker(L)$, $\ker(L')$, $\operatorname{rg}(L)$, $\operatorname{rg}(...
Infinite_28's user avatar
5 votes
0 answers
1k views

Sum of operator and adjoint is self-adjoint

In abstract Hodge theory there is the following lemma: Let $H$ be a Hilbert space and $A \in \mathcal{C}(H)$ a densely defined, closed operator (so possibly unbounded) and $A^*$ its adjoint operator. ...
bodo's user avatar
  • 1,134
4 votes
0 answers
111 views

Norm of the adjoint operator of an operator of the form $\int_{0}^{1} k(t,s)f(s)ds$

I am asked to compute the adjoint of the operator $A: L^2[0,1] \longrightarrow L^2[0,1] $ defined by $$ Af(t)=\int_{t}^{1} t (s-1/2) f(s) ds $$ and then to compute its norm, that is $\lVert A^* \rVert$...
ferolimen's user avatar
  • 474
4 votes
0 answers
110 views

If the boundary is adjoint to the differential, what is the "coboundary" adjoint to the codifferential in the continuum?

For a smooth manifold, Stoke's theorem says that the differential/exterior derivative $\mathrm{d}$ is adjoint to the boundary operator $\partial$, i.e. $$\int_{\partial U} \omega = \int_{U} \mathrm{d}\...
Kai's user avatar
  • 1,151
4 votes
0 answers
143 views

Adjoint of unbounded integral operator

Consider a Borel-measurable function $a:\mathbb{R}\times\mathbb{R}\rightarrow\mathbb{C}$, and let $T_a$ be the linear operator on $L^2(\mathbb{R})$ with domain \begin{equation} \mathcal{D}(T_a)=\left\{...
Davide's user avatar
  • 349
4 votes
0 answers
127 views

Find Adjoint of $L = p(x) \frac{d^2}{dx^2} + r(x) \frac{d}{dx} + q(x)$

Suppose that \begin{align*} L &= p(x) \frac{d^2}{dx^2} + r(x) \frac{d}{dx} + q(x) \\ \end{align*} Consider \begin{align*} \int_a^b vL(u) \, dx \\ \end{align*} By repeated integration ...
clay's user avatar
  • 2,609
4 votes
1 answer
2k views

Adjoint differential equations

Consider the vector differential equations \begin{equation} \mathbf{x}^{\prime}=\mathbf{A}(t)\cdot\mathbf{x}\tag{1} \end{equation} and \begin{equation} \mathbf{y}^{\prime}=-\mathbf{A}^{\ast}(t)\cdot\...
bkarpuz's user avatar
  • 791
4 votes
1 answer
83 views

Using inner product property to determine if operator is an isomorphism.

Let $\varphi$ be an operator on a $k$-vector space $V$ with an inner product $\langle\cdot,\cdot\rangle$. Suppose that $\langle v,\varphi v\rangle = 0$ for every $v\in V$. If we take $k=\mathbb R$, is ...
user avatar
3 votes
1 answer
146 views

Existence and uniqueness of formal adjoint operator on manifolds

Let $(\mathcal{M},g)$ be a (pseudo)-Riemannian manifold and $E$ a real vector bundle over $\mathcal{M}$, which we equip with a non-degenerate metric $\langle\cdot,\cdot\rangle_{E}\in\Gamma^{\infty}(E^{...
B.Hueber's user avatar
  • 2,196
3 votes
0 answers
96 views

Diffusion-Reaction problem $u_t = \int_{-\infty}^{\infty} K(x-y) u(y) dy . u + u^3$.

I have bee stuck in this problem since more than a week. During my study I kinda understand how to find the adjoint operator for the linearization. But I have no Idea how to find the linearization to ...
Mr. Proof's user avatar
  • 1,372
3 votes
1 answer
437 views

Does the derivative operator have an adjoint?

Determine whether the linear operator $T(f) = f'$ (taking the derivative) has an adjoint or not. Consider the inner product $\left<f,g\right> = \int_0^1 f(t)g(t)\ dt $ defined on the vector ...
Dinoman's user avatar
  • 700
3 votes
0 answers
102 views

adjoint matrix of an operator

considering a $2\times 2$ matrix $\bf S$, \begin{equation} {\bf S} = \begin{bmatrix} \frac{\partial}{\partial{t}} & \kappa\nabla .\\ 1/\rho \nabla . & \frac{\partial}{\partial{t}} \...
Rafael_Cristo's user avatar
3 votes
0 answers
109 views

Range of $𝐴^*𝐴$ and range of $𝐴^∗$ have the same closure

I have the following lemma and proof in my lecture notes ($\mathcal{R},\mathcal{N}$ denote range, kernel, respectively, and $\mathcal{X}$ and $\mathcal{Y}$ are Hilbert spaces). I was hoping there was ...
mss's user avatar
  • 713
3 votes
0 answers
315 views

What is a duality argument?

I believe this is probably a question that can have a wide variety of answers, but i believe i'm still interested. The thing is, i have been in a couple pde talks, and i saw that in both of these ...
Alek Murt's user avatar
  • 469
3 votes
0 answers
50 views

How to calculate a multiplication operator representation?

Let $H =\ \mathcal{l}^{2}(\mathbb{Z},\mathbb{C})$ and $A = R + L$, where $L$ is the left-shift operator (and $R$ is the right-shift $(Ra)_{n}=a_{n-1}$). Set $$U : \mathcal{l}^{2}(\mathbb{Z},\...
jinour's user avatar
  • 31
3 votes
0 answers
38 views

Prove that for the defined $\langle .,. \rangle$ there exist $0 < a \le b$ such that $a\|x\| \le \|x\|_\ast ≤ b\|x\|$ for all $x \in H$.

Let $H$ be a Hilbert space over $\mathbb{R}$ with an inner product $(·, ·)$ and the norm $\|x\| = \sqrt {(x, x)}$. Let $A$ be a bounded strictly positive definite linear operator on $H$ with $A^\ast = ...
domath's user avatar
  • 1,361
3 votes
0 answers
449 views

Null space equals annihilator of range of adjoint in general spaces

(It turns out that the claim is incorrect as pointed out in the comment. Will get back soon) Let $A, B$ be normed linear spaces and let $S$ be a bounded linear map from $A$ to $B$. Define the map $S^*...
Chenliang Zhou's user avatar
3 votes
0 answers
76 views

Show that T is a surjective linear application

Let $X,Y$ be Banach spaces and $T:X\to Y$ a bounded linear application. Let $T^*:Y^*\to X^*$ be its adjoint (i.e. $T^*g(x)=g(Tx)$, $\forall g\in Y^*, x\in X$ ). If $||T^*g||\geq K||g||$ for some ...
Pires Dankan's user avatar
3 votes
0 answers
36 views

Showing that a map is open by usying lower boundedness of adjoint

Let consider the following exercise: Let $V$ and $W$ be Banach spaces and $T\colon V \longrightarrow W$ be a closed linear operator. Then, the following assumptions are equivalent: (i) R$(T)=W$; (ii) ...
Mathecm's user avatar
  • 649
3 votes
0 answers
301 views

Adjoint vs Self-adjoint operators represented by matrices

I want to see the difference between just adjoint and self-adjoint (hermitian) operator represented by matrices. If I have a matrix $$A= \begin{pmatrix} 1 & i \\ i & 1 \\ \...
Leif's user avatar
  • 1,463
3 votes
0 answers
142 views

Check if a Differential operator is self-adjoint

Let $\Omega \in \mathbb{R}^n$ be a bounded domain with boundary of class $C^2$. Define \begin{cases} D(A) = H^2 \cap H_0^1(\Omega;\mathbb{C})\\ Au(x)=\Delta u(x)-V(x)u(x) \hspace{3mm} x \in \Omega \...
James Arten's user avatar
  • 1,884
3 votes
0 answers
195 views

Show that $T$ has an adjoint, and describe $T^*$ explicitly.

Let $V$ be an inner product space and $ \beta, \gamma$ fixed vectors in $V$. Show that $T \alpha = (\alpha\mid\beta) \gamma$ defines a linear operator on $V$. Show that $T$ has an adjoint, and ...
Ilovemath's user avatar
  • 2,817
3 votes
0 answers
82 views

adjoint operators in the vector space of real polynomials

This problem is about the space $V$ of real polynomials in the variables $x$ and $y$. If $f$ is a polynomial, $d_f$ will denote the operator $f(d/dx,d/dy)$ , and $d_f(g)$ will denote the result of ...
Miles Johnson's user avatar
3 votes
0 answers
146 views

Show that the integral-operator compact?

We have the operator $T$ on $L_2[0,1]$ which is defined as $Tf = y$ where $y$ is the solution to the ODE $y^{\prime \prime} + y^\prime = f$ with boundary conditions $y(0)=0, y(1) = 1$ Show that $T$ ...
blux's user avatar
  • 171
3 votes
0 answers
277 views

Explicit form of generators of a Lie algebra in the adjoint representation

My question can be summarized as: Generators of a Lie group in the adjoint representation can be written as, $$ (T^a_\text{Ad})_{bc} = \text{i}f^{abc}, \tag{1}\label{adj} $$ where $f^{abc}$ ...
ersbygre1's user avatar
  • 296
3 votes
1 answer
161 views

How is the "adjoint representation" related to generic group representations?

I'm studying representation theory in order to have a basis to study quantum field theory. I think the text (my professor's) i'm studying on is pretty confusing. I don't really get the difference ...
PsycoPulcino's user avatar
3 votes
1 answer
236 views

Operator $f \mapsto u(f)$ solution of non-homogeneous Laplace equation is compact and self-adjoint

Let $u : L^2_0(D) \to L^2_0(D): = \lbrace f \in L^2 : \int_D f = 0 \rbrace $ be the linear operator which associates $f$ to $u(f)$ the solution of $$ \begin{cases} \Delta u = f & \text{in } D \\ \...
varia's user avatar
  • 31
3 votes
0 answers
27 views

Finding two adjoints, and showing boundedness of operators

Let $H = l_2$ and consider the following operators: $T,S:H \to H$ $Tx = (0,x_1,x_2,\ldots)$ and $Sx = (x_2,x_3,x_4,\ldots)$ Show they are bounded, and find the adjoint of both: For $T$, I have $\|Tx\|...
bestfriends's user avatar
3 votes
0 answers
334 views

adjoint method for computing derivatives

I am curious if anyone has heard of this problem before: Suppose that $u(x,p)$ is a function of $x$ and $p$. These arguments need not be scalars. Let $u(x,p)$ satisfy some differential equation, say:...
Tomas Jorovic's user avatar
3 votes
1 answer
401 views

Properties of adjoint matrix in a finite dimensional inner product space

let $V$ be a finite dimensional inner product space. Let $T$ be a linear operator on $V$. Prove that there exists an invertible linear operator $U$ such that $U^{-1}TT^*U = T^*T $ where $T^*$ is ...
Phantom's user avatar
  • 1,089
3 votes
0 answers
91 views

Do I have the correct mental map for adjoint operators for inner product spaces?

Let $X$, $Y$ be finite dimensional inner product spaces, let $A: X \to Y$ be a linear operator, let $A^*: Y \to X$ be the adjoint operator to the linear operator, defined using $<y, Ax>_Y = <...
Fraïssé's user avatar
  • 11.1k
3 votes
0 answers
1k views

Linear map is diagonalizable iff its adjoint is diagonalizable

Problem Let $V$ be a finite inner product space and let $T:V \to V$ be a linear transformation. Prove that $T$ is diagonalizable if and only if the adjoint transformation $T^{*}$ is diagonalizable. ...
user16924's user avatar
  • 2,591
3 votes
1 answer
107 views

How to prove this is a self-adjoint operator?

I have this operator from $H^1_0$ to $H^1_0$ defined by: $$Au(t)=\int_0^1 G(t,s) f(s,u(s))\mathsf ds$$ where $$G(t,s)=\begin{cases} t(1-s), &t\leq s\\s(1-t), &s\leq t.\end{cases}$$ I want to ...
Vrouvrou's user avatar
  • 5,183
3 votes
1 answer
754 views

$T \in B(X,Y)$ is an isometry if and only if $T^*$ is an isometry

I would like to prove that $T \in \mathscr{B}(X,Y)$ is an isometry of $X$ onto $Y$ if and only if $T^*$ is an isometry of $Y^*$ onto $X^*$. I am not really sure what to do. I started the argument as ...
Ben's user avatar
  • 491
3 votes
0 answers
275 views

Proving that a certain differential operator is self-adjoint

Consider the differential operator $T:u\mapsto -iu'$ for any $u\in D(T):=\{f\in AC[-\pi,\pi]~|~f'\in L^2(-\pi,\pi),f(-\pi)=f(\pi)\}$; we consider $T$ as a densely-defined operator on $L^2(-\pi,\pi)$. ...
Stromael's user avatar
  • 1,372
3 votes
0 answers
643 views

Find the adjoint operator

I would like to find the adjoint operator in the Hilbertspace $L^2(0,\infty)$ of the operator $$ (Ax)(t)=x(at), x\in L^2(0,\infty), a>0. $$ My calculation is the following; I use the ...
user avatar
2 votes
1 answer
75 views

Domain of the adjoint operator of a bounded operator (on a Hilbert space). (Experimental physicist)

Let $A$ be a bounded operator on a Hilbert space $H$ and $D_A$ its domain. We can define the following functional on $D_A$: $$f_\eta(\xi)=(\eta,A\xi).$$ Then we have that: $$||f_\eta(\xi)||=||(\eta,A\...
davise's user avatar
  • 21
2 votes
0 answers
23 views

Brezis' exercise 6.24.1: prove that $T$ is positive IFF $\sigma (T) \subset [0, \infty)$

Let $E$ be a real Banach space. Let $\mathcal L(E)$ be the space of bounded linear operators on $E$ and $\mathcal K(E)$ its subspace consisting of compact operators. Let $\| \cdot\|$ be the operator ...
Akira's user avatar
  • 16.2k
2 votes
0 answers
44 views

On an operator inequality

Let $A$ and $B$ be two positive, self-adjoint and traceclass operators mapping from some Hilbert space $H$ to it self. Note that we have for any $a, b > 0$, $p>1$ $$(a+b)^p\leq 2^{p-1}(a^p+b^p)$$...
Gauß0123's user avatar
2 votes
0 answers
31 views

Assume $T\in \mathcal L(E, F)$. Then $T\in \mathcal K(E, F)$ IFF $T^* \in \mathcal K(F^*, E^*)$

Let $E, F$ be Banch spaces. Let $\mathcal L(E, F)$ be the space of bounded linear operators from $E$ to $F$. We endow $\mathcal L(E, F)$ with the operator norm. Let $\mathcal K(E, F)$ be the subset of ...
Akira's user avatar
  • 16.2k
2 votes
0 answers
40 views

Discrete spectrum under a finite rank perturbation

Let $A$ be a bounded self-adjoint operator on a Hilbert space. Assume the discrete spectrum of $A$ is empty. Let $B$ be a finite rank operator. I have learned that the essential spectrum of $A+B$ and $...
Justin Lien's user avatar
2 votes
0 answers
74 views

The adjoint operator of the inclusion map

Let $(H, |\cdot|)$ be a Banach space and $V$ a linear subspace of $H$. Assume that the vector space $V$ has its own norm $[ \cdot ]$ such that $(V, [\cdot])$ is a Banach space. We consider the (linear)...
Akira's user avatar
  • 16.2k
2 votes
0 answers
53 views

The adjoint of $T_a: L^2 (\mathbb R^d) \to L^2 (\mathbb R^d), u \mapsto a * u$

Let $a \in L^1 (\mathbb R^d)$ be a fixed function. Consider a linear operator $$ T_a: L^2 (\mathbb R^d) \to L^2 (\mathbb R^d), u \mapsto a * u. $$ By Young's inequality, $\|a*u\|_2 \le \|a\|_1 \|u\|_2$...
Analyst's user avatar
  • 5,128
2 votes
0 answers
62 views

Sturm-Liouville theory and adjoint operator

Suppose we have a differential equation of the form $$ L[f(x)] = a(x)f''(x) + b(x)f'(x) + c(x)f(x) = g(x) $$ where $a, b, c$ and $g$ satisfy the regularity conditions demanded in Sturm-Liouville ...
Uri Toti's user avatar
  • 533

1
2 3 4 5 6