Questions tagged [abelian-groups]

For questions about abelian groups, including the basic theory of abelian groups as a topic in elementary group theory as well as more advanced topics (classification, structure theory, theory of $\mathbb{Z}$-modules as related to modules over other rings, homological algebra of abelian groups, etc.). Consider also using the tag (group-theory) or (modules) depending on the perspective of your question.

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Why is a Sylow 5-subgroup abelian?

For weeks I tried to solve the following question on Brilliant: Fill in the blank: "Every group of order ___ is abelian." And these are the possible answers I get: 15, 16, 20, 21, 27. Using ...
user3635700's user avatar
-2 votes
1 answer
60 views

Let $h\in G$. Let $\phi_h : G \to G$ st $g\mapsto hgh^{−1}$. Then $G$ is abelian iff $\phi_h = \operatorname{id}_G$ for all $h\in G$.

Let $G$ be a group and $h\in G$. Consider the map $\phi_h : G \to G$ st $g\mapsto hgh^{−1}$, $G$ is an abelian group if and only if $\phi_h = \operatorname{id}_G$ for all $h\in G$. I know what it ...
Jasmin's user avatar
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1 vote
0 answers
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How to show that a subgroup of a product of finite cyclic group has itself this property?

Let $G$ be a subgroup of a finite product of finite cyclic groups. Is it easy to prove that $G$ is itself a finite product of cyclic groups without appealing to the structure theorem of finite abelian ...
Stabilo's user avatar
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0 answers
25 views

On Ulm invariants of a famous abelian p-group due to Prufer

We know that there is a famous example due to Pruefer, of a countable reduced p-group $G$ of length $\omega + 1$ as following:// Let G be the Abelian group generated by the countable set of ...
Mahmood Behboodi's user avatar
0 votes
1 answer
54 views

How to find invariant factor of this finitely generated group

I'm trying to solve this problem. Let $G$ be the set $\Bbb Z^2$ with binary operation defined by $(x_1,y_1)*(x_2,y_2) = (x_1+x_2, y_1+y_2+x_1x_2)$ Show that $(G,*)$ is a finitely generated abelian ...
MLe's user avatar
  • 47
2 votes
1 answer
46 views

Finding all the possible orders of elements in a quotient group

Let $A$ be an arbitrary Abelian group and let $H:=\{a\in A\mid\exists b\in A\mid a=b^3\}.$ Prove $H$ is a normal subgroup of $A$. Determine all the possible orders of elements in the group $A/H.$ My ...
Invisible's user avatar
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2 votes
1 answer
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The maximal free abelian subgroup that can be embedded in $GL(n,\mathbb{Z})$

I am stuck on this problem and cannot seem to find a good reason for drawing the required conclusion. The problem is as follows: Given $SL(n, \mathbb{Z})$ a subroup in $GL(n, \mathbb{Z})$. How can ...
Yushi MuGiwara's user avatar
1 vote
0 answers
52 views

A group closed under scalar multiplication is a vector space

Suppose $G$ is an abelian group closed under scalar multiplication with elements in the field $F$. Is $G$ always a vector space over $F$? I have been trying to find a counter-example, but failing. In ...
Athere's user avatar
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1 vote
2 answers
69 views

Abelian groups with all elements having order $2$

This result is not an exercise, but more so a hunch that I am trying to prove for myself. Let's say that $G$ is a finite group with the property that it is both abelian and every non-identity element ...
Brad G.'s user avatar
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Doubt regarding the generality of an equivalent definition for Abelian Group [duplicate]

I was given a problem as follows: Let $G$ be a finite group of odd order. If $(ab)^{3}=a^{3}b^{3}$ and $(ab)^{5}=a^{5}b^{5}$ for all $a,b\in G$ then $G$ is abelian. I was able to show that this is ...
Shash's user avatar
  • 73
0 votes
2 answers
114 views

Proving that there is a functor $F: Grp \rightarrow Ab$ s.t $F(G)=G_{ab}$- How to deal with the quotient?

Let $G$ be a group. $f$ a group hom. $f:G\rightarrow H $ I define: $F(G)=G_{ab}$ and $F$ : $G$ $\rightarrow$ $G_{ab}$ a homomorphism, where $G_{ab} : = G/[G,G]$ is the abelianization of group $G$....
some_math_guy's user avatar
6 votes
3 answers
208 views

When two infinite direct products $\prod_I\Bbb{Z}$ and $ \prod_J\Bbb{Z}$ are isomorphic?

It is known that two free $\Bbb{Z}$-modules $\bigoplus_{I}\Bbb{Z}$ and $\bigoplus_{J}\Bbb{Z}$ are isomorphic if and only if $|I|=|J|$. Moreover, it is true for any two free module over a commutative ...
Mahmood Behboodi's user avatar
0 votes
1 answer
51 views

Free product and direct product of $\mathbb{Z}$

I'm studying Seifert Van Kampen theorem and I evaluate the fundamental group of torus seen as a quotient space in particular $$T = [0,1]\times[0,1]/\sim\\ (x,0)\sim(x,1) \\ (0,y)\sim(1,y)$$ With $\pi:[...
Turquoise Tilt's user avatar
2 votes
0 answers
28 views

Category of LCAG's "measures" the difference between the integers and the reals: what does this mean?

The Wikipedia article on Locally compact abelian Groups (https://en.m.wikipedia.org/wiki/Locally_compact_abelian_group) has the following excerpt in the Categorical properties section: Clausen (2017) ...
Pedro Lourenço's user avatar
3 votes
1 answer
51 views

Is multiplication by a scalar an open map in topological groups?

If n is any non-zero integer and G is a topological abelian group, under what conditions is the continuous homomorphism $g \mapsto ng$ open or weakly open? If this map happens to be open for all n and ...
Pedro Lourenço's user avatar
0 votes
2 answers
73 views

Row reduction and generating sets of a finite abelian group

Let us suppose that we have a finite abelian subgroup which is generated by 2 elements $A,B$. On the other hand, define the following 3 "actions": Changing $\{A,B\}$ for $\{B,A\}$. Changing ...
Alejandro Tolcachier's user avatar
2 votes
0 answers
76 views

The structure of a finitely generated abelian group and its endomorphism ring

This is a question from our past exams. I worked it out. Would anyone kind enough to check the correctness? Thanks! (It occurred several times that I somehow skipped crucial steps or overlooked ...
Zeta's user avatar
  • 65
2 votes
0 answers
36 views

the non-abelian subgroups of the Lamplighter group

The lamplighter group can be defined by the semidirect product: $$ L_2=(\mathbb{Z} _2) \wr \mathbb{Z} \cong \bigoplus_{i=-\infty}^{\infty}\mathbb{Z}_{2} \rtimes_\phi\mathbb{Z},$$ where $\phi(1)$ &...
ghc1997's user avatar
  • 1,163
0 votes
1 answer
79 views

Why $\operatorname{Hom}(\mathbb Z, \mathbb Z) = \mathbb Z$? [duplicate]

Why $\operatorname{Hom}(\mathbb Z, \mathbb Z) = \mathbb Z$? Is there a proof for this fact? Also, if I want to understand more the hom, ext, tor and tensor functors, should I study homological algebra ...
Emptymind's user avatar
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1 vote
1 answer
53 views

Non-discrete LCAG's whose closed non-trivial subgroups are open

Let G be a locally compact abelian group and suppose that for any non-trivial closed subgroup H of G, H is open. It also makes sense to suppose that G is non-discrete (since in that case this ...
Pedro Lourenço's user avatar
2 votes
0 answers
189 views

The cyclic subgroups of $GL_{3}(\mathbf{F}_{p})$

Let $p$ be an odd prime number and let $\mathbf{F}_{p}$ be the finite field of order $p$. The group $H$ is a cyclic subgroup of $GL_{3}(\mathbf{F}_{p})$ such that there does not exist an abelian ...
Shotaro Hidari's user avatar
0 votes
0 answers
37 views

kernel and cokernel of multiplication with 2

Let $A$ be an abelian group and let $f_n \colon A \to A, x \mapsto 2^n x$ be a morphism. Suppose the kernel and cokernel of $f_1$ are finite $2$-groups. I want to show that then the kernel and ...
Candyblock's user avatar
3 votes
1 answer
97 views

When is the intersection of all open normal subgroups equal to the connected component at the identity?

I've managed to show that for locally compact abelian groups, the connected component at the identity $G_0$ is equal to the intersection of all open subgroups of G, since we have that $$A(G_0) = \...
Pedro Lourenço's user avatar
1 vote
0 answers
65 views

Quotient of the group $\mathbb{Z}^2 \oplus \mathbb{Z} ^2 \oplus \mathbb{Z} ^2$

Does there exists $x_1$, $x_2$ , $y_1$ , $y_2 \in \mathbb{Z}^2$, such that $$\frac{\mathbb{Z}^2 \oplus \mathbb{Z} ^2 \oplus \mathbb{Z} ^2 }{ \langle (x_1,y_1,0), (0,x_1,y_1) , (x_2,y_2,0), (0,x_2,y_2) ...
ghc1997's user avatar
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1 vote
1 answer
32 views

Subgroups of self dual groups

Let G be an infinite locally compact abelian group that is isomorphic to its own dual. If H is a closed subgroup of G, is it necessarily true that $H \cong \widehat{G/H}$? I ask because in the case of ...
Pedro Lourenço's user avatar
7 votes
1 answer
125 views

Finding a set of representatives that sum to zero.

Let $G$ be an abelian group of order $2n$, where $n$ is an odd integer (For simplicity, we may assume $G\simeq \mathbb{Z}_{2n}$ (the cyclic group of order $2n$). Let $A_1,A_2,\ldots,A_n$ be a ...
Michal Dvořák's user avatar
4 votes
1 answer
138 views

Is there a type of product of groups where $C_2 \star C_2 = C_4$?

Hi I am wondering if there is a type of product $\star$ of groups to get $C_4 \cong C_2 \star C_2$. We know that the composition series of $C_4$ indeed is a 2 copy of $C_2$ so I am wondering if there ...
Leon Kim's user avatar
  • 193
1 vote
0 answers
22 views

2-groups with abelianization of type (2,2)

On Olga Taussky's article "A Remark on the class field tower" there is a note on the last page where she states that P. Hall pointed out to her that exists 3 different groups of order $2^k$ ...
Vítor Machado's user avatar
3 votes
1 answer
58 views

Decomposition of infinite abelian groups

A colleague recently mentioned a "Prüfer Decomposition Theorem", claiming that every abelian group $A$ could be expressed as the direct sum $A = T(A) \oplus F(A)$, where $T(A)$ is the ...
alexchandel's user avatar
0 votes
1 answer
45 views

Why Scalar Multiplication is not commutative/Abelian?

Definition 2.9 (Vector Space). A real-valued vector space V = (V,+, ·) is vector space a set V with two operations : V × V → V (2.62) · : R × V → V (2.63) where (V, +) is an Abelian group Source: ...
user13034532's user avatar
1 vote
0 answers
15 views

Groups extensions by linear cocycles

Let $0 \to A \to X \to C \to 0$ be an abelian group extension (we require $X$ to be abelian too). Then the group operation on $X$ is described by a $2$-cocycle $c(x, y) = s(x) + s(y) -s(x+y)$ where $s:...
Matteo Casarosa's user avatar
2 votes
0 answers
117 views

Is it possible to write a code that computes all the subgroups (up to isomorphism) of a finite Abelian group?

I am new to computational group theory. I am trying to find/write a program that computes the following: Input: a finite abelian group $$G \cong \mathbb{Z}_{m_1} \oplus \cdots \oplus \mathbb{Z}_{m_{...
ghc1997's user avatar
  • 1,163
6 votes
0 answers
79 views

Abelian subgroups of the group of automorphisms of a finite group

This is a follow-up question from my post here, which has been moved according to a comment. For context, here is the setup. Let $G$ be a nontrivial finite group. In his book "Finite Group ...
Gauss's user avatar
  • 2,197
3 votes
1 answer
66 views

Size of $p$-subgroups of $\operatorname{Aut}(G)$, where $p$ divides the order of $G$

Let $G$ be a nontrivial finite group. In his book "Finite Group Theory", M. Isaacs proves the following two results: Corollary 3.3: Let $\sigma \in \operatorname{Aut}(G)$. Then, $o(\sigma) &...
Gauss's user avatar
  • 2,197
0 votes
1 answer
53 views

Given two isomorphic subgroups of a finite abelian group with the same number of minimal generators, are the quotients isomorphic?

Let $G$ be a finite abelian group. We know that the least size of a minimal generating set of a proper nontrivial subgroup $H \leqslant G$ might be the same as $G$, for example ($\Bbb Z_6 \cong \...
ghc1997's user avatar
  • 1,163
0 votes
0 answers
24 views

Spectral sequences of bicomplexes: are differentials chain complex maps?

This is a probably stupid question, and I guess the answer is no, but it's worth trying. Consider the spectral sequence $E^{pq}_r$ associated to a bicomplex (of abelian groups). At page $r$ we will ...
Andrea Marino's user avatar
0 votes
0 answers
11 views

Maximal Essential Extension in Finitely Generated Abelian groups

In GTM4, the author asked the reader to give a procedure for calculating the maximal essential extension of $A$ in $B$, where $B$ is a finitely generated abelian group. I've got completely no idea of ...
Jon Snow's user avatar
  • 101
0 votes
0 answers
14 views

Maximal Essential Extension of Abelian Groups

Given any abelian group $A$, let $T(A)$ be its torsion subgroup and $F(A)=A/T(A)$. A homomorphism $\varphi:A\to B$ induces $T(\varphi):T(A)\to T(B)$, $F(\varphi):F(A)\to F(B)$, and $\varphi$ is one-to-...
Jon Snow's user avatar
  • 101
9 votes
1 answer
252 views

Weird duality between integers and p-adic integers

The integers are, up to isomorphism, the unique infinite discrete abelian group that is isomorphic to all its non-trivial subgroups. This can be seen easily by Pontryagin Duality: It's equivalent to ...
Pedro Lourenço's user avatar
1 vote
0 answers
29 views

Preimage of a canonical vector with a coprime coordinate in a epimorphism of abelian groups

Let $s,r$ be natural numbers such that $s \geq r$, $$B = \prod_{i = 1}^r\mathbb{Z}_{e_i}$$ a finite abelian group where $1 < e_r$ and $e_{i+1} | e_i$ for all $i$ and consider $\phi$ a surjective ...
Santiago Radi's user avatar
1 vote
2 answers
72 views

Given $\text{Hom}(M,M')$ is abelian, does $M$ have to be abelian?

I am doing a course on algebra (self-study) and it was left as an excercise to prove that if $M$ and $M'$ are abelian groups, then $(\text{Hom}(M,M'), +)$ is an abelian group, where the operation is ...
kubo's user avatar
  • 1,451
2 votes
0 answers
44 views

What is $H^2(U(1),\mathbb Z_2)$?

Let $U(1)$ denote the multiplicative group of complex numbers of modulus $1$ and $\mathbb Z_2:=\mathbb Z/(2\mathbb Z)=\left(\{0,1\},+\right)$ I know that the central group extension $$\mathbb Z_2\...
mma's user avatar
  • 1,828
0 votes
1 answer
90 views

Abelian, transitive subgroup of $S_A$, then $\sigma(a)\neq a$ for $\forall\sigma \in G-\{1\}$ and $\forall a$

I have read these questions: Show that $\sigma(a)\ne a,\forall\sigma\in G-\{1\}$ and all $a\in A$.where $G$ is abelian, transitive subgroup of $S_A$, Show that any abelian transitive subgroup of $S_n$ ...
Joshua Woo's user avatar
  • 1,069
-1 votes
1 answer
70 views

Basis of tensor product over non-commutative ring. [closed]

Let $M$ and $N$ be $R$-modules, where $R$ is a ring, and let $M\otimes_R N$ be the tensor product over $R$. If $R$ is commutative, then the basis of $M\otimes_R N$ is the set $$ \{ m\otimes_R n :m\in ...
Logi's user avatar
  • 833
1 vote
0 answers
54 views

A "simpler" description of the automorphism group of the Lamplighter group

The lamplighter group is defined by the following presentation: $$ L_N=(\mathbb{Z} _N) \wr \mathbb{Z} \cong\left\langle t, a_n, n \in \mathbb{Z} \mid a_n^N, t a_n t^{-1}=a_{n+1}, n \in \mathbb{Z}, a_n ...
ghc1997's user avatar
  • 1,163
1 vote
0 answers
80 views

What is ${\rm Aut}\bigoplus_{i=-\infty}^{\infty}\mathbb{Z}_p$?

Let $p$ be a prime, what is the automorphism group of $G=\bigoplus_{i=-\infty}^{\infty}\mathbb{Z}_p$ (countable infinite direct sum of $\mathbb{Z}_p$)? I know every permutation of the coordinates will ...
ghc1997's user avatar
  • 1,163
0 votes
0 answers
29 views

$\prod_p \mathbb{Z}/p\mathbb{Z}$ is not the direct sum of $\bigoplus_p \mathbb{Z}/p\mathbb{Z}$ and a torsion-free subgroup

While I was reading "Abelian Groups" by Fuchs $(2015)$, I encountered Example $1.2$ in the chapter on Mixed Groups, which stated the following: Let $p_1,p_2,\dots,p_n,\dots$ denote different ...
John123's user avatar
  • 69
0 votes
0 answers
38 views

Comparing spectral sequences with different coefficients

Several spectral sequences coming from geometry have a "degree of freedom" in choosing the coefficients (say an abelian group $A$). This applies fo example to the Serre spectral sequence and ...
Andrea Marino's user avatar
5 votes
1 answer
214 views

Real Elliptic curves as compact abelian groups

It's well known that an elliptic curve of the form $y^3 = x^3 +ax +b$ admits a group structure, as long as a point at infinity $O$ is added to serve as identity. If we look at a real elliptic curve as ...
Pedro Lourenço's user avatar
3 votes
0 answers
54 views

$\underset{p\in \mathbb{P}}{\prod}\mathbb{Z}/p\mathbb{Z}$ is non splitting mixed abelian group.

We say that an abelian group $G$ is mixed if it has elements $ \neq 0$, that are of finite order (torsion elements), as well as elements of infinite order (torsion-free elements). We denote the ...
John123's user avatar
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