Questions tagged [a.m.-g.m.-inequality]

For questions about proving and manipulating the AM-GM inequality. To be used necessarily with the [inequality] tag.

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if a,b,c>0 and $abc=1$ prove that $\frac{a}{b}+\frac{b}{c}+\frac{c}{a}\geq a+b+c$ [duplicate]

problem: a,b,c>0 and $abc=1$ prove that $\frac{a}{b}+\frac{b}{c}+\frac{c}{a}\geq a+b+c$ my attempt: $LHS=\frac{a}{b}+\frac{b}{c}+\frac{c}{a}=(a+b+c) \frac{\frac{a}{b}+\frac{b}{c}+\frac{c}{a}}{a+b+...
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5 votes
1 answer
738 views

Weighted AM-GM Inequality

I was tried to learn some tools on inequalities, and I learn the "Weighted AM-GM Inequality" in a small book: in this book there is an exercise and a solution, I did my attempt and it was ...
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0 votes
2 answers
82 views

prove that :$(1+\frac{1}{n})^k<1+\frac{k}{n}+\frac{k^2}{2n^2}$.

if $ n,k \in \mathbb{N^*}$ and $(k-1)^2<n$ prove that :$(1+\frac{1}{n})^k<1+\frac{k}{n}+\frac{k^2}{2n^2}$. my attempt: $(1+\frac{1}{n})^k+1=(1+\frac{1}{n}).(1+\frac{1}{n})^{k-1}+1\leq \sqrt{(1+\...
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0 votes
2 answers
94 views

Let $f:\mathbb R^+\to\mathbb R$ be a continuous function satisfied $f(a)+f(b)\ge f(2\sqrt{ab})$ for all $a,b>0$ , is $f$ differentiable? [closed]

Let $f:\mathbb R^+\to\mathbb R$ be a continuous function satisfied $f(a)+f(b)\ge f(2\sqrt{ab})$ for all $a,b>0$ , is $f$ differentiable? Morever, if for all $a_1,a_2,\cdots,a_n>0$ there holds $$\...
0 votes
0 answers
79 views

Prove $ \frac{(c-a)^{2}}{6c} \le \frac{a+b+c}{3} - \frac{3}{ 1/a + 1/b+ 1/c}$

Given real numbers $c \ge b \ge a>0$, prove that $$ \frac{(c-a)^{2}}{6c} \le \frac{a+b+c}{3} - \frac{3}{ \frac{1}{a} + \frac{1}{b} + \frac{1}{c}}$$ *using well-known inequality Other solution ...
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1 vote
1 answer
74 views

An Application of Cauchy Schwarz - AM-GM in Discrete Probability Measures

Suppose $p_m \geq 0$ and $\sum_{m \in \mathbf{Z}} p_m =1 .$ That is $p$ is a probability measure on integers. Then how can I show (is it true) that $$ \sum_{m \in \mathbf{Z}} (p_m + p_{m+1} + p_{m+2})^...
2 votes
0 answers
59 views

Finding a limit using AM-GM?

Doing some calculus papers before going university and I found this question: Find $\lim_{x\to\infty} \left[\frac{1}{3} \left(3^\frac{1}{x} + 8^\frac{1}{x} + 9^\frac{1}{x} \right)\right]^x$ My ...
1 vote
1 answer
126 views

Find number of continuous functions satisfying the equation $4\int_{0}^{\frac{3}{2}}f(x)dx+125\int_{0}^{\frac{3}{2}}\frac{dx}{\sqrt{f(x)+x^2}}=108$

The number of continuous functions $f:\left[0,\frac{3}{2}\right]\rightarrow (0,\infty)$ satisfying the equation$$4\int_{0}^{\frac{3}{2}}f(x)dx+125\int_{0}^{\frac{3}{2}}\frac{dx}{\sqrt{f(x)+x^2}}=108$$ ...
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2 votes
1 answer
242 views

Let $x,y,z\in[0,1]$. Find the maximum value of $\sqrt{|x-y|}+\sqrt{|y-z|}+\sqrt{|z-x|}$. [duplicate]

Let $x,y,z\in[0,1]$. Then find the maximum value of $\sqrt{|x-y|}+\sqrt{|y-z|}+\sqrt{|z-x|}$. Now the given answer is $2\sqrt{2}$ but I am not able to obtain the corresponding values of $x,y,z$. ...
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1 vote
0 answers
40 views

How can i find minimum value of this inequality

$a_1,a_2,...,a_n$ are 8 distinct positive integers. $b_1,b_2,...,b_n$ are another 8 distinct positive integers ($a_i,b_j$ are not necessarily y distinct for $i, j = 1, 2, ...8$).Enter the smallest ...
2 votes
1 answer
68 views

Let m be the smallest number among: $(x-y)^2, (y-z)^2, (z-x)^2$ Prove $m \le \frac{1}{2}(x^2+y^2+z^2)$

Let m be the smallest number among: $(x-y)^2, (y-z)^2, (z-x)^2$ Prove $m \le \frac{1}{2}(x^2+y^2+z^2)$ My attempts: $3m \le (x-y)^2+(y-z)^2+(z-x)^2$ so I tried to prove $(x-y)^2+(y-z)^2+(z-x)^2 \le \...
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5 votes
3 answers
103 views

A conditional negative definite quadratic form involving $\ln$ function

Let us consider the following property which is a constrained version of $(\star)$ (see Remark below): $$\begin{align*}\bbox[#EFF,15px,border:2px solid blue] {\begin{aligned}\text{For any n, for any} \...
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2 votes
0 answers
92 views

Find bounds of $\prod_{i=1}^k (x_i-x_{i+1})$ where $\sum_{i=1}^k x^2_i=1$

Let $x_1,x_2,...,x_k$ be real numbers such that $\sum_{i=1}^k x^2_i=1$. Determine the minimum and maximum (if there is) value of $$\prod_{i=1}^k (x_i-x_{i+1})$$ and determine all values of $(x_1,x_2,...
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2 votes
1 answer
94 views

Prove that for positive reals $x,y,z$, $x^6+y^6+z^6 + 6x^2y^2z^2 \geq 3xyz(x^3+y^3+z^3)$.

I am not sure if the inequality is true. My first attempt was to try AM-GM inequality in clever ways. I also tried Schur's inequality which gives $$ x^6+y^6+z^6 + 6x^2y^2z^2 \geq (x^2+y^2+z^2)(x^2y^2+...
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1 vote
1 answer
87 views

Prove that $(1+x)^k/k + (1-x)^m/m\geq 1/k +1/m$ without calculus

Note: this has been edited to make the question more general. I want to show that $(1+x)^k/k + (1-x)^m/m$ is minimized at $x=0$ when $k,m\geq 1$ and $-1\leq x \leq1$. Of course, I could take the first ...
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2 votes
1 answer
88 views

How can I prove that the perimeter is at most 60?

Problem: Let $\Delta$ be a triangle in the plane. Let $P$ be the perimeter of the triangle and $A$ be the area. Let $a,b,c$ be the length of the sides and suppose they are positive integers. Suppose ...
0 votes
0 answers
20 views

Inequality of positive integers [duplicate]

I have to prove the following inequalities for positive integer $n$: $$n^n\geqslant\left(\frac{n+1}2\right)^{n+1}$$ $$ 2^ {n(n+1)}> (n+1)^{n+1} \left(\frac{n}{1}\right)^{n} \left(\frac{n-1}{2}\...
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2 votes
3 answers
118 views

find the maximum of $x+\frac{1}{2y}$ under the condition $(2xy-1)^2=(5y+2)(y-2)$

Assume $x,y \in \mathbb{R}^+$ and satisfy $$\left(2xy-1\right)^2 = (5y+2)(y-2)$$, find the maximum of the expression $x+\frac{1}{2y}$. $\because (5y+2)(y-2) \geq 0$ , $\therefore y\geq 2$ or $y \leq -\...
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1 vote
1 answer
58 views

To prove the inequality of positive rational numbers

Show that: $$ \left(\frac{a+b}{a+b+c}\right)^{c} \left(\frac{b+c}{a+b+c}\right)^{a} \left(\frac{a+c}{a+b+c}\right)^{b}< \left(\frac{2}{3}\right)^{a+b+c} ,a\ne b\ne c$$ PS: I am supposed to use ...
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2 votes
1 answer
66 views

Is there a solution for $(\frac{3}{x+y+z})^n+(\frac{3}{x+y+z})^{5-n}<2$?

Is there a solution for $$\left(\frac{3}{x+y+z}\right)^n+\left(\frac{3}{x+y+z}\right)^{5-n}<2$$ where $n\in\mathbb Z$ and $x,y,z>0, xyz=1$. This is the part of my attempts for my homework, that ...
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0 votes
1 answer
86 views

How would I prove the following using the AGM inequality?

Question 17. Let $x,y\in\mathbb R$, $x,y\geq0$. Prove that $$(\sqrt x+\sqrt y)^2\geq2\sqrt{2(x+y)\sqrt{xy}}.$$ I believe I have to use AGM multiple times, but I am not exactly sure how
2 votes
1 answer
77 views

Proving $\frac{x^2+y^2+z^2}{x+y+z}+\frac 32\sqrt[3]\frac{xy+yz+xz}{x+y+z}\geq \frac 52$, for positive values with $xyz=1$, without expansion?

Let, $x,y,z>0$ and $xyz=1$, then prove that $$\frac{x^2+y^2+z^2}{x+y+z}+\frac 32\sqrt[3]\frac{xy+yz+xz}{x+y+z}\geq \frac 52$$ I know that $$x^2+y^2+z^2\geq x+y+z$$ by Cauchy-Schwarz. So, $$\frac{x^...
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5 votes
2 answers
139 views

How can I prove that, if $x,y,z>0$ and $xyz=1$, then $2(x^2+y^2+z^2)+9\geq 5(x+y+z)$

How can I prove that, if $x,y,z>0$ and $xyz=1$, then $$2(x^2+y^2+z^2)+9\geq 5(x+y+z)$$ I used the famous inequality $$x^2+y^2+z^2+3\geq 2(x+y+z)$$ I got $$2(x^2+y^2+z^2)+9\geq 4(x+y+z)+3\geq 5(x+y+...
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0 votes
0 answers
12 views

To prove the relation between n numbers and their AM - GM [duplicate]

Given $A$ and $G$ to be the arithmetic and geometric mean of n positive real numbers $a_1, a_2,...,a_n$ then for any $k > 0$ show that $$ (k+A)^n \ge\ (k+a_1)...(k+a_n) \ge\ (k+G)^n .$$ I started ...
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0 votes
2 answers
99 views

To prove the following inequalities of positive rational numbers

I have to prove the following inequalities: $$ a^ab^bc^c \ge \ (\frac{a+b}{2})^{\frac{a+b}{2}} (\frac{c+b}{2})^{\frac{c+b}{2}} (\frac{a+c}{2})^{\frac{a+c}{2}} $$ $$(a+b)^{c}(c+b)^{a}(a+c)^{b} < \...
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0 votes
1 answer
48 views

To prove the following inequality of real numbers

If $a_1,...a_n$ are all positive real numbers then prove that $$\left(\frac{a_1 + a_2 + \dots + a_n}{n}\right)^n \ge a_1a_2\left(\frac{a_3 + a_4 + \dots + a_n}{n-2}\right)^{n-2}.$$ I approached the ...
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3 votes
2 answers
104 views

To prove the given inequality of n numbers

Given $ a_1 + a_2 + ... + a_n = S$ where $a_1,...,a_n$ are positive reals and all $a_i$s are not equal, then show that $$ \prod_{i=1}^n\dfrac{S-a_i}{n-1} > a_1.a_2...a_n$$ I began by considering ...
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0 votes
1 answer
29 views

Prove the A.M.-G.M. inequality for n terms using induction

You are required to give a detailed proof of the A.M.-G.M. inequality using induction. I have one answer and I am posting it but it is too brutish. I want a more elegant method of proving A.M.-G.M. ...
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0 votes
1 answer
171 views

Proving the AM-GM Inequality by induction [closed]

I am required to prove the AM-GM inequality using induction but via this route: (i) Let $a_1$, $a_2$, ..., an be a sequence of positive numbers. Denote their sum by $s$ and their geometric mean by $G$....
0 votes
1 answer
51 views

question based on AM/GM [closed]

If $a, b, c$ are positive real numbers and \begin{align*} a^{2}(1 + b^{2})+ b^{2}(1 + c^{2}) + c^{2}(1 + a^{2}) = 6abc \end{align*} Find $a + b + c$.
0 votes
1 answer
68 views

Solve the inequality $ \sum_{cyc}\frac{a-bc}{a+bc} \le \frac32$

Solve the inequality $ \displaystyle\sum_{cyc}\frac{a-bc}{a+bc} \le \frac32$ given $a + b + c = 1$ and $a, b, c \in \mathbb{R_{>0}}$ So, I wanted to use the known inequality $9(a+b)(b+c)(c+a) \ge ...
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4 votes
2 answers
105 views

Prove the inequality $9(a+b)(b+c)(c+a) \geq 8(a+b+c)(ab+bc+ca)$

Prove the inequality $9(a+b)(b+c)(c+a) \geq 8(a+b+c)(ab+bc+ca)$ for $a, b, c \in \mathbb{R_{>0}}$ I tried by first using AM-HM inequality on $a, b, c$ to get the following result. $\frac{a+b+c}3 \...
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1 vote
1 answer
76 views

Prove $\sum_{j=1}^{n^2} \log_n(2j-1)\leq2n^2 $

Deduce whether the statement is true or false. Suppose $n\in \mathbb N \setminus \{0,1\}$. Then, $$\sum_{j=1}^{n^2} \log_n(2j-1)\leq2n^2 $$ I would like to ask what inequality I can apply or any ...
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3 votes
2 answers
133 views

Showing $\frac{xy+yz+xz}{x+y+z}>5-\sqrt{4(x^2+y^2+z^2)+6}$ for $x,y,z>0$ and $xyz=1$

Let $x,y,z>0$ with $ xyz=1$ then prove that, $$\frac{xy+yz+xz}{x+y+z}>5-\sqrt{4(x^2+y^2+z^2)+6}$$ Let $$5≤\sqrt{4(x^2+y^2+z^2)+6}\implies x^2+y^2+z^2≥\frac {25-6}{4}=\frac {19}{4}$$ then the ...
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2 votes
3 answers
94 views

Prove that $(xy+yz+xz)(x^2+y^2+z^2+x+y+z)≥2(x+y+z)^2$

Let, $x,y,z>0$ such that $xyz=1$, then prove that $$(xy+yz+xz)(x^2+y^2+z^2+x+y+z)≥2(x+y+z)^2$$ My progress: Using the Cauchy-Schwars inequality I got $$(xy+yz+xz)(x^2+y^2+z^2+x+y+z)≥2(xy+yz+xz)(x+...
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1 vote
2 answers
114 views

Is this nice-looking inequality actually trivial?

Let, $x,y,z>0$ such that $ xyz=1$, then prove that $$(xy+yz+xz)(x^2+y^2+z^2+xy+yz+xz)≥2(x+y+z)^2 $$ I tried to use the inequality $$x^2+y^2+z^2≥xy+yz+xz$$ Then I got, $$(xy+yz+xz)(x^2+y^2+z^2+xy+...
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2 votes
2 answers
65 views

Can we prove the inequality without opening the parentheses? $(x+y+z)(xy+yz+xz)(x^2+y^2+z^2)≥6(x^2+y^2+z^2)+3(xy+yz+xz)$

Let, $x,y,z>0$ such that $ xyz=1$, then prove that $$(x+y+z)(xy+yz+xz)(x^2+y^2+z^2)≥6(x^2+y^2+z^2)+3(xy+yz+xz)$$ I tried to use the following inequalities: $$x^2+y^2+z^2≥xy+yz+xz$$ and The Cauchy–...
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4 votes
2 answers
110 views

Find minimum of the function using AM-GM

Problem: Find the minimum of the function $f(x,y)=x + \frac{8}{y(x-y)}$, where $x>y>0$ using AM-GM. My attempt: $$f(x,y)=2\cdot \frac{x+\frac{8}{y(x-y)}}{2} \ge 2 \sqrt{\frac{8x}{y(x-y)}}$$ But ...
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0 votes
1 answer
40 views

Is the geometric mean bounded above by this value?

It is clear that the geometric mean is bounded above by the arithmetic mean: $$ \prod_{k=1}^{M} x_k^{\alpha_k} \leq \sum_{k=1}^{M}\alpha_k x_k $$ Moreover, it is clear that the arithmetic mean is ...
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-1 votes
2 answers
57 views

Alternate proofs of the inequality $\sum_{\text{cyclic}} \frac{x}{2x+y+z}\le \frac{3}{4}$.

If $x,y,z\in(0,\infty),$ prove the inequality, $$\sum_{\text{cyclic}} \frac{x}{2x+y+z}\le \frac{3}{4}$$ I have a solution using the substitution $x+y=a,$ $y+z=b$ and $z+x=c$. $$\frac{x}{2x+y+z}+\frac{...
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1 vote
1 answer
79 views

Prove $\left(\frac{a+b+c}{3}\right)^p\leq \frac{a^p+b^p+c^p}{3}$.

Prove: Let $p$ be an integer greater than $1$. Suppose $a,b,c$ be positive real numbers. Then $\left(\frac{a+b+c}{3}\right)^p\leq \frac{a^p+b^p+c^p}{3}$. By AM-GM, I get $\frac{a+b+c}{3}\geq (abc)^{1/...
  • 133
1 vote
1 answer
167 views

Prove that for $a,b,c \in \mathbb{R}^+$ with $abc = 1$, $\frac{1}{a^3(b + c)} + \frac{1}{b^3(a + c)} + \frac{1}{c^3(a + b)} \ge \frac{3}{2}$ [duplicate]

I would like confirmation that I did this proof correctly. If I did, it would be a milestone in my mathematical journey as it would be my first IMO problem. By Cauchy, we have that $$\left( \frac{1}{a^...
1 vote
3 answers
142 views

What is the minimum value of $\frac{2a}{a+2b+2c} + \frac{2b}{b+2c+2a} +\frac{2c}{c+2a+2b}$ given $ a+b+c=2$?

What is the minimum value of $\frac{2a}{a+2b+2c} + \frac{2b}{b+2c+2a} +\frac{2c}{c+2a+2b}$ given $ a+b+c=2$? I know the answer is going to be $\frac{6}{5}$ because it will occur when there is equality ...
2 votes
0 answers
78 views

Prove that for all $a,b,c \in \mathbb{R}^+$, $\sqrt[3]{\frac ab} + \sqrt[5]{\frac bc} + \sqrt[7]{\frac ca} > \frac 52$

Prove that for all $a,b,c \in \mathbb{R}^+$, $\sqrt[3]{\dfrac ab} + \sqrt[5]{\dfrac bc} + \sqrt[7]{\dfrac ca} > \dfrac 52$. My thought process along with the proof: Since we're dealing with ...
-4 votes
3 answers
59 views

Proof based on inequalities [closed]

I want to find the minimum value of $$\frac{(5+x)(2+x)}{1+x}.$$ I brought it down to the fact that it depends on the value of $$(x^2 + x)\sqrt{7x+10}.$$ Also $x\geq -10/7$, but don't know what to do ...
1 vote
0 answers
76 views

Maximizing $\dfrac{4 \sqrt{a} + 6 \sqrt{b} + 12 \sqrt{c}}{\sqrt{abc}}$ over $a+b+c=4abc$ and $a,b,c>0$

Let $a,$ $b,$ $c$ be positive real numbers such that $a + b + c = 4abc.$ Find the maximum value of $$\dfrac{4 \sqrt{a} + 6 \sqrt{b} + 12 \sqrt{c}}{\sqrt{abc}}.$$ First, I tried using $\dfrac{4 \sqrt{...
1 vote
1 answer
52 views

Maximize $\lambda$ over $a^2 + b^2 + c^2 + d^2 \ge ab + \lambda bc + cd$ and $a,b,c,d\geq 0$.

Find the largest real number $\lambda$ such that $$a^2 + b^2 + c^2 + d^2 \ge ab + \lambda bc + cd$$ for all nonnegative real numbers $a,$ $b,$ $c,$ $d.$ I tried using AM-GM on like $a^2+\dfrac{b^2}{4}...
1 vote
1 answer
71 views

Hard AM-GM Inequality

Find the sum of all positive integers $n,$ where the inequality $\sqrt{a + \sqrt{b + \sqrt{c}}} \ge \sqrt[n]{abc}$ holds for all nonnegative real numbers $a,$ $b,$ and $c.$ I tried squaring both sides ...
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-2 votes
1 answer
44 views

question about AM-GM inequality ab<(a^2+b^2)/2 [closed]

I have a question about the AM-GM inequality if a,b>0 then ab≤(a+b)^2/4; ab≤a^2+b^2; I wonder if these 2 inequality are true for all a,b>0, if not which one is correct?
0 votes
0 answers
71 views

Proof that $\frac{x}{\sqrt y}+\frac{y}{\sqrt z}+\frac{z}{\sqrt x} \geq 3$ for $x+y+z=3$ [duplicate]

If $x+y+z=3$, where $x$, $y$ and $z$ are sides of a triangle, prove that $$\frac{x}{\sqrt y}+\frac{y}{\sqrt z}+\frac{z}{\sqrt x} \geq 3$$ We have $0< x,y,z<\frac{3}{2}$ from the triangle ...
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