Linked Questions
11 questions linked to/from Integral solutions of hyperboloid $x^2+y^2-z^2=1$
1
vote
3answers
166 views
$p^2+1=q^2+r^2$. Strange phenomenon of primes
Problem:
Find prime solutions to the equation
$p^2+1=q^2+r^2$
I welcome you to post your own solutions as well
I have found a strange solution which I can't understand why it works(or what's the ...
9
votes
4answers
1k views
Showing that $m^2-n^2+1$ is a square
Prove that if $m,n$ are odd integers such that $m^2-n^2+1$ divides $n^2-1$ then $m^2-n^2+1$ is a square number.
I know that a solution can be obtained from Vieta jumping, but it seems very different ...
0
votes
0answers
188 views
Positive even numbered integer solutions of $y=n^2-m^2-x^2$
Prove that no integer $x$ exists where $y=n^2-m^2-x^2$ has solutions:
For all even integer values of $y$ in the range $2\le y \le 2x+1$ where $x$ is odd.
For all odd integer values of $y$ in the ...
0
votes
0answers
85 views
Number of integer points on a rotational hyperboloid of two sheets.
There are many integer points on the hyperboloid of two sheets
$x^2+y^2-z^2=-1$.
(0,0,1), (2,2,3), (4,8,9),...
Let us denote such set as H.
I will consider only the upper sheet $z>0$, but ...
5
votes
4answers
6k views
Solutions to $ax^2 + by^2 = cz^2$
The integer solutions to the equation $x^2 + y^2 = z^2$ are very well studied. I'm wondering if there's any literature about the integer solutions to the equation $ax^2 + by^2 = cz^2$ where a,b,c are ...
4
votes
3answers
141 views
$x^2+y^2=z(4z+1)$ solutions
For a small project I am working on, I wish to find the solutions for
$$x^2+y^2=z(4z+1)$$
in natural numbers $x,y,z$.
I wish to automate finding solutions for $z$ up to a maximum value as efficient as ...
1
vote
2answers
6k views
Solution of Diophantine equation
Find all integral solutions of $x^2+1= y^2+z^2$. Actually I have to find all integral solution of $a(a+1)=b(b+1)+c(c+1)$. I reduced this in the above form I.e., $ (2a+1)^2+1= (2b+1)^2+(2c+1)^2$ .
0
votes
3answers
157 views
Solving $x^2 + y^2 = 1 + z^4$ with (x,y,z) = 1 and z < x < y
I have a computer programming problem where I need to find n many sets of integers that meet the condition $x^2 + y^2 = 1 + z^4$ with (x,y,z) = 1 and z < x < y
I can do this relatively easily ...
0
votes
2answers
249 views
The diophantine equation $z^2=a^2+bx^2+cy^2$
Is there a way to obtain (enumerate) the integer solutions $(x,y,z)$ of the following quadratic Diophantine equation
$z^2=a^2+bx^2+cy^2$
where $a$ is an integer and $b, c$ are positive integers?
I ...
1
vote
0answers
56 views
How can I obtain a solution for the equation $a^2 + b^2 = c^2 + 1$? [duplicate]
For the equation $a^2 + b^2 = c^2$, the solution is:
$a = m^2 - n^2, b= 2mn, c = m^2 + n^2$
$m,n\in\mathbb{Z}$ and $m > n$, free to choose
How is a similar solution obtained for the equation $a^2 ...
17
votes
5answers
2k views
Integral solutions of $x^2+y^2+1=z^2$
I am interested in integral solutions of $$x^2+y^2+1=z^2.$$ Is there a complete theory comparable to the one for $x^2+y^2=z^2?$