Linked Questions

I have been taught that $\frac{1}{3}$ is 0.333.... However, I believe that this is not true, as 1/3 cannot actually be represented in base ten; even if you had ...

Just out of curiosity, since $$\sum_{i>0}\frac{9\times10^{i-1}}{10^i}, \quad\text{ or }\quad 0.999\ldots=1,$$ Does that mean $0.999\ldots=1$, or in other words, that $0.999\ldots$ is an integer, ...

Ok use your closest calculator, and type $\frac{4}{3}$, which is $1.3333333333$,and then multiply it with $3$ which is $3.9999999999$ but then type $\frac{4}{3} \times 3=4$ how?. How can it be $4$ if $...

Possible Duplicate: Does .99999… = 1? I was thinking about this the other day... if 10/3 = 3.33333... (series) why doesn't ...

I was wondering is there any way to express $0.999999$ recurring as an actual fraction without equaling $1$? Because I tried to convert it into a fraction following the rules for normal recurring ...

Possible Duplicate: Does .99999… = 1? I have to explain $0.999\ldots=1$ to people who don't know limit. How can I explain $0.999\ldots=1$? The common procedure is as follows \begin{align} x&...

Let's start considering a simple fractions like $\dfrac {1}{2}$ and $\dfrac {1}{3}$. If I choose to represent those fraction using decimal representation, I get, respectively, $0.5$ and $0.3333\...

I'm noob in math. If 0.333(3) is 1/3, 0.666(6) is 2/3, then 0.999(9) is what? If 3/3 and 0.999(9) is the same, then how can I express one of them without expressing the other?

Possible Duplicate: Does .99999… = 1? After reading all the kind answers for this previous question question of mine, I wonder... How do we get a fraction whose decimal expansion is the ...

I'm a student of 10th std. Recently our teacher asked a Question that "Is 4.999...equal to 5 or not?" Everyone said that is isn't equal or it is approximately equal. Teacher too agreed to that. But ...

If x = 0.999... (a) -> 10x=9.999... -> 10x-x=(9.999...)-(0.999...) -> 9x = 9 -> x = 9/9 = 1 (b) x = 0.999 (a) = 1 (b) ? So... what is the right explanation for this occur? I know that exists a ...

I am finding hard to understand why $0,99999..... = 1$ I have the following proof: Let $x$ be $0,9999...$ then $10x = 9,999...$ So $10x - x = 9,999 - 0,9999$ $9x = 9 \rightarrow x = 1$ From a ...

Recently I stumbled across a, to me, rather strange idea. I was messing around with the proof of $0.999... = 1$, when I figured that what $0.999...$ means is that those are all nines. That way I came ...

Possible Duplicate: Does .99999… = 1? I'm only doing this at GSCE and I'm really only asking here because of an interesting email conversation between my Grandfather and I regarding the ...

Is it possible to express $0.999...$, a repeating number, as a fraction? Or as a ratio of two numbers? Basically all (my) attempts at the problem cancels all the terms and returns $1$. Is it even ...