12 questions linked to/from Prove the map has a fixed point
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### Fixed point of continuous function on compact metric space [duplicate]

Possible Duplicate: Prove the map has a fixed point Let $X$ be a compact metric space and $f:X\rightarrow X$ be a continuous function such that $d(f(x),f(y))<d(x,y)$ for every $x,y\in X$ such ...
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### Existence of unique fixed point in compact Metric space [duplicate]

Let $(X,d)$ be compact. Show: for a map $f$ that when $\forall x, y \in X$ with $x\neq y$ $d(f(x),f(y))<d(x,y)$ is fulfilled. Then $f$ has a unique fixed point.
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### Fixed Point Problem. [duplicate]

Suppose $(X,d)$ is compact and we have a mapping $T:X \rightarrow X$ such that $d(Tx,Ty)<d(x,y)$ for every $x,y\in X$ with $x\neq y$. The question is that to show $T$ has a unique fixed point. ...
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### How to show there exist a unique $x_o$ in X such that f($x_o$)=$x_o$? [duplicate]

Let $(X, d)$ be a compact metric space. Let $f:X\rightarrow X$ be such that $d(f(x), f(y)) < d(x, y)$ for all $x, y\in X$ with $x$ not equal to $y$. Show that $f$ has a fixed point, that is, there ...
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### A subset of a compact set is compact?

Claim:Let $S\subset T\subset X$ where $X$ is a metric space. If $T$ is compact in $X$ then $S$ is also compact in $X$. Proof:Given that $T$ is compact in $X$ then any open cover of T, there is a ...
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### Prove there is no contraction mapping from compact metric space onto itself

This question is from Foundations of mathematical analysis by Richard Johnsonbaugh The thing with this question is that there is a question that seems to prove the opposite claim Prove the map has a ...
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### How can I prove $x_{n+1} = e^{-x_n}$ is convergent?

I'm doing a practice problem which asks to prove that the sequence defined by $x_{n+1} = e^{-x_n}$ is convergent (or rather "study the convergence of $(x_n)$"). So I'd like to try and find some ...
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### Infimum of Distance in Compact Space

If $X$ is a compact metric space, $A: X\to X$, is it true that if $a = \inf d(x,Ax),\space x \in X$, then there exists $y \in X$ such that $d(y,Ay) = \inf d(x,Ax)$? If so, why?
### If $X$ is a compact space and $A:X\rightarrow X$ is such that $\rho(Ax,Ay)<\rho(x,y)$, $x\neq y, \Rightarrow A$ have only one fix point on X.
I have problems with this demostration can anybody help me please? If $X$ is a compact space and $A:X\rightarrow X$ is such that $\rho(Ax,Ay)<\rho(x,y)$, $x\neq y, \Rightarrow A$ have only one ...