How many ways to make a $3$ digits even number with only $2,3,5,6,7$ . And no repeated use of digit.
I think I did something like for the first digit you have $5$ choices, for second digit $4$ choices, last digit will only have $2$ choices, because, we need it to be even, so $40$ in total. Out of these $40$ choices, $2$ of them are not possible to obtain: $26x$ or $62x$. I think I'm still getting the wrong answer.