If group $G$ is isomorphic to group $H$, show that if $G$ is cyclic then so is $H$.
An isomorphism is simply a bijective homomorphism. The latter is a function which preserves the group operation. $f(g_1*g_2)= f(g_1) \cdot f(g_2)$, $g_1, g_2 \in G$
A cyclic group is a group generated by one element. I'm not sure how to connect these though