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After successive discounts of 25%, 20%, 37.5% and 33(1/3)% are applied to the original price of an item, the final price of that item is the same as if the original price had been discounted once by n%. Compute n. Is the answer 66.625. If not, please teach me how to approach to the right answer!! Thank you very much!!!

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  • $\begingroup$ This is easier if you calculate the reduced prices (instead of just the discounts), and then translate the final answer to a discount at the end. $\endgroup$ – John Joy Oct 26 '14 at 20:29
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Lets call the original amount $A$. Then, after the first discount the price would become:$$A\times(1-0.25)=a\times0.75$$The second discount should now be applied to this new amount so after the second discount the price would become:$$A\times0.75\times(1-0.2)=A\times0.75\times0.8=A\times0.6$$This means that the first two discounts are equivalent to $(1-0.6)=0.4=40$%. Keep applying this rule until you end up with something like:$$A\times r$$The equivalent discount is then $(1-r)\times100$%

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  • $\begingroup$ I still get 66.625 by ur way. $\endgroup$ – Annie Oct 27 '14 at 0:05
  • $\begingroup$ is it right?I might did st wrong throughout. $\endgroup$ – Annie Oct 27 '14 at 0:06
  • $\begingroup$ No it is not correct - please show your full working so that I can spot where you may have made a mistake $\endgroup$ – Mufasa Oct 27 '14 at 21:07

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