A fair die is tossed twice. About how many times would you expect to roll 3 or greater?
So based on sequence of Bernoulli trials:
P(exactly k successes in n trials) = C(n,k) p^k q^(n-k) where p = probability of success, and q = probability of failure
So in this case, p = 2/3, and q = 1/3
P = C(2,0) p^0 q^2 + C(2,1) p^1 q^1 + C(2,2) p^2 q^0 = 1,
While on the other hand, P is absolutely greater than 1, by common sense. So any ideas? Maybe I mess up with some definitions though.