# Finding the square roots of a complex number.

Express $z=4\sqrt2(1+i)$ in modulus/argument form. Hence find the two square roots of $z$ and mark their representations on an Argand Diagram.

So far I've worked out the mod/arg form of the complex number which is just

$$z = 8(\cos\frac{\pi}{4} + i\sin\frac{\pi}{4}) \\$$

Then used $\alpha = \frac{\theta +360k}{n}$ where $k$ is $0,1,2,...,n-1$ and got two results for the argument. The first being $\frac{-7\pi}{8}$ and the other being $\frac{\pi}{8}$.

$$z_1 = 2\sqrt2(\cos\frac{-7\pi}{8} + i\sin\frac{-7\pi}{8}) \\ z_2 = 2\sqrt2(\cos\frac{\pi}{8} + i\sin\frac{\pi}{8})$$

For some reason, the answers from the book were

$$z_1 = 2\sqrt2(\cos\frac{\pi}{8} + i\sin\frac{\pi}{8}) \\ z_2 = -2\sqrt2(\cos\frac{\pi}{8} + i\sin\frac{\pi}{8})$$

What was it that I did wrong in my calculations? Thanks in advance!

$$2\sqrt 2 (\cos\frac{-7\pi}{8} + i\sin\frac{-7\pi}{8}) = -2 \sqrt 2 (\cos\frac{\pi}{8} + i\sin\frac{\pi}{8})$$
Moreover, $-2\sqrt 2 (\cos\frac{\pi}{8} + i\sin\frac{\pi}{8})$ looks better.