# Question on Showing the dimensions of a Vector Space

For the first part I put the matrix into echleon form :

$$\begin{pmatrix}1&-1&2&3\\0&1&0&1\\0&0&0&0\\0&0&0&0\end{pmatrix}$$

And then:

$r(A)=2\implies \dim(A)=4-2=2$

^^ Is my presentation correct?

• For the second part: If $M:\mathbb{R}^4 \to \mathbb{R}^4$ is non-singular, what does this imply about the kernel of $M$ and thus the range of $M$? – Krijn Oct 20 '14 at 10:59
• If $M$ is non-singular, how do the dimensions of the domain of $M$ and the range of $M$ relate? – Ruvi Lecamwasam Oct 20 '14 at 11:00
• The domain of $M$ is the space that $M$ acts on, i.e the domain of $A$ above is $\mathbb{R}^4$. If $\{v_i\}$ in the domain of $M$ are linearly independent, what do you know about $\{Mv_i\}$? (consider applying $M^{-1}$ to $\sum_n Mc_nv_n$ for $c_n$ arbitrary constants.) – Ruvi Lecamwasam Oct 20 '14 at 11:03