Here's the equation I'm working with: y''+y'-2y = 3e^(x)+4x
I want to use the method of undetermined coefficients for this equation. The logical choice for our guess would be y = Ae^(x)+Bx+C.
After substituting in, we end up getting Ae^(x) + Ae^(x)+B - 2(Ae^(x)+Bx+C) = 3e^(x)+4x.
While we get a value for B, -2, it doesn't quite work out for A and C. Thoughts?